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ban ko tra loi ho minh cau nay a
neu the minh ket ban kieu gi
a) \(\frac{1}{3}+\frac{1}{4}-\frac{1}{5}\)
\(=\frac{23}{60}\)
b) \(\frac{5}{2}+\frac{1}{3}-\frac{1}{4}\)
\(=\frac{31}{12}\)
c) \(\frac{10}{3}-\left(\frac{1}{4}+\frac{1}{12}\right)\)
\(=\frac{9}{3}=3\)
d) \(\frac{1}{3}+\frac{6}{5}-\frac{1}{15}\)
\(=\frac{22}{15}\)
trả lòi:
A)= 23/60
B)= 31/12
C)= 3* vì 3/9 cùng chia hết cho 3*
D)= 22/15
Hc tốt!
(2/3 x 4/5) x 5/6
= 8/15 x 5/6
= 4/9
(2/3 x 4/5) x 5/6
= (5/6 x 4/5) x 2/3
= 2/3 x 2/3
= 4/9
(1/2 + 1/3) x 1/5
= 5/6 x 1/5
= 1/6
(1/2 + 1/3) x 1/5
= (1/2 x 1/5) + (1/3 x 1/5)
= 1/10 + 1/15
= 1/6
4A6?
a) \(\left(\frac{1}{3}+\frac{1}{5}\right)\cdot\frac{1}{2}\) b)\(\left(\frac{1}{3}-\frac{1}{5}\right)\cdot\frac{3}{5}\)
\(=\frac{8}{15}\cdot\frac{1}{2}\) \(=\frac{2}{15}\cdot\frac{3}{5}\)
\(=\frac{4}{15}\) \(=\frac{2}{25}\)
\(\frac{2}{5}:\frac{3}{7}x\frac{3}{7}:\frac{2}{5}+1999=\)\(\frac{2}{5}x\frac{7}{3}x\frac{3}{7}x\frac{5}{2}+1999=\)\(\left(\frac{2x7x3x5}{5x3x7x2}\right)+1999=\)\(1+1999=2000\)
\(\left(1-\frac{1}{2}\right)x\left(1-\frac{1}{3}\right)x\left(1-\frac{1}{4}\right)x\left(1-\frac{1}{5}\right)\)\(=\left(\frac{2}{2}-\frac{1}{2}\right)\)\(x\left(\frac{3}{3}-\frac{1}{3}\right)\)\(x\left(\frac{4}{4}-\frac{1}{4}\right)\)\(x\left(\frac{5}{5}-\frac{1}{5}\right)\)\(=\frac{1}{2}x\frac{2}{3}x\frac{3}{4}x\frac{4}{5}=\)\(\frac{1x2x3x4}{2x3x4x5}=\frac{1x\left(2x3x4\right)}{\left(2x3x4\right)x5}=\frac{1}{5}\)\(.\)
2/5:3/7 nhân 3/7:2/5+1999
=2/5 nhân 7/3 nhân 3/7nhân 5/2+1999
=14/15 nhân 15/14+1999
=1+1999
=2000
(1-1/2) nhân (1-1/3) nhân (1-1/4) nhân (1-1/5)
=1/2 nhân 2/3 nhân 3/4 nhân 4/5
=24/120
=1/5
\(\dfrac{1}{5}+\dfrac{1}{3}=\dfrac{3}{15}+\dfrac{5}{15}=\dfrac{8}{15}\)
1/5 + 1/3 = 3/15 + 5/15 = 8/15