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5/11+5/12+5/13+5/14
=115/132+5/13+5/14
=2155/1716+5/14
=1.612970363
5/11+5/12+5/13+5/14
=115/132+5/13+5/14
=2155/1716+5/14
=1.612970363
a,\(\frac{31}{17}+\frac{5}{13}+\frac{8}{13}-\frac{14}{17}=\left(\frac{31}{17}-\frac{14}{17}\right)+\left(\frac{5}{13}+\frac{8}{13}\right)=1+1=2\) b,\(\frac{5}{7}.\frac{22}{11}+\frac{5}{7}.\frac{9}{11}+\frac{5}{7}=\frac{5}{7}.\left(\frac{22}{11}+\frac{9}{11}+1\right)=\frac{5}{7}.4=\frac{20}{7}\)
Câu 1: \(\frac{5}{7}\):x+\(\frac{2}{3}\)=1\(\frac{1}{3}\)
\(\frac{5}{7}\):x+\(\frac{2}{3}\)=\(\frac{4}{3}\)
\(\frac{5}{7}\):x=\(\frac{4}{3}\) - \(\frac{2}{3}\)
\(\frac{5}{7}\):x=\(\frac{2}{3}\)
x=\(\frac{5}{7}\):\(\frac{2}{3}\)
x=\(\frac{15}{14}\)
Câu 2:x*\(\frac{3}{7}\)-\(\frac{5}{14}\)=2\(\frac{1}{3}\)
x*\(\frac{3}{7}\)-\(\frac{5}{14}\)=\(\frac{7}{3}\)
x*\(\frac{3}{7}\)=\(\frac{7}{3}\)+\(\frac{5}{14}\)
x*\(\frac{3}{7}\)=\(\frac{113}{42}\)
x=\(\frac{113}{42}\):\(\frac{3}{7}\)
x=\(\frac{791}{126}\)
Câu 3: 3\(\frac{5}{7}\)-x*\(\frac{1}{3}\)=1\(\frac{13}{11}\)
\(\frac{26}{7}\)-x*\(\frac{1}{3}\)=\(\frac{24}{11}\)
x*\(\frac{1}{3}\)=\(\frac{26}{7}\)-\(\frac{24}{11}\)
x*\(\frac{1}{3}\)=\(\frac{118}{77}\)
x=\(\frac{118}{77}\):\(\frac{1}{3}\)
x=\(\frac{356}{77}\)
1+2+3+4+5+6+7+8+9+10+11+12+13+14=(1+14)+(2+13)+(3+12)+(4+11)+(5+10)+(6+9)+(7+8)
=15+15+15+15+15+15+15
=15*7=105
Đặt biểu thức trên là A
A=(1-3)+(2-4)+(5-7)+(6-8)+.....+(297-299)+(298-300)+301+302
A=301+302-(3-1)-(4-2)-(7-5)-(8-6)-......-(299-297)-(300-298)
------------------------------------------------------------------
có 150 số hạng
A=301+302-(2+2+2+2+..........+2)
------------------------------
50 số hạng
A=301+302-2x150=303
1+2+3+4+5+6+7+8+9+10+11+12+13+14
=(1+14)+(2+13)+(3+12)+(4+11)+(5+10)+(6+9)+(7+8)
= 15+15+15+15+15+15+15
=105
1+(2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17)x0,000001
=1+(2+(3+17x10)+10)x0,000001
=1+(2+200+10)x0,000001
=1+212x0,000001
=1+0,000212
=1,000212
1+2-3-4+5+6-...+301+302
đặt A=(1+2)+(5+6)+...+(301+302)=3+11+19+...+603
A=[(603-3):8+1]x(603+3)=75x606=45450
đặt B=-3-4-7-8-11-13-...-299-300
B=(-3-4)+(-7-8)+(-11-12)+..+(-299-300)
B=-(7+15+23+...+599)
B=-[(599-7):8+1]x(599+7)=45450
ta có:
1+2-3-4+5+6-7-8+...+301+302=A-B=45450-45450=0
sai đề