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6: \(=3\cdot2\sqrt{3}-4\cdot3\sqrt{3}+5\cdot4\sqrt{3}=14\sqrt{3}\)
7: \(=2\sqrt{3}+5\sqrt{3}-4\sqrt{3}=3\sqrt{3}\)
8: \(=2\cdot4\sqrt{2}+4\cdot2\sqrt{2}-5\cdot3\sqrt{2}=\sqrt{2}\)
9: \(=3\cdot2\sqrt{5}-2\cdot3\sqrt{5}+4\sqrt{5}=4\sqrt{5}\)
10: \(=2\cdot2\sqrt{6}-2\cdot3\sqrt{6}+3\sqrt{6}-5\sqrt{6}=-4\sqrt{6}\)
=\(\frac{1}{\sqrt{5}}+\frac{5\left(2\sqrt{5}+5\sqrt{5}\right)}{\left(2\sqrt{5}+5\sqrt{5}\right)\left(2\sqrt{5}-5\sqrt{5}\right)}+\frac{2\left(2+\sqrt{5}\right)}{\left(2-\sqrt{5}\right)\left(2+\sqrt{5}\right)}\)
=\(\frac{1}{\sqrt{5}}-7\sqrt{5}-2\sqrt{5}-4\)=\(\frac{1-45-4\sqrt{5}}{\sqrt{5}}=\frac{-44\sqrt{5}-20}{5}\)
a: \(=9\sqrt{2}-4\sqrt{2}+4\sqrt{2}+9\sqrt{2}=18\sqrt{2}\)
b: \(=8\sqrt{3}-12\sqrt{3}+5\sqrt{3}+2\sqrt{3}=3\sqrt{3}\)
c: \(=2\sqrt{21}\)
a, (\(\sqrt{128}\)-\(\sqrt{50}\)+\(\sqrt{98}\)):\(\sqrt{2}\)
=(8-5+3)
=10
b, (\(\sqrt{48}\)+\(\sqrt{27}\)-\(\sqrt{192}\)):2\(\sqrt{3}\)
=(2+1,5-4)
=-0,5
c, \(\dfrac{1}{8}\)-3\(\sqrt{2}\) +\(\dfrac{1}{8}\)+3\(\sqrt{2}\)
=\(\dfrac{1}{4}\)
d, \(\sqrt{\left(1-\sqrt{5}\right)^2}-\sqrt{5}\)
=-1
\(2\sqrt{5}-3\sqrt{125}+\sqrt{52}-2\sqrt{8}\)
\(=2\sqrt{5}-15\sqrt{5}+2\sqrt{13}-4\sqrt{2}\)
\(=-13\sqrt{5}+2\sqrt{13}-4\sqrt{2}\)