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a) 20152016 + 20152015 = 20152015 . 2015 + 20152015 = 20152015 . ( 2015 + 1 ) = 20152015 . 2016
20162016 = 20162015 . 2016
Vì 20152015 . 2016 < 20162015 . 2016 nên 20152016 + 20152015 < 20162016
b) 5299 < 5300 = ( 52 ) 150 = 25150
3501 = ( 33 ) 167 = 27167
Vì 25150 < 27167 nên 5299 < 3501
Đổi: \(\frac{1}{5}=\frac{25}{125}\)
\(\frac{1}{25}=\frac{5}{125}\)
Vậy \(\frac{1}{5}+\frac{1}{25}+\frac{1}{125}=\frac{25}{125}+\frac{5}{125}+\frac{1}{125}\)= \(\frac{31}{125}\)
-2x-(x-7)=34-(-x+25)
-2x-x+7=34+x-25
-2x-x+7-34-x+25=0
-4x-2=0
-4x=2
x=\(-\frac{1}{2}\)
#H
Bài 1 : dễ bạn tự làm được :)
Bài 2 :
Ta có :
\(B=\frac{2015+2016+2017}{2016+2017+2018}=\frac{2015}{2016+2017+2018}+\frac{2016}{2016+2017+2018}+\frac{2017}{2016+2017+2018}\)
Vì :
\(\frac{2015}{2016}>\frac{2015}{2016+2017+2018}\)
\(\frac{2016}{2017}>\frac{2016}{2016+2017+2018}\)
\(\frac{2017}{2018}>\frac{2017}{2016+2017+2018}\)
Nên \(\frac{2015}{2016}+\frac{2016}{2017}+\frac{2017}{2018}>\frac{2015}{2016+2017+2018}+\frac{2016}{2016+2017+2018}+\frac{2017}{2016+2017+2018}\)
\(\Leftrightarrow\)\(\frac{2015}{2016}+\frac{2016}{2017}+\frac{2017}{2018}>\frac{2015+2016+2017}{2016+2017+2018}\)
\(\Leftrightarrow\)\(A>B\)
Vậy \(A>B\)
Chúc bạn học tốt ~
Ta có : B = 2016 + 2017 + 2018 2015 + 2016 + 2017 = 2016 + 2017 + 2018 2015 + 2016 + 2017 + 2018 2016 + 2016 + 2017 + 2018 2017 Vì : 2016 2015 > 2016 + 2017 + 2018 2015 2017 2016 > 2016 + 2017 + 2018 2016 2018 2017 > 2016 + 2017 + 2018 2017 Nên 2016 2015 + 2017 2016 + 2018 2017 > 2016 + 2017 + 2018 2015 + 2016 + 2017 + 2018 2016 + 2016 + 2017 + 2018 2017 ⇔ 2016 2015 + 2017 2016 + 2018 2017 > 2016 + 2017 + 2018 2015 + 2016 + 2017 ⇔A > B Vậy A > B Chúc bạn học tốt ~
a) x+ 10 = 2
x = 2 - 10 = -8
b) 15 - x = -25
x = 15 - (-25) = 40
Ta có:\(\left(25-2015\right)-\left(25-2016\right)\)
\(=25-2015-25+2016\)
\(=\left(25-25\right)-\left(2015-2016\right)\)
\(=0-\left(-1\right)\)
\(=1\)
Vậy: \(\left(25-2015\right)-\left(25-2016\right)=1\)
\(\left(25-2015\right)-\left(25-2016\right)\)
\(=25-2015-25+2016\)
\(=\left(25-25\right)+\left(-2015+2016\right)\)
\(=0+1\)
\(=1\)