Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a ) \(x^2-12x+36=\left(x-6\right)^2\)
b ) \(x^2-7=\left(x-\sqrt{7}\right)\left(x+\sqrt{7}\right)\)
c ) \(1-27x^3=\left(1-3x\right)\left(1+3x+9x^2\right)\)
d ) \(\left(x-y\right)-4y^2\) ( Câu này bó tay )
e ) \(y^3+3y^2+3y+1=\left(y+1\right)^3\)
f ) \(x^2+14x+49=\left(x+7\right)^2\)
Wish you study well !!
d)5.(x-y)-y(x-y)
=(x-y)(5-y)
e) y.(x-z)+7(z-x)
=y.(x-z)-7(x-z)
=(x-z)(y-7)
\(a.10x\left(x-y\right)-6y\left(y-x\right)\\ =10x\left(x-y\right)+6y\left(x-y\right)\\ =\left(10x-6y\right)\left(x-y\right)\\ =2\left(5x-3y\right)\left(x-y\right)\)
\(b.14x^2y-21xy^2+28x^3y^2\\ =7xy\left(x-y+xy\right)\)
\(c.x^2-4+\left(x-2\right)^2\\ =\left(x-2\right)\left(x+2\right)+\left(x-2\right)^2\\ =\left(x-2\right)\left(x+2+x-2\right)\\ =2x\left(x-2\right)\)
\(d.\left(x+1\right)^2-25\\ =\left(x+1-5\right)\left(x+1+5\right)=\left(x-4\right)\left(x+6\right)\)
Bài làm :
\(\text{a)}9\left(x+y-1\right)^2-4\left(2x+3y+1\right)^2\)
\(=\left(3x+3y-3\right)^2-\left(4x+6y+2\right)^2\)
\(=\left(3x+3y-3-4x-6y-2\right)\left(3x+3y-3+4x+6y+2\right)\)
\(=\left(-x-3y-5\right)\left(7x+9y-1\right)\)
\(\text{b)}3x^4y^2+3x^3y^2+3xy^2+3y^2\)
\(=\left(3x^4y^2+3xy^2\right)+\left(3x^3y^2+3y^2\right)\)
\(=3xy^2\left(x^3+1\right)+3y^2\left(x^3+1\right)\)
\(=\left(3xy^2+3y^2\right)\left(x^3+1\right)\)
\(=3y^2\left(x+1\right)\left(x+1\right)\left(x^2-x+1\right)\)
\(=3y^2\left(x+1\right)^2\left(x^2-x+1\right)\)
\(\text{c)}\left(x+y\right)^3-1-3xy\left(x+y-1\right)\)
\(=\left(x+y-1\right)\left[\left(x+y\right)^2+x+y+1\right]-3xy\left(x+y-1\right)\)
\(=\left(x+y-1\right)\left(x^2+2xy+y^2+x+y+1-3xy\right)\)
\(=\left(x+y-1\right)\left(x^2+x+y^2+y+1-xy\right)\)
\(d ) x^3+3x^2+3x+1-27z^3\)
\(=\left(x+1\right)^3-\left(3z\right)^3\)
\(=\left(x+1-3z\right)\left(x^2+2x+1+3xz+3z+9z^2\right)\)
b: \(x^2-6x+xy-6y\)
\(=x\left(x-6\right)+y\left(x-6\right)\)
\(=\left(x-6\right)\left(x+y\right)\)
c: \(2x^2+2xy-x-y\)
\(=2x\left(x+y\right)-\left(x+y\right)\)
\(=\left(x+y\right)\left(2x-1\right)\)
e: \(x^3-3x^2+3x-1=\left(x-1\right)^3\)
1, \(3x^2y^2-6x^2y^3+9x^2y^2\)
\(\Leftrightarrow12x^2y^2-6x^2y^2\)
\(\Leftrightarrow3x^2y^2\left(4+2y\right)\)
5x^2y^3 - 25x^3y^4 + 10x^3y^3
\(\Leftrightarrow5x^2y^3\left(1-5xy+2x\right)\)
a) \(x^2-12x+36=\left(x-6\right)^2\)
b) \(x^2-7=\left(x-\sqrt{7}\right)\left(x+\sqrt{7}\right)\)
c) \(1-27x^3=\left(1-3x\right)\left(1+3x+9x^2\right)\)
d) mk chỉnh lại đề chút xíu nhé. đúng thì bn tham khảo:
\(\left(x-y\right)^2-4y^2=\left(x-y-2y\right)\left(x-y+2y\right)=\left(x-3y\right)\left(x+y\right)\)
e) \(y^3+3y^2+3y+1=\left(y+1\right)^3\)
f) \(x^2+14x+49=\left(x+7\right)^2\)