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\(\left(x-1\right)^{10}=0\)
\(\Leftrightarrow x-1=0\)
\(\Leftrightarrow x=1\)
290-10.(2018^0+3^5:3^2)
=290-10.(1+243:9)
=290-10.(1+27)
=290-10.28
=290-280
=10
71-50:[5+3.(57-6.7)]
a)
\(-68+\left(-72\right)+2017+\left(-28\right)+168.\)
\(=\left(-68+168\right)+\left(-28-72\right)+2017.\)
\(=\left(168-68\right)+\text{ }\left[-\left(72+28\right)\right]+2017.\)
\(=100+\left(-100\right)+2017.\)
\(=100-100+2017.\)
\(=2017\)
b)
\(\left|-28\right|+\left(129-182+99\right)\)\(-\left(129+199-182\right)\)
\(=28+129-182+99\)\(-129-199+182.\)
\(=28+\left(129-129\right)+\left(182-182\right)\)\(-\left(199-99\right)\)
\(=28+0+0-100.\)
\(=-\left(100-28\right)\)
\(=-72\)
c)
\(17\left(-83\right)+18\times83.\)
\(=-17\left(83\right)+18\left(83\right)\)
\(=83\left[18+\left(-17\right)\right]\)
\(=83\left(18-17\right)\)
\(=83\left(1\right)\)
\(=83\)
d)
\(2018^0-\left(15^2\div\left[175+\left(2^3\times5^2-6\times25\right)\right]\right).\text{ }\)
\(=1-\left(15^2\div\left[175+\left(8\times25-6\times25\right)\right]\right)..\)
\(=1-\left(15^2\div\left[175+\left(25\left[8-6\right]\right)\right]\right)\)
\(=1-\frac{15^2}{175+\left(25\times2\right)}.\)
\(=1-\frac{15^2}{175+50}\)
\(=1-\frac{225}{225}\)
\(=1-1\)
\(=0\)
Học tốt
Mìk xin lỗi nha, câu a sai rùi, làm lại cho:
a) \(12.3^2-2^3.\left(2015^0+1^3\right)=12.9-8.\left(1+1\right)\)
\(=12.9-8.2=108-16=92\)
OK rùi đấy, tick nha thank you trước
a)2019-5{70+9[37-(32+1)]}=2019-5{70+9[37-33]}=2019-5{70+9.4}=2019-5.106=2019-530=1489
b)3[25-(9+8)]-25(8+1)=3[25-17]-25.9=3.8-225=-201
a) ( x-140):7=33 -23 -3
(x-140):7 = 27 - 8-3
(x-140):7 = 16
(x-140):7 = 16 .7
x-140 = 112
x-140 = 112+ 140
x = 252
2, \(=>9A=3^3+3^5+3^7+......+3^{39}+3^{41}\)
\(=>9A-A=3^{41}-3\)
\(=>A=\dfrac{3^{41}-3}{8}\)
CHÚC BẠN HỌC TỐT........
\(2018^0\left\{15^2:\left[175+2^3.5^2\right]\right\}\\ =1\left\{225:\left[175+8.25\right]\right\}\\ =225:\left[175+200\right]\\ =225:375\\ =\dfrac{3}{5}\)