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\(10x+2^2.5=10^2\)
\(10x+4.5=100\)
\(10x+20=100\)
\(10x=100-20\)
\(10x=80\)
\(x=80:10\)
\(x=8\)
10x+2^2x5=10^2
10x+4x5=100
10x+20=100
10x=100-20=80
x=80:10=8
10x + 22 x 5 = 102
=> 10x + 4 x 5 = 100
=> 10x + 20 = 100
=> 10x = 100 - 20
=> 10x = 80
=> x = 80 : 10
=> x = 8
(x+1) + (2x+2) + (3x+3) + ...+ (10x+10) = 550
( x + 2x + 3x + ...+ 10x) + (1+2+3+..+10) = 550
x.(1+2+3+...+10) + 55 = 550
x.55 + 55 = 550
55.(x+1) = 550
x+ 1 = 10
x = 9
(x+1)+(2x+2)+.....+(10x+10)=550
x+1+2x+2+...+10x+10=550
(x+2x+3x+...+10x)+(1+2+3+4+...+10)=550
x nhân (1+2+3+...+10)+1 nhân (1+2+3+...+10)=550
(1+2+3+...+10) nhân (x+1)=550
55 nhân (x+1)=550 =>x+1=550:55=10
x =9
nk nghĩ v,hc tốt
b) \(9x-2:3^2=3^4\)
\(9x-2:9=81\)
\(2:9=9x-81\)
\(\dfrac{2}{9}=9x-81\)
\(9x=81+\dfrac{2}{9}\)
\(9x=\dfrac{731}{9}\)
\(x=\dfrac{731}{9}:9\)
\(x=\dfrac{731}{81}\)
\(a.5x-5^2=10\) \(b.9x-2:3^2=3^4\)
\(5x=10+5^2\) \(9x-2=3^4.3^2\)
\(5x=35\) \(9x-2=729\)
\(x=35:5=7\) \(9x=729+2=731\)
\(x=731:9\)
\(x=\dfrac{731}{81}\)
\(c=10x+\left(2^2\right).5=10^2\)
\(10x+20=100\)
\(10x=100-20\)
\(10x=80\)
\(x=80:10=8\)
\(-7.\left(5-x\right)-2.\left(x-10\right)=1\)
\(-35+7x-2x+20=1\)
\(-15+5x=1\)
\(5x=1+15\)
\(5x=16\)
\(x=\frac{16}{5}\)
\(-5.\left(2-x\right)+4.\left(x-3\right)=10x-15\)
\(-10+5x+4x-12=10x-15\)
\(-22+9x=10x-15\)
\(9x-10x=-15+22\)
\(-x=7\)
\(x=-7\)