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a) \(\frac{15}{16}\cdot\frac{4}{3}-\frac{1}{2}:\frac{5}{4}+3\)
\(=\frac{5}{4}-\frac{2}{5}+3\)
\(=\frac{25}{20}-\frac{8}{20}+\frac{60}{20}\)
\(=\frac{77}{20}=3\frac{17}{20}\)
b) \(\left(\frac{2}{3}-\frac{3}{8}\right):\left(\frac{3}{5}+\frac{1}{4}\right)\)
\(=\frac{7}{24}:\frac{17}{20}\)
\(=\frac{35}{102}\)
c) \(\frac{15}{8}\cdot\left(\frac{1}{3}+\frac{1}{8}\right)-\frac{3}{8}:\frac{3}{4}\)
\(=\frac{15}{8}\cdot\frac{11}{24}-\frac{1}{2}\)
\(=\frac{55}{64}-\frac{1}{2}\)
\(=\frac{23}{64}\)
d) \(\frac{20}{21}:\left(\frac{4}{5}-\frac{1}{10}\right)+\frac{13}{15}:\frac{5}{26}\)
\(=\frac{20}{21}:\frac{7}{10}+\frac{52}{15}\)
\(=\frac{200}{147}+\frac{52}{15}\)
\(=4\frac{608}{735}\)
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Lời giải:
$\frac{-3}{8}.\frac{2}{15}+\frac{-3}{8}.\frac{13}{15}+1\frac{3}{8}$
$=\frac{-3}{8}(\frac{2}{15}+\frac{13}{15})+1+\frac{3}{8}$
$=\frac{-3}{8}.\frac{15}{15}+1+\frac{3}{8}=\frac{-3}{8}+1+\frac{3}{8}=1$
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\(\dfrac{1}{15}-\dfrac{2}{15}+\dfrac{3}{15}-\dfrac{4}{15}+\dfrac{5}{15}-\dfrac{6}{15}+\dfrac{7}{15}-\dfrac{8}{15}+\dfrac{9}{15}\)
\(=\dfrac{1-2+3-4+5-6+7-8+9}{15}\)
\(=\dfrac{\left(1-2\right)+\left(3-4\right)+\left(5-6\right)+\left(7-8\right)+9}{15}\) => có 4 cặp
\(=\dfrac{\left(-1\right)+\left(-1\right)+\left(-1\right)+\left(-1\right)+9}{15}\)
\(=\dfrac{\left(-1\right).4+9}{15}\)
\(=\dfrac{\left(-4\right)+9}{15}\)
\(=\dfrac{5}{15}=\dfrac{1}{3}\)
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=7/15 + 3/8 -7/15 +1/8
=> 3/8+1/8
=> 1/2
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\(A=\frac{15^8-1+3}{15^8-1}=1+\frac{3}{15^8-1}\)
\(B=\frac{15^8-3+3}{15^8-3}=1+\frac{3}{15^8-3}\)
Ta có: \(15^8-3< 15^8-1\)
=> B>A
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a ) ( -1/6 + 5/12 ) + 7/12
= -1/6 + ( 5/12 + 7/12 )
= -1/6 + 12/12
= -2/12 + 12/12
= -10/12
= -5/6
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a: =1/8-1/8+2/5=2/5
b: =(-1/15-14/15)+(23/27+31/27)=2-1=1
c: \(=\dfrac{3}{7}\left(\dfrac{22}{21}+\dfrac{5}{21}+\dfrac{15}{21}\right)=\dfrac{3}{7}\cdot2=\dfrac{6}{7}\)
d: \(=\dfrac{-8}{9}\cdot\dfrac{3}{2}+\dfrac{1}{9}\cdot\dfrac{-3}{2}=-\dfrac{3}{2}\)
1/3 +8/15 : 3/15
= 1/3 + 8/15 x 15/3
= 1/3 + 8/3
= 9/3
= 3
1/3 +8/15 : 3/15
= 1/3 + 8/15 x 15/3
= 1/3 + 8/3
= 9/3
= 3