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(11+99)+(22+88)+(33+77)+(44+66)+(55+55)=110+110+110+110+110=550
1=11 2=22 3=33 4=44 5=55 6=66 7=77 8=88 .... 11=1
như đề bài cho
\(\frac{55}{22}+\frac{44}{22}\)
\(=\frac{55+44}{22}\)
\(=\frac{99}{22}\)
~~~~~~~~~~~~~~~
\(\frac{7}{9}\cdot\frac{3}{5}=\frac{7\cdot3}{9\cdot5}=\frac{7\cdot1}{3\cdot5}=\frac{7}{15}\)
\(\frac{9}{22}\cdot55=\frac{9}{22}\cdot\frac{55}{1}=\frac{9\cdot55}{22\cdot1}=\frac{9\cdot5}{2\cdot1}=\frac{45}{2}\)
\(\frac{11}{17}:\frac{33}{34}=\frac{11}{17}\cdot\frac{34}{33}=\frac{11\cdot34}{17\cdot33}=\frac{1\cdot2}{1\cdot3}=\frac{2}{3}\)
\(\frac{9}{22}x55=\frac{9x55}{22}=\frac{495}{22}\frac{45}{2}\)
k mình nhé các bạn
12+54:3+7+30-10=45
55:(7-2)x10-22:3+34=45
12x5:3-4x5:2+10=50
(12+54=66:3=22+7=29+30=59-10=49 ;55:(7-2)=11x5=55-22=33:3=11+34=45 ;12x5=60:3=20-4=16x5=80:2=40+10=50.Vậy thôi)
12+54:3+7+30-10=45
55:(7-2)x10-22:3+34=45
12x5:3-4x5:2+10=50
\(\dfrac{13}{2}\)=\(\dfrac{65}{10}\)
\(\dfrac{4}{5}\)=\(\dfrac{8}{10}\)
\(\dfrac{22}{55}\)=\(\dfrac{4}{10}\)
5/9 x 12/25 = 4/15
12/11 : 36/ 55 = 5/3
9/55 x 22 = 18/5
144/7 : 36 = 4/7
55+55-22:3/4
=55+55-88/3
=110-88/3
=242/3