Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Câu a đề sai rồi bạn
b: \(3+3^2+3^3+...+3^{16}\)
\(=3\left(1+3\right)+3^3\left(1+3\right)+...+3^{15}\left(1+3\right)\)
\(=4\left(3+3^3+...+3^{15}\right)\)
\(=12\left(1+3^2+...+3^{14}\right)⋮12\)
(3/11+3/13-3/7):(12/11+12/13-12/7) =75/1001:300/1001 =75/1001.1001/300 =1/4
\(a)\dfrac{5}{12}+\dfrac{5}{3}+\dfrac{2}{12}+\dfrac{2}{3}\)
\(=\left(\dfrac{5}{12}+\dfrac{2}{12}\right)+\left(\dfrac{5}{3}+\dfrac{2}{3}\right)\)
\(=\dfrac{7}{12}+\dfrac{7}{3}\)
\(=\dfrac{7}{12}+\dfrac{28}{12}\)
\(=\dfrac{35}{12}\)
\(b)\dfrac{5}{9}.\dfrac{7}{13}+\dfrac{5}{9}-\dfrac{5}{9}.\dfrac{3}{13}\)
\(=\dfrac{5}{9}.1.\dfrac{7}{13}+\dfrac{5}{9}-\dfrac{5}{9}.\dfrac{3}{13}\)
\(=\dfrac{5}{9}.\left(1+\dfrac{7}{13}-\dfrac{3}{13}\right)\)
\(=\dfrac{5}{9}.\dfrac{17}{13}\)
\(=\dfrac{85}{117}\)
\(\left(19\frac{5}{8}:\frac{7}{12}-13\frac{1}{4}:\frac{7}{12}\right).\frac{4}{5}\)
\(=\left(\frac{157}{8}:\frac{7}{12}-\frac{53}{4}:\frac{7}{12}\right).\frac{4}{5}\)
\(=\left[\left(\frac{157}{8}-\frac{53}{4}\right):\frac{7}{12}\right].\frac{4}{5}\)
\(=\left[\frac{51}{8}:\frac{7}{12}\right].\frac{4}{5}\)
\(=\frac{153}{14}.\frac{4}{5}\)
\(=\frac{306}{35}\)
\(\left(\frac{-2}{5}+\frac{3}{7}\right)-\left(\frac{4}{9}+\frac{12}{20}-\frac{13}{35}\right)+\frac{7}{35}\)
\(=\frac{1}{35}-\frac{212}{315}+\frac{7}{35}\)
\(=\frac{1}{35}+\frac{-212}{315}+\frac{7}{35}\)
\(=\frac{9}{315}+\frac{-212}{315}+\frac{63}{315}\)
\(=\frac{-140}{315}=\frac{-4}{9}\)
\(\dfrac{13}{12}:3=\dfrac{13}{12}\times\dfrac{1}{3}=\dfrac{13}{36}\)