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(1/3x5+1/5x7+....+1/19x21)*x=9/7
(1/3-1/5+1/5-1/7+...+1/19-1/21)*x=9/7
(1/3-1/21)*x=9/7
2/7*x=9/7
=> x=9/7:2/7
=> x=9/2
Bạn leminhduc sai rùi @@
Ta xét :
B = \(\frac{1}{3.5}+\frac{1}{5.7}+...+\frac{1}{19.21}\)
2 x B = \(\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{19.21}\)
2 x B = \(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{19}-\frac{1}{21}\)
2 x B = \(\frac{1}{3}-\frac{1}{21}\)=\(\frac{2}{7}\)
B = \(\frac{2}{7}:2\)
B = \(\frac{1}{7}\)
Thay B vào biểu thức ta có :
\(\frac{1}{7}.x=\frac{9}{7}\)
=> x = \(\frac{9}{7}:\frac{1}{7}\)=\(\frac{9}{7}.\frac{7}{1}\)=9
Vậy x = 9
=(2-1)*(2+1)+(4-1)*(4+1)+ ...+(2n-1)*(2n+1) =(2^2-1)+(4^2-1)+...+(4n^2-1) =(2^2+4^2+...+4n^2)-(1+1+...+1) =4(1^2+2^2+...n^2)-n n(n+1)(2n+1)/6: 1^2+2^2+3^2+…+n^2=n(n+1)(2n+1)/6n^2=n 1x3+3x5+5x7+7x9+...+17x19 =4(1^2+2^2+...n^2)-n =4*n(n+1)(2n+1)/6-n; n=10,1x3+3x5+5x7+7x9+...+17x19=1530
c)
\(C=\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+...+\frac{1}{19.21}\)
\(=\frac{1}{2}.\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{19}-\frac{1}{21}\right)\)
\(=\frac{1}{2}.\left(1-\frac{1}{21}\right)\)
\(=\frac{1}{2}.\frac{20}{21}\)
\(=\frac{10}{21}\)
\(A\)= \(\frac{1}{3.4}+\frac{1}{4.5}+..+\frac{1}{49.50}=\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{49}-\frac{1}{50}=\)\(\frac{1}{3}-\frac{1}{50}=\frac{50}{150}-\frac{3}{150}=\frac{47}{150}\)
3/2 . x + ( 5/3 - 3/2) : 2/3 = 5/3
3/2.x + 1/6 : 2/3 = 5/3
3/2.x + 1/4 = 5/3
3/2.x = 5/3 - 1/4
3/2.x=17/12
x= 17/12 : 3/2
x= 17/18
Vậy...
Bài 2:
4/5x7 + 4/7x9 + 4/9x11 +...+4/17x19
= 2(2/5.7 + 2/7.9 + 2/9.11+...+ 2/17/19)
= 2( 1/5 - 1/7 + 1/7 -1/9 + 1/9 -1/11 +...+ 1/17 - 1/19)
= 2( 1/5- 1/19)
= 2 . 14/95
= 28/95
Trả lời:
Bài 1
\(\frac{3}{2}\times x+\left(\frac{5}{3}-\frac{3}{2}\right)\div\frac{2}{3}=\frac{5}{3}\)
\(\Leftrightarrow\frac{3}{2}\times x+\frac{1}{6}\div\frac{2}{3}=\frac{5}{3}\)
\(\Leftrightarrow\frac{3}{2}\times x+\frac{1}{6}\times\frac{3}{2}=\frac{5}{3}\)
\(\Leftrightarrow\frac{3}{2}\times x+\frac{1}{4}=\frac{5}{3}\)
\(\Leftrightarrow\frac{1}{6}\times x=\frac{17}{12}\)
\(\Leftrightarrow x=\frac{17}{2}\)
Vậy \(x=\frac{17}{2}\)
\(\left(\frac{1}{1.3}+\frac{1}{3.5}+\frac{1}{5.7}+\frac{1}{7.9}+\frac{1}{9.11}\right)y=\frac{2}{3}\)
=> \(\frac{1}{2}\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\right)y=\frac{2}{3}\)
=> \(\frac{1}{2}\left(1-\frac{1}{11}\right)y=\frac{2}{3}\)
=> \(\frac{1}{2}.\frac{10}{11}y=\frac{2}{3}\)
=> \(\frac{5}{11}y=\frac{2}{3}\)
=>y = \(\frac{2}{3}:\frac{5}{11}\)
=> y = \(\frac{22}{15}\)
cho mk cái lời giải thích chỗ nhân 1/2 ý mk ko hiểu mong bn thông cảm
Giải:
\(\left(\dfrac{1}{1.3}+\dfrac{1}{3.5}+\dfrac{1}{5.7}+\dfrac{1}{7.9}+\dfrac{1}{9.11}\right)y=-\dfrac{2}{3}\)
\(\Leftrightarrow\dfrac{1}{1.3}+\dfrac{1}{3.5}+\dfrac{1}{5.7}+\dfrac{1}{7.9}+\dfrac{1}{9.11}=-\dfrac{2}{3y}\)
\(\Leftrightarrow\dfrac{1}{2}\left(\dfrac{1}{1}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{11}\right)=-\dfrac{2}{3y}\)
\(\Leftrightarrow\dfrac{1}{2}\left(\dfrac{1}{1}-\dfrac{1}{11}\right)=-\dfrac{2}{3y}\)
\(\Leftrightarrow\dfrac{1}{2}.\dfrac{10}{11}=-\dfrac{2}{3y}\)
\(\Leftrightarrow\dfrac{5}{11}=-\dfrac{2}{3y}\)
\(\Leftrightarrow15y=-22\)
\(\Leftrightarrow y=-\dfrac{22}{15}\)
Vậy ...
quá dễ :
A=3/3x5+3/5x7+3/7x9+...+3/97x99
A=3/2.(1/3-1/5+1/5-1/3+...+1/97-1/99)
A=3/2.(1/3-1/99)
A=3/2.32/99
A= 16/33
\(2.\left(\frac{2}{1.3}+\frac{2}{3.5}+\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}\right).y=\frac{2}{3}\)
\(2\left(\frac{1}{1}-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{9}-\frac{1}{11}\right).y=\frac{2}{3}\)
\(2.\left(\frac{1}{1}-\frac{1}{11}\right).y=\frac{2}{3}\)
\(2.\frac{10}{11}.y=\frac{2}{3}\)
\(\frac{20}{11}.y=\frac{2}{3}\)
\(\Rightarrow y=\frac{11}{30}\)
Study well
11 21
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