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Ta có : A=20/11×13 + 20/13×15 +20/15×17+...+20/53×55
A = 10 ×( 2/11×13+2/13×15+...12/53×55)
A = 10 ×(1/11-1/13+1/13-1/15+1/15-1/17+...+1/53-1/55)
A = 10 × (1/11-1/55)
A =10 × 4/55
A = 8/11
1a) \(\frac{10}{11}:\frac{11}{3}=\frac{10}{11}.\frac{3}{11}=\frac{30}{121}\)
b) \(3,42:0,75.8,4-6,8\)
\(=4,56.8,4-6,8=38,304-6,8=31,504\)
2a) \(\frac{21}{11}.\frac{22}{17}.\frac{68}{63}=\frac{21.22.68}{11.17.63}=\frac{7.3.2.11.17.4}{11.17.3.3.7}=\frac{2.4}{3}=\frac{8}{3}\)
b) \(\frac{5}{14}.\frac{7}{13}.\frac{26}{25}=\frac{5.7.26}{14.13.25}=\frac{5.7.13.2}{2.7.13.5.5}=\frac{1}{5}\)
\(\frac{10}{11}:1\frac{1}{3}\)
\(=\frac{10}{11}:\frac{4}{3}\)
\(=\frac{10}{11}\cdot\frac{3}{4}\)
\(=\frac{15}{22}\)
\(3,42:0,57\cdot8,4-6,8\)
\(=6\cdot8,4-6,8\)
\(=50,4-6,8\)
\(43,6\)
2.
\(\frac{21}{11}\cdot\frac{22}{17}\cdot\frac{68}{63}\)
\(=\frac{21\cdot22\cdot68}{11\cdot17\cdot63}\)
\(=\frac{21\cdot11\cdot2\cdot17\cdot4}{11\cdot17\cdot21\cdot3}\)
\(=\frac{̸21\cdot̸11\cdot2\cdot̸17\cdot4}{̸11\cdot̸17\cdot̸21\cdot3}\)
\(=\frac{8}{3}\)
\(\frac{5}{14}\cdot\frac{7}{13}\cdot\frac{26}{25}\)
\(=\frac{5\cdot7\cdot26}{14\cdot13\cdot25}\)
\(=\frac{̸5\cdot̸7\cdot̸13\cdot2}{̸7\cdot2\cdot̸13\cdot̸5\cdot5}\)
\(=\frac{2}{10}\)
X + 0,2 x X = 7,2
1,2 x X = 7,2
X = 7,2 : 1,2
X = 6
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Ta có: \(x+20\%x=7,2\)
<=>\(x+0,2x=7,2\)
<=>\(x\left(1+0,2\right)=7,2\)
<=>\(1,2x=7,2\)
<=>\(x=7,2:1,2\)
<=>\(x=6\)
Vậy:\(x=6\)
158,65-63,75:17=158,65-3,75=154,9
65,2:10-67,2x0,1=6,52-6,72=-0,23
xx35=164-83,5
x x35=80,5
x=80,5:35
x=2,3
[7,5x10-650x0,1]xx=8,4
[75-65]x x=8,4
10x x=8,4
x=8,4:10
x=0,84