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11 tháng 4 2019

\(\frac{14}{15}-\frac{5}{6}=\frac{1}{10}\)

\(\frac{9}{7}-\frac{9}{14}=\frac{9}{14}\)

\(2-\frac{3}{4}=\frac{5}{4}\)

11 tháng 4 2019

\(\frac{14}{15}-\frac{5}{6}=\frac{28}{30}-\frac{25}{30}=\frac{3}{30}=\frac{1}{10}\)

\(\frac{9}{7}-\frac{9}{14}=\frac{18}{14}-\frac{9}{14}=\frac{9}{14}\)

\(2-\frac{3}{4}=\frac{8}{4}-\frac{3}{4}=\frac{5}{4}\)

~Học tốt~

10 tháng 9 2016

Giúp mình với hiccc

15 tháng 9 2020

a) 1/2
b) 18/17; 17/16; 16/15; 15/14; 14/13; 13/12; 10/9
Nhớ k cho mk nha

15 tháng 9 2020

a)1/2

b)Vì 18/17 <17/16 <16/15<15/14< 14/13< 13/12< 10/9

Nên, ta có: 

18/17; 17/16; 16/15; 15/14; 14/13; 13/12; 10/9.

9 tháng 9 2016

1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10=55

2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 + 18 + 20=110

1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19=100

k mk nha pạn hiền!

9 tháng 9 2016

10 +1 = 11 có 10 số vậy thì 10 : 2 = 5 thì sẽ bằng 5x11 = 55

2 + 20 = 22 cũng có 10 số lấy 10 : 2 = 5 se bang 22 x5 = 110

1+19 = 20 , 10 : 2 = 5 , 20x5 = 100

11 tháng 12 2015

1+1+2+2+3+3+4+4+5+5+6+6+7+7+8+9+8+9+10+12+13+14+15+16+17+18+19+20+30+1000000=10000274

10000274

21 tháng 7 2019

a) 3+15+35+63           = 116

18+90+210+378            378

=58/189

21 tháng 7 2019

a) \(\frac{1.3+3.5+5.7+7.9}{3.6+9.10+15.14+21.18}\)

\(\frac{1.3+3.5+5.7+7.9}{1.3.2.3+3.5.2.3+5.7.2.3+7.9.2.3}\)

\(\frac{1.3+3.5+5.7+7.9}{1.3.6+3.5.6+5.7.6+7.9.6}\)

\(\frac{1.3+3.5+5.7+7.9}{6.\left(1.3+3.5+5.7+7.9\right)}=\frac{1}{6}\)

Dấu "." là dấu nhân cấp 2 

b)  \(\frac{1.2+2.3+3.4+4.5}{3.6+6.9+9.12+12.15}\)

\(\frac{1.2+2.3+3.4+4.5}{1.2.3.3+2.3.3.3+3.4.3.3+4.5.3.3}\)

\(\frac{1.2+2.3+3.4+4.5}{1.2.9+2.3.9+3.4.9+4.5.9}\)

\(\frac{1.2+2.3+3.4+4.5}{9.\left(1.2+2.3+3.4+4.5\right)}=\frac{1}{9}\)

Dấu "." là dấu nhân cấp 2 

c) \(\frac{0,3+\frac{3}{7}+\frac{3}{11}}{0,4+\frac{4}{7}+\frac{4}{11}}\)\(\frac{\frac{3}{10}+\frac{3}{7}+\frac{3}{11}}{\frac{4}{10}+\frac{4}{7}+\frac{4}{11}}\)\(\frac{3.\left(\frac{1}{10}+\frac{1}{7}+\frac{1}{11}\right)}{4.\left(\frac{1}{10}+\frac{1}{7}+\frac{1}{11}\right)}=\frac{3}{4}\)

10 tháng 8 2022

 

1.3.77−1​+3.7.99−3​+7.9.1313−7​+9.13.1515−9​+\frac{19-13}{13.15.19}+13.15.1919−13​

=\frac{1}{1.3}-\frac{1}{3.7}+\frac{1}{3.7}-\frac{1}{7.9}+\frac{1}{7.9}-\frac{1}{9.13}+\frac{1}{9.13}-\frac{1}{13.15}+\frac{1}{13.15}-\frac{1}{15.19}=1.31​−3.71​+3.71​−7.91​+7.91​−9.131​+9.131​−13.151​+13.151​−15.191​

=\frac{1}{1.3}-\frac{1}{15.19}=\frac{95}{285}-\frac{1}{285}=\frac{94}{285}=1.31​−15.191​=28595​−2851​=28594​

b,=\frac{1}{6}.\left(\frac{6}{1.3.7}+\frac{6}{3.7.9}+\frac{6}{7.9.13}+\frac{6}{9.13.15}+\frac{6}{13.15.19}\right)b,=61​.(1.3.76​+3.7.96​+7.9.136​+9.13.156​+13.15.196​)

làm giống như trên

c,=\frac{1}{8}.\left(\frac{1}{1.2.3}+\frac{1}{2.3.4}+\frac{1}{3.4.5}+...+\frac{1}{48.49.50}\right)c,=81​.(1.2.31​+2.3.41​+3.4.51​+...+48.49.501​)

=\frac{1}{16}.\left(\frac{2}{1.2.3}+\frac{2}{2.3.4}+\frac{2}{3.4.5}+...+\frac{2}{48.49.50}\right)=161​.(1.2.32​+2.3.42​+3.4.52​+...+48.49.502​)

