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- \(B=\frac{1}{1.5}+\frac{1}{5.9}+\frac{1}{9.13}+...+\frac{1}{93.97}\)
\(4.B=\frac{4}{1.5}+\frac{4}{5.9}+\frac{4}{9.13}+...+\frac{4}{93.97}\)
\(4.B=1-\frac{1}{5}+\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+...+\frac{1}{93}-\frac{1}{97}\)
\(4.B=1-\frac{1}{97}\)
\(4.B=\frac{96}{97}\)
\(B=\frac{96}{97}:4\)
\(B=\frac{24}{97}\)
a) 128 - 3(x + 4) = 23
3(x + 4) = 128 -23
3(x + 4) = 105
x + 4 = 105 : 3
x + 4 = 35
x = 35 - 4
x = 31
\(a.128-3\left(x+4\right)=23.\)
\(3\left(x+4\right)=128-23\)
\(3\left(x+4\right)=105\)
\(x+4=105:3=35\)
\(x=35-4=31\)
\(b.\left[\left(4x+28\right)\cdot3+55\right]:5=35\)
\(\left(4x+28\right)\cdot3+55=35\cdot5=175\)
\(\left(4x+28\right)\cdot3=175-55=120\)
\(4x+28=120:3=40\)
\(4x=40-28=12\)
\(x=12:4=3\)
Mk ko chép lại đầu bài đâu,thông cảm nha mk chỉ biết giải ý B
3B=1.2.3+2.3.3+3.4.3+...+1000.1001.3
=1.2.(3-0)+2.3.(4-1)+3.4.(5-2)+...+1000.1001.(1002-999)
=1.2.3-1.2.0+2.3.4-2.3.1+3.4.5-3.4.2+...+1000.1001.1002-1000.1001.999
=(1.2.3+2.3.4+3.4.5+...+1000.1001.1002) - (1.2.0+2.3.1+3.4.2+...+1000.1001.999)
=1000.1001.1002
=>B=(1000.1001.1002):3
=334 334 000
k hộ mk nha!
1-1/2+1/2-1/3+1/3+1/4-1/4+1/5-1/5+1/6-1/6+1/7-1/7+1/8-1/8+1/9-1/9+1/10-(1-1/3+1/3-3/5+3/5-4/7+5/9-5/9+6/11-6/11-7/13)=1+1/10-1+7/13=83/130
E=4/3+4/15+4/35+4/63+...+4/399+4/483
=4/1.3+4/3.5+4/5.7+4/7.9+...+4/19.21+4/21.23
=2(2/1.3+2/3.5+2/5.7+...+2/19.21+2/21.23)
=2(1/1-1/3+1/3-1/5+1/5-1/7+...+1/19-1/21+1/21-1/23)
=2(1/1-1/23)
=2(23/23-1/23)
=2.22/23
=44/23
D =3-32-....-3100
(=)D=3-(32+33+....+3100)
(=)3D=3.3-(33+....+3101)
(=)2D=6-(3101-32)
(=)D=6-(3101-32) :2
B=-2/15-2/35-....-2/399
(=)B=-2/15-(2/35-...-2/399)
(=)B=-2/15-(2/5.7-...-2/19.21)
(=)B=-2/15-(1/5-1/21)
(=)B=-2/15-16/105
(=)B=-2/7
3/15+3/35+...+3/399
Đặt S=3/15+3/35+...+3/399
=> S=3/3.5+3/5.7+..+3/19.21
=> S=(3/3.5+3/5.7+...+3/19.21).2
=> S=2.3/3.5+2.3/5.7+...+2.3/19.21
=> S=3.(2/3.5+2/5.7+...+2/19.21)
=> S=3.(1/3-1/5+1/5-1/7+...+1/19-1/21)
=> S=3.(1/3-1/21)
=> S=3.2/7
=> S=6/7
Vậy 3/15+3/35+...+3/399=6/7
\(\frac{3}{15}+\frac{3}{35}+\frac{3}{63}+...+\frac{3}{399}\)
\(=\frac{3}{3.5}+\frac{3}{5.7}+\frac{3}{7.9}+...+\frac{3}{399}\)
\(=\frac{3}{2}.\left(\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+...+\frac{1}{19.21}\right)\)
\(=\frac{3}{2}.\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{19}-\frac{1}{21}\right)\)
\(=\frac{3}{2}.\left(\frac{1}{3}-\frac{1}{21}\right)\)
\(=\frac{3}{2}.\frac{2}{7}\)
\(=\frac{3}{7}\)