Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Bài 1 :
a) ( 2x + 1 )3 = 9.81
=> ( 2x + 1 )3 = 9 . 92
=> ( 2x + 1 )3 = 93
=> 2x + 1 = 9
=> 2x = 9 - 1
=> 2x = 8
=> x = 8 : 2
=> x = 4
Vậy x = 4
a) \(\left(2x+1\right)^3=8.91\)
\(\left(2x+1\right)^3=729\)
\(\left(2x+1^3\right)=9^3\)
\(\Rightarrow2x+1=9\)
\(2x=9-1\)
\(2x=8\)
\(x=8:2\)
\(x=4\)
Vậy \(x=4\) là giá trị cần tìm
b) \(5^x+5^{x+2}=650\)
\(5^x+5^x+5^2=650\)
\(5^x\left(1+5^2\right)=650\)
\(5^x.26=650\)
\(5^x=650:26\)
\(5^x=25\)
\(5^x=5^2\)
\(\Rightarrow x=2\)
Vậy \(x=2\) là giá trị cần tìm
2.
\(\left(1+2+3+...+100\right)\cdot\left(1^2+2^2+3^2+...+10^2\right)\cdot\left(65\cdot111-13\cdot15\cdot37\right)\\ =\left(1+2+3+...+100\right)\cdot\left(1^2+2^2+3^2+...+10^2\right)\cdot\left(65\cdot111-13\cdot5\cdot3\cdot37\right)\\=\left(1+2+3+...+100\right)\cdot\left(1^2+2^2+3^2+...+10^2\right)\cdot\left[65\cdot111-\left(13\cdot5\right)\cdot\left(3\cdot37\right)\right]\\ =\left(1+2+3+...+100\right)\cdot\left(1^2+2^2+3^2+...+10^2\right)\cdot\left[65\cdot111-65\cdot111\right]\\ =\left(1+2+3+...+100\right)\cdot\left(1^2+2^2+3^2+...+10^2\right)\cdot0\\ =0\)
a) 26 x 4 + 169 : 132 = 104 + 169 : 169 = 104 + 1 = 105
b) 555 : 5 + 256 : 162 = 111 + 256 : 256 = 111 + 1 = 112
c) 175 - ( 3 x 52 - 5 x 32 ) = 175 - ( 3 x 25 - 5 x 9 ) = 175 - ( 75 - 45 )
= 175 - 30 = 145
a: \(\Leftrightarrow3\cdot5^n\cdot25+4\cdot5^n\cdot\dfrac{1}{125}=19\cdot5^{10}\)
\(\Leftrightarrow5^n\cdot\left(75+\dfrac{4}{125}\right)=19\cdot5^{10}\)
\(\Leftrightarrow5^n\simeq2472903,228\)(vô lý)
b: \(\Leftrightarrow6^x\cdot11\cdot\dfrac{1}{6}+2\cdot6^x\cdot6=11\cdot6^{11}+2\cdot6^{11}\cdot36\)
\(\Leftrightarrow6^x\left(\dfrac{11}{6}+12\right)=6^{11}\cdot83\)
\(\Leftrightarrow6^x=6^{12}\)
hay x=12
\(3^2.x+2^2.x=26.2^2-13\)
\(\Rightarrow x.\left(3^2+2^2\right)=26.4-13\)
\(\Rightarrow x.13=104-13=91\)
\(\Rightarrow x=91:13=7\)
32 . x + 22 . x = 26 . 22 - 13
9 . x + 4 . x = 26 . 4 - 13
( 9 + 4 ) . x = 104 - 13
13 . x = 91
x = 91 : 13
x = 7