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d)\(\frac{2}{3.5}+\frac{2}{5.7}+....+\frac{2}{97.99}\)
\(=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+....+\frac{1}{97}-\frac{1}{99}\)
\(=\frac{1}{3}-\frac{1}{99}\)
\(=\frac{32}{99}\)
a) 11/4x(-0,4)x-1,6x11/4
= -1,1 x-1,6x11/4
= 1,76x11/4
= 4,48
b) 6/19x-7/11+6/19x-4/19x-4/11+13/19
= -42/209+96/3971+13/19
= -702/3971+13/19
= 2015/3971
c) 2/5x3/7+-3/7x3/5+3/7
= 3/7x(2/5+3/5+1)
= 3/7x(1+1)
= 3/7x2
= 6/7
d) 2/3x5+2x5/7+2/7x9+....+2/97x99
= 1/3-1/5+1/5-1/7+1/7-1/9+......+1/97-1/99
= 1/3-1/99
= 32/99
a) \(\frac{7}{2}-\frac{14}{3}+\left(\frac{3}{4}-\frac{7}{3}\right)-\left(\frac{5}{6}-\frac{7}{4}\right)+\frac{11}{2}-3\)
\(=\frac{7}{2}-\frac{14}{3}+\frac{3}{4}-\frac{7}{3}-\frac{5}{6}+\frac{7}{4}+\frac{11}{2}-3\)
\(=\left(\frac{7}{2}+\frac{11}{2}\right)-\left(\frac{14}{3}+\frac{7}{3}\right)-3+\left(\frac{3}{4}+\frac{7}{4}\right)-\frac{5}{6}\)
\(=9-7-3+(\frac{5}{2}-\frac{5}{6})\)
\(=-1+\frac{5}{3}\)
\(=\frac{2}{3}\)
b) \(\frac{7}{3}-\frac{7}{5}+\frac{11}{10}-\left(\frac{2}{5}-\frac{5}{6}\right)+\frac{4}{15}-\frac{4}{3}\)
\(=\left(\frac{7}{3}-\frac{4}{3}\right)-\left(\frac{7}{5}+\frac{2}{5}\right)+(\frac{11}{10}+\frac{5}{6}+\frac{4}{15})\)
\(=1-\frac{9}{5}+\frac{11}{5}\)
\(=1-\left(\frac{9}{5}-\frac{11}{5}\right)\)
\(=1-\left(\frac{-2}{5}\right)\)
\(=1\frac{2}{5}\)
......................?
mik ko biết
mong bn thông cảm
nha ................
a) 5/9 + 4/9 . 3/7 + 4/9 . 4/7
= 5/9 + 4/9 . (3/7 + 4/7)
= 5/9 + 4/9 . 1
= 5/9 + 4/9
= 1
\(M=\left(\frac{3}{5}+\frac{4}{5}\right)+\left(\frac{3}{7}+\frac{4}{7}\right)-\left(\frac{3}{11}+\frac{4}{11}\right)\)
\(=\frac{7}{5}+1-\frac{7}{11}\)
\(\frac{12}{5}-\frac{7}{11}\)
\(=......t\text{ự}t\text{ính}nh\text{á}\)
\(=\frac{3}{5}+\frac{3}{7}-\frac{3}{11}+\frac{4}{5}+\frac{4}{7}-\frac{4}{11}\)
\(=\left(\frac{3}{5}+\frac{4}{5}\right)+\left(\frac{3}{7}+\frac{4}{7}\right)-\left(\frac{3}{11}+\frac{4}{11}\right)\)
\(=\frac{7}{5}+1-\frac{7}{11}\)
\(=\frac{12}{5}-\frac{7}{11}\)
\(=\frac{97}{55}\)
- Spirit Of Yen Thanh Dong lừa làm
\(\frac{\frac{3}{5}+\frac{3}{7}+\frac{3}{11}}{\frac{4}{5}+\frac{4}{7}+\frac{4}{11}}\)
\(=\frac{3.\frac{1}{5}+3.\frac{1}{7}+3.\frac{1}{11}}{4.\frac{1}{5}+4.\frac{1}{7}+4.\frac{1}{11}}\)
\(=\frac{3\left(\frac{1}{5}+\frac{1}{7}+\frac{1}{11}\right)}{4\left(\frac{1}{5}+\frac{1}{7}+\frac{1}{11}\right)}\)
\(=\frac{3}{4}\)
A=\(\frac{\frac{4}{5}+\frac{4}{7}-\frac{4}{11}}{\frac{3}{5}+\frac{3}{7}-\frac{3}{11}}=\frac{4\left(\frac{1}{5}+\frac{1}{7}-\frac{1}{11}\right)}{3\left(\frac{1}{5}+\frac{1}{7}-\frac{1}{11}\right)}=\frac{4}{3}\)
a=113/13-(24/7+53/13)=113/13-24/7-53/13=60/13-24/7=396/16
b=(64/9+37/11)-44/9=64/9+37/11-44/9=20/9+37/11=181/33
c=-5/7(2/11+9/11)+15/7=-5/7+15/7=10/7
d=0.7.22/3.20.0.375.5/28=0
e=(6,17+35/9-236/97)(1/3-0.25-1/12)=A.(1/3-1/4-1/12)=A.(1/12-1/12)=A.0=0
e=(6,17 + 3 5/9 - 2 36/97 ) . ( 1/3 - 0,25 - 1/12)=(6,17 + 3 5/9 - 2 36/97 ) .(1/3-1/12-0,25)
=(6,17 + 3 5/9 - 2 36/97 ) .(4/12-1/12-0,25)=(6,17 + 3 5/9 - 2 36/97 ) .(3/12-0,25)
=(6,17 + 3 5/9 - 2 36/97 ) .(1/4-0.25)=(6,17 + 3 5/9 - 2 36/97 ) .(0.25-0.25)
=(6,17 + 3 5/9 - 2 36/97 ) .0=0
Vậy E=0
=3(1/5+1/7-1/11)/4(1/5+1/7-1/11)
=3/4
(3/5+3/7-3/11)/(4/5+4/7-4/11)
=(21/35+15/35-3/11)/(4/5+4/7-4/11)
=(36/35-3/11)/(4/5+4/7-4/11)
=(396/385-105/385)/(4/5+4/7-4/11)
=(291/385)/(4/5+4/7-4/11)
=(291/385)/(28/35+20/35-4/11)
=(291/385)/(48/35-4/11)
=(291/385)/(528/385-140/385)
=(291/385)/(388/385)
=(291/385):(388/385)
=(291/385)x(385/388)
=112035/149380
=3/4
=