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\(2x+5.11^0=3^2\)
\(\Rightarrow2x+5.1=9\)
\(\Rightarrow2x+5=9\)
\(\Rightarrow2x=9-5\)
\(\Rightarrow2x=4\)
\(\Rightarrow x=4:2\)
\(\Rightarrow x=2\)
Vậy \(x=2\)
b) \(4\left(3x-13\right)=64:2^3\)
\(\Rightarrow4\left(3x-13\right)=64:8\)
\(\Rightarrow4\left(3x-13\right)=8\)
\(\Rightarrow3x-13=8:4\)
\(\Rightarrow3x-13=2\)
\(\Rightarrow3x=2+13\)
\(\Rightarrow3x=15\)
\(\Rightarrow x=15:3\)
\(\Rightarrow x=5\)
Vậy \(x=5\)
1. Ta có: 2x + 5.11^0 = 3^2
=> 2x + 5.1 = 9
=> 2x + 5 = 9
=> 2x = 9 - 5 = 4
=> x = 4 : 2 = 2
Vậy x = 2
2. Ta có: 4. ( 3x - 13 ) = 64 : 2^3
=> 4. ( 3x - 13 ) = 64 : 8 = 8
=> 3x - 13 = 8 : 4 = 2
=> 3x = 2 + 13 = 15
=> x = 15 : 3 = 5
Vậy x =5
Chúc bạn học tốt! ~
a)
\(2x+5.11^0=3^2\)
<=>\(2x+5.1=3^2\)
<=> \(2x=9-5\)
<=> \(2x=4\)
<=> \(x=2\)
Vậy x=2
b)
\(4.\left(3x-13\right)=\dfrac{64}{2^3}\)
<=> \(4\left(3x-13\right)=\dfrac{64}{8}\)
<=> \(4.\left(3x-13\right)=8\)
<=> \(3x-13=2\)
<=> \(3x=15\)
<=> \(x=5\)
Vậy x=5
125(28+72)-25(3^2.4+64)
=125.100-25(9.4+64)
=125.100-25.(36+64)
=125.100-25.100
=12500-2500
=10000
a) \(2^2.2^4.x=16^2\)
\(2^6x=\left(2^4\right)^2\)
\(2^6.x=2^8\)
\(x=2^8:2^6\)
\(x=2^2\)
\(x=4\)
vay \(x=4\)
b) \(5^{2x+1}=125\)
\(5^{2x+1}=5^3\)
\(\Rightarrow2x+1=3\)
\(\Rightarrow2x=2\)
\(\Rightarrow x=1\)
vay \(x=1\)
c) \(\left(2x-1\right)^3=64\)
\(\left(2x-1\right)^3=4^3\)
\(\Rightarrow2x-1=4\)
\(\Rightarrow2x=5\)
\(\Rightarrow x=\frac{5}{2}\)
vay \(x=\frac{5}{2}\)
\(a,2x^5+2=4\)=> \(2x^5=2\)=> \(x^5=1\)=> x = 1
\(b,(x-2)^2=144\)
=> \((x-2)^2=12^2\)
=> \(x-2=\pm12\)
=> \(\orbr{\begin{cases}x-2=12\\x-2=-12\end{cases}}\)=> \(\orbr{\begin{cases}x=14\\x=-10\end{cases}}\)
\(c,(2x+1)^2=49\)
=>\((2x+1)^2=7^2\)
=> \(2x+1=\pm7\)
=> \(\orbr{\begin{cases}2x+1=7\\2x+1=-7\end{cases}}\)=> \(\orbr{\begin{cases}2x=6\\2x=-8\end{cases}}\)=> \(\orbr{\begin{cases}x=3\\x=-4\end{cases}}\)
e, Tương tự
\(2^{10}.2^{x+4}=64^5\)
\(\Leftrightarrow2^{x+14}=2^{30}\)
\(\Leftrightarrow x+14=30\)
\(\Leftrightarrow x=16\)
\(5^x+5^{x+3}=630\)
\(\Rightarrow5^x.1+5^x.125=630\)
\(\Rightarrow5^x.126=630\)
\(\Rightarrow5^x=5\)
\(\Rightarrow x=1\)
\(x+\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+..............+\left(x+100\right)=7450\)
\(\Rightarrow\left(x+x+x+x+.........+x\right)+\left(1+2+3+..........+100\right)=7450\)
\(101x+5050=7450\)
Đến đây tự tính
a)(2x+4).8-40=24
(2x+4).8=24+40
(2x+4).8=64
2x+4=64:8
2x+4=8
2x=8+4
2x=12
x=12:2
x=6
b)(2x+42)-8=64:2
(2x+16)-8=32
2x+16=32+8
2x+16=40
2x=40-16
2x=24
x=24:2
x=12
c)(3x+2).4-20=24
(3x+2).4=24+20
(3x+2).4=44
3x+2=44:4
3x+2=11
3x=11-2
3x=9
x=9:3
x=3
= 42x-5 = 43
=> 2x -5 = 3
<=> 2x = 8
<=> x = 4
Chúc bạn hc tốt