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1.(4x-1)2=25*9=225=152
=>4x-1=15
=>4x=15+1=16
=>x=4.
2. 32x+2=9x+3
=>32x+2=(32)x+3
=>32x+2=32x+6
=>2x+2=2x+6.
=> 2 = 6 ( vô lí )
Vậy x không thỏa mãn điều kiền trên.
3. (x-5)4=(x-5)6
=>x-5=0 hoặc x-5=1 hoặc x-5=-1
=>x=5 hoặc x=6 hoặc x=4.
4.x15=x2
=>x=1 hoặc x=0
1.(3x-1/4)^2=36
(3x-1/4)^2=6^2
3x-1/4 =6
3x =6+1/4
3x = 25/4
x =25/4:3
x =25/12
2.(1/4-2x)^3=8
(1/4-2x)^3=2^3
1/4-2x =2
2x =1/4-2
2x =-7/4
x =-7/8
3.(5-7/2x)^2=25
(5-7/2x)^2=5^2
5-7/2x =5
7/2x =0
x =0
4.x+(1/4)^2=25
x+1/16 =25
x =25-1/16
x =399/16
7.(2/5x-3/4)^2=1/9
(2/5x-3/4)^2=(1/3)^2
2/5x-3/4 =1/3
2/5x =1/3+3/4
2/5x =13/12
x =13/12:2/5
x =65/24
8.(3/7-x)^2=1/49
(3/7-x)^2=(1/7)^2
3/7-x =1/7
x =3/7-1/7
x =2/7
9.(2/3x+1/4)^3=125
(2/3x+1/4)^3=5^3
2/3x+1/4 =5
2/3x =5-1/4
2/3x =19/4
x =19/4:2/3
x =57/8
10.(-3/4x+1/4)^2=25/16
(-3/4x+1/4)^2=(5/4)^2
-3/4x+1/4 =5/4
-3/4x =5/4-1/4
-3/4x =1
x =1:-3/4
x =-4/3
11.2.(x+1/4)^2=1/4
2x^2+1/8 =1/4
2x^2 =1/4-1/8
2x^2 =1/8
x^2 =1/8:2
x^2 =1/16
x =1/4
(x-13)2 =36
(x-13)2=62
*x-13=6 *x-13=-6
x=6+13 x=-6+13
x=19 x=7
Vậy x=19 hoặc x=7
(x-3)3=(-27)
(x-3)3=(-3)3
x-3=-3
x=-3+3
x=0
Vậy x=0
(x+4)2-9=55
(x+4)2=55+9
(x+4)2=64
(x+4)2=82
*x+4=8 *x+4=-8
x=8-4 x=-8-4
x=4 x=-12
Vậy x=4 hoặc x=-12
(x-5)3=123
Vô lí vì 123 ko chuyển sang được mũ 3
Vậy \(x\in\varnothing\)
2) \(\left(x-13\right)^2=36\)
\(\Leftrightarrow\left(x-13\right)^2=6^2\)
\(\Leftrightarrow x-13=6\)
\(\Leftrightarrow x=19\)
Vậy x = 19
3) \(\left(x-3\right)^3=\left(-27\right)\)
\(\Leftrightarrow\left(x-3\right)^3=\left(-3\right)^3\)
\(\Leftrightarrow x-3=\left(-3\right)\)
\(\Leftrightarrow x=0\)
Vậy x = 0
4) \(\left(x+4\right)^2-9=55\)
\(\Leftrightarrow\left(x+4\right)^2=64\)
\(\Leftrightarrow\left(x+4\right)^2=8^2\)
\(\Leftrightarrow x+4=8\)
\(\Leftrightarrow x=4\)
Vậy x = 4
5) \(\left(x-5\right)^3=123\)
\(\Leftrightarrow x\in\left\{\varnothing\right\}\)
Vì 123 sẽ không thể chuyển thể thành mũ 3 đc
1,1/3+1/2:X= -4
1/2:X= -4-1/3
1/2:X= -13/3
X=1/2 : -13/3
X= -3/26
1. 1/3 + 1/2 : x = -4
=> 1/2 : x = -4 - 1/3
1/2 : x = -13/3
=> x = 1/2 : (-13/3)
x = -3/26
2. 3x - 30%.x = -5,4
3x - x = -18
2x = -18
=> x = -18 : 2
x = -9
Ý 1 là x= 4 ; y=8
Ý 2 là x= 3 và 1 ; y = 1 và 2
Ý 3 là x= 2 ; y = 4
a) \(\left(x-5\right)\left(x^2-9\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-5=0\\x^2-9=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=5\\x=\left\{\pm3\right\}\end{cases}}\)
Vậy........
b) \(x\left(x+3\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x+3=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=0\\x=-3\end{cases}}\)
Vậy......
a)\(5^{2x-3}-2\cdot5^2=5^2\cdot3\)
\(5^{2x-3}-2\cdot25=75\)
\(5^{2x-3}-50=75\)
\(5^{2x-3}=125\)
\(125=5^3\)
\(5^3=5^{\left(3+3\right):2}=5^3\Rightarrow x=3\)
Vậy \(x=3\)
b)\(\frac{2}{9}\cdot\left(5x+1\right):2-\frac{1}{18}=\frac{5}{36}\)
\(=\frac{2}{9}\cdot\left(5x+1\right):2=\frac{5}{36}+\frac{1}{18}\)
\(=\frac{2}{9}\cdot\left(5x+1\right)=\frac{7}{36}\cdot2\)
\(5x+1=\frac{7}{18}:\frac{2}{9}\)
\(x=\left(\frac{7}{4}-1\right):5=\frac{3}{20}\)
\(\Rightarrow x=\frac{3}{20}\)
a, \(5^{2x-3}-2.5^2=5^2.3\)
\(\Leftrightarrow5^{2x-3}-2.25=25.3\)
\(\Leftrightarrow5^{2x-3}-50=75\)
\(\Leftrightarrow5^{2x-3}=125\)
\(\Leftrightarrow5^{2x-3}=5^3\)
\(\Leftrightarrow2x-3=3\)
\(\Leftrightarrow2x=6\)
\(\Leftrightarrow x=3\)
b, \(\frac{2}{9}.\left(5x+1\right):2-\frac{1}{18}=\frac{5}{36}\)
\(\Leftrightarrow\frac{2}{9}.\left(5x+1\right):2=\frac{7}{36}\)
\(\Leftrightarrow\frac{2}{9}.\left(5x+1\right)=\frac{7}{36}.2\)
\(\Leftrightarrow\frac{2}{9}.\left(5x+1\right)=\frac{7}{18}\)
\(\Leftrightarrow5x+1=\frac{7}{18}:\frac{2}{9}\)
\(\Leftrightarrow5x+1=\frac{7}{18}.\frac{9}{2}\)
\(\Leftrightarrow5x+1=\frac{7}{4}\)
\(\Leftrightarrow5x=\frac{3}{4}\)
\(\Leftrightarrow x=\frac{3}{4}:5=\frac{3}{4}.\frac{1}{5}=\frac{3}{20}\)