=\frac{1}{16}.\left(\frac{3-1}{1.2.3}+\frac{4-2}{2.3.4}+\frac{5-3}{3.4.5}+...+\frac{50-48}{48.49.50}\right)=161​.(1.2.33−1​+2.3.44−2​+3.4.55−3​+...+48.49.5050−48​)

=\frac{1}{16}.\left(\frac{1}{1.2}-\frac{1}{2.3}+\frac{1}{2.3}-\frac{1}{3.4}+\frac{1}{3.4}-\frac{1}{4.5}+...+\frac{1}{48.49}-\frac{1}{49.50}\right)=161​.(1.21​−2.31​+2.31​−3.41​+3.41​−4.51​+...+48.491​−49.501​)

=\frac{1}{16}.\left(\frac{1}{2}-\frac{1}{2450}\right)=\frac{1}{16}.\left(\frac{1225}{2450}-\frac{1}{2450}\right)=\frac{153}{4900}=161​.(21​−24501​)=161​.(24501225​−24501​)=4900153​

d,=\frac{5}{7}.\left(\frac{7}{1.5.8}+\frac{7}{5.8.12}+\frac{7}{8.12.15}+...+\frac{7}{33.36.40}\right)d,=75​.(1.5.87​+5.8.127​+8.12.157​+...+33.36.407​)

=\frac{5}{7}.\left(\frac{8-1}{1.5.8}+\frac{12-5}{5.8.12}+\frac{15-8}{8.12.15}+...+\frac{40-33}{33.36.40}\right)=75​.(1.5.88−1​+5.8.1212−5​+8.12.1515−8​+...+33.36.4040−33​)

=\frac{5}{7}.\left(\frac{1}{1.5}-\frac{1}{5.8}+\frac{1}{5.8}-\frac{1}{8.12}+\frac{1}{8.12}-\frac{1}{12.15}+...+\frac{1}{33.36}-\frac{1}{36.40}\right)=75​.(1.51​−5.81​+5.81​−8.121​+8.121​−12.151​+...+33.361​−36.401​)

=\frac{5}{7}.\left(\frac{1}{5}-\frac{1}{1440}\right)=\frac{5}{7}.\left(\frac{288}{1440}-\frac{1}{1440}\right)=\frac{41}{288}=75​.(51​−14401​)=75​.(1440288​−14401​)=28841​

P/S: . là nhân nha

1 tháng 6 2018

\(\frac{1}{3}+\frac{3}{7}+\frac{5}{3}+\frac{8}{14}\)

\(=\left(\frac{1}{3}+\frac{5}{3}\right)+\left(\frac{3}{7}+\frac{8}{14}\right)\)

\(=\frac{6}{3}+\left(\frac{6}{14}+\frac{8}{14}\right)\)

\(=2+\frac{14}{14}\)

\(=2+1\)

\(=3\)

\(\frac{5}{6}+\frac{4}{15}+\frac{6}{18}+\frac{3}{45}\)

\(=\left(\frac{5}{6}+\frac{6}{18}\right)+\left(\frac{4}{15}+\frac{3}{45}\right)\)

\(=\left(\frac{5}{6}+\frac{2}{6}\right)+\left(\frac{4}{15}+\frac{1}{15}\right)\)

\(=\frac{7}{6}+\frac{5}{15}\)

\(=\frac{7}{6}+\frac{1}{3}\)

\(=\frac{7}{6}+\frac{2}{6}\)

\(=\frac{9}{6}\)

\(=\frac{3}{2}\)

~ Ủng hộ nhé 

1 tháng 6 2018

\(9\times17+83\times9\)

\(=\left(83+17\right)\times9\)

\(=100\times9\)

\(=900\)

\(4\frac{1}{7}+7+8\frac{6}{7}\)

\(=\left(4\frac{1}{7}+8\frac{6}{7}\right)+7\)

\(=\left(8+4\right)+\left(\frac{1}{7}+\frac{6}{7}\right)+7\)

\(=12+\frac{7}{7}+7\)

\(=12+1+7\)

\(=20\)

~ Ủng hộ nhé 

6 tháng 9 2018

Bài 1:

\(\left(\frac{9}{4}:\frac{6}{5}\right)-1=\frac{45}{24}-1=\frac{15}{8}-1=\frac{7}{8}\)

\(2+\left(\frac{1}{4}\times\frac{2}{5}\right)=2+\frac{2}{10}=2+\frac{1}{5}=\frac{11}{5}\)

Bài 2: 

\(\frac{3}{5}+\frac{2}{3}=\frac{9}{15}+\frac{10}{15}=\frac{19}{15}\)

\(1-\frac{9}{11}=\frac{1}{1}-\frac{9}{11}=\frac{11}{11}-\frac{9}{11}=\frac{2}{11}\)

\(\frac{7}{9}\times\frac{3}{14}=\frac{21}{126}=\frac{3}{18}\)

\(\frac{15}{7}:\frac{5}{21}=\frac{315}{35}=9\)

6 tháng 9 2018

1 Tính giá trị biểu thức

( 9/4 : 6/5 ) - 1 = 45/24 - 1 = 7/8

2 + ( 1/4 × 2/5 ) = 2 + 1/10 = 21/10

2 Tính

3/5 + 2/3 = 

1 - 9/11 = 2/11

7/9 × 3/14 = 1/6

15/7 : 5/21 = 9