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DT
0
1 tháng 5 2019
a)2/9-(-4/9)=6/9=2/3
b)(-1/24+0,25+1 1/12):(-1/2)2
=(-1/24+6/24+26/24):(-1/2).2
=31/24.-2.2
=-31/12.2
=-31/6
c)3/13.(-5/9)+10/13.(-5/9)+(-4/9)
=-5/9(3/13+10/13)+(-4/9)
=-5/9.1+(-4/9)
=-1
NP
2
1 tháng 8 2018
d) \(\frac{2}{3}+\frac{-5}{12}=\frac{8-5}{12}=\frac{3}{12}=\frac{1}{4}\)
k) \(\left(4-\frac{5}{12}\right):2+\frac{5}{24}=\frac{43}{12}\cdot\frac{1}{2}+\frac{5}{24}=\frac{43+5}{24}=\frac{48}{24}=2\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
11 tháng 11 2024
a; (4 - \(\dfrac{12}{5}\)).\(\dfrac{25}{8}\) - \(\dfrac{2}{5}\) : - \(\dfrac{4}{25}\)
= 4.\(\dfrac{25}{8}\) - \(\dfrac{12}{5}\).\(\dfrac{25}{8}\) - \(\dfrac{2}{5}\) x \(\dfrac{-25}{4}\)
= \(\dfrac{25}{2}\) - \(\dfrac{15}{2}\) + \(\dfrac{5}{2}\)
= \(\dfrac{10}{2}\) + \(\dfrac{5}{2}\)
= \(\dfrac{15}{2}\)
NT
Nguyễn Thị Thương Hoài
Giáo viên
VIP
11 tháng 11 2024
b; (- \(\dfrac{5}{24}\) + \(\dfrac{3}{4}\) - \(\dfrac{7}{12}\)) : (- \(\dfrac{5}{16}\))
= (- \(\dfrac{5}{24}\)) : (-\(\dfrac{5}{16}\)) + \(\dfrac{3}{4}\) : (- \(\dfrac{5}{16}\)) - \(\dfrac{7}{12}\) : (- \(\dfrac{5}{16}\))
= \(\dfrac{5}{24}\) x \(\dfrac{16}{5}\) - \(\dfrac{3}{4}\) x \(\dfrac{16}{5}\) + \(\dfrac{7}{12}\) x \(\dfrac{16}{5}\)
= \(\dfrac{2}{3}\) - \(\dfrac{12}{5}\) + \(\dfrac{28}{15}\)
= \(\dfrac{10}{15}\) - \(\dfrac{36}{15}\) + \(\dfrac{28}{15}\)
= \(\dfrac{-26}{15}\) + \(\dfrac{28}{15}\)
= \(\dfrac{2}{15}\)
9 tháng 2 2017
a) \(24\left(16-5\right)-16\left(24-5\right)\)
\(=24.16-24.5-16.24+16.5\)
\(=\left(24.16-16.24\right)-24.5+16.5\)
\(=5\left(-24+16\right)\)
\(=5\left(-8\right)\)
\(=-40\)
b) \(29\left(9-13\right)-19\left(29-13\right)\)
\(=29.9-29.13-19.29+19.13\)
\(=\left(29.9-19.29\right)-\left(29.13-19.13\right)\)
\(=29\left(9-19\right)-13\left(29-19\right)\)
= \(29.\left(-10\right)-13.10\)
\(=-290-130\)
\(=-420\)
c) \(31.\left(-18\right)+31.\left(-81\right)-31\)
\(=31\left[-18+\left(-81\right)\right]-31\)
\(=31.\left(-99\right)-31\)
\(=31\left(-99-1\right)\)
\(=31.\left(-100\right)\)
\(=-3100\)
d) \(-12.47+\left(-12\right).52+\left(-12\right)\)
\(=-12\left(47+52+1\right)\)
\(=-12.100\)
\(=-1200\)
e) \(\left(-6-2\right)\left(-6+2\right)\)
= \(-8.\left(-4\right)\)
\(=32\)
\(f\)) \(\left(-5+9\right)\left(-4\right)\)
\(=4.\left(-4\right)\)
\(=-16\)
VK
0
CT
1
NK
10 tháng 8 2016
2/3-6/12+1/4 = 5/12
4/12-18/24+5/2 = 25/12
-5/7*11/9+5/7*4/9 = -5/9
-3/8*13/11-3/8*3/11 = -6/11
AH
Akai Haruma
Giáo viên
21 tháng 10 2023
1.
$(5^{1986}-5^{1985}):5^{1985}=5^{1985}(5-1):5^{1985}=5-1=4$
2.
\((7^{846}+7^{847}):7^{846}=7^{846}(1+7):7^{846}=1+7=8\)
3.
\((9^{2018}-3^{4036}):6^{2006}=[(3^2)^{2018}-3^{4036}]:6^{2006}\)
$=(3^{4036}-3^{4036}):6^{2006}=0:6^{2006}=0$
4.
$(7^{80}.8^{70}-56^{70}):56^{70}$
$=[7^{10}(7.8)^{70}-56^{70}]:56^{70}$
$=[7^{10}.56^{70}-56^{70}]:56^{70}$
$=56^{70}(7^{10}-1):56^{70}=7^{10}-1$
AH
Akai Haruma
Giáo viên
21 tháng 10 2023
5.
$4^{4016}:(4^{4017}-4^{4016})=4^{4016}:[4^{4016}(4-1)]$
$=4^{4016}:4^{4016}:3=1:3=\frac{1}{3}$
6.
$(12^{206}.2^{207}-24^{206}):24^{206}$
$=(12^{206}.2^{206}.2-24^{206}):24^{206}$
$=[(12.2)^{206}.2-24^{206}]:24^{206}$
$=(24^{206}.2-24^{206}):24^{206}$
$=24^{206}(2-1):24^{206}=2-1=1$
7.
$(5^2-24)^{8946}+4^{30}:2^{60}=1^{8946}+(2^2)^{30}:2^{60}$
$=1+2^{60}:2^{60}=1+1=2$
8.
$(37.8^{1007}-7.2^{3021}):8^{1007}=[37.8^{1007}-7.(2^3)^{1007}]:8^{1007}$
$=[37.8^{1007}-7.8^{1007}]:8^{1007}$
$=8^{1007}(37-7):8^{1007}=37-7=30$