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a. 3^x=1-x^2
x=0 la nghiem
x>=1; VT>=3 VP<=0 vo nghiem
b. (de bai thieu n khac 0 vi neu n=0 dung voi moi x)
3x-14=1=> x=5
c.(5^2x5^x+1)=5^4
5^x+1=5^2=> x=1
/2.x-3/=x-1 \(\Leftrightarrow\orbr{\begin{cases}2x-3=x-1\\2x-3=-(x-1)\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}2x-3-x=-1\\2x-3=-x+1\end{cases}}\Leftrightarrow\orbr{\begin{cases}x(2-1)=2\\2x+x=4\end{cases}\Leftrightarrow\orbr{\begin{cases}x=2\\3x=4\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=2\\x=\frac{4}{3}\end{cases}}}\)
\(∘backwin\)
\(a ) ( x + 1 ) + ( x + 2 ) + ( x + 3 ) + ... + ( x + 100 ) = 5750\)
\( ( x + x + x + ... + x ) + ( 1 + 2 + 3 + ... + 100 ) = 5750 \)
\( 100 x + ( 1 + 100 ) ×100 : 2 = 5750\)
\(100 x + 5050 = 5750\)
\( 100 x = 5750 − 5050\)
\(100 x = 700\)
\(x = 700 : 100\)
\(x = 7\)
\(b,\) \(B=\)\(\dfrac{1}{2^2}+\dfrac{1}{3^2}+\dfrac{1}{4^2}+...+\dfrac{1}{2021^2}< \dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{2020}+2021\)
\( B < 1 -\)\(\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{2020}-\dfrac{1}{2021}\)
\(B<1-\)\(\dfrac{1}{2021}\)
\(B<\)\(\dfrac{2020}{2021}\)
\(\dfrac{2020}{2021}< 1\)
\(B<1\)
a) (x+1) +(x+2 ) + ...+(x+100)=5750
= 100x + (1+2+3+...+100) = 5750
=100x + 5050 = 5750
--> 100x = 5750-5050=700
--> x=7
a) (3^x-15)^7=0
=) 3x-15=0
=) 3x=15
=) x=5
b) 4^2.x-6=1
4^2.x-6= 4^0 ( vì số nào mũ không cũng bằng 1)
2x-6=0
2x=6
x=3
\(\dfrac{x+3}{15}=\dfrac{1}{3}\left(1\right)\\ \Leftrightarrow x+3=\dfrac{1}{3}\cdot15\\ \Leftrightarrow x+3=5\\ \Rightarrow x=5-3\\ \Rightarrow x=2\)
Vậy tập nghiệm phương trình (1) là \(\left\{2\right\}\)
\(35-3^{x+1}=8\)
\(\Rightarrow3^{x+1}=35-8=27\)
Mà \(27=3^3\)
\(\Rightarrow x+1=3\Rightarrow x=3-1=2\)
Vậy \(x=2\)
\(a.35-3^{x+1}=8\)
\(3^x.3^1=35-8\)
\(3^x.3^1=27\)
\(3^x.3^1=3^3\)
\(3^x=3^3:3^1\)
\(3^x=3^{3-1}\)
\(3^x=3^2\)
\(\Rightarrow x=2\)
\(b.3.2^{x-1}+5=29\)
\(3.2^x:2^1=29-5\)
\(3.2^x:2^1=24\)
\(2^x:2^1=24:3\)
\(2^x:2^1=8\)
\(2^x:2^1=2^3\)
\(2^x=2^3.2^1\)
\(2^x=2^{3+1}\)
\(2^x=2^4\)
\(\Rightarrow x=4\)
\(c.9:3^x+15=18\)
\(3^2:3^x+15=18-15\)
\(3^2:3^x=3\)
\(3^x=3^2:3\)
\(3^x=3^{2-1}\)
\(3^x=3^1\)
\(\Rightarrow x=1\)
Chúc bạn học tốt!
a , 3x - 4 = 57 : 56
3x - 4 = 57-6
3x -4 = 5
3x = 9
3x = 32
suy ra x = 2
Vậy x =2
b , 3x-1 = 27
3x-1 = 33
suy ra x - 1 =3 suy ra x = 3-1 =2
Vậy x =2
c , (x-1)3 = 4(x-1)
( x - 1)3 : ( x-1 ) = 4
(x-1)3-1 = 4
(x-1)2 = 22
suy ra x-1 =2 suy ra x = 2+1 =3
Vậy x =3
d , 5x . 5x-2 = 130
5x . 5x : 52 = 130
52x = 130 x 25
52s = 3250
suy ra x thuộc rỗng
Vậy x thuộc rỗng
a) 3^x -4 =5^7 : 5^6
3^x -4 =5
3^x=9
x=2
b ) 3^x-1=26
3^x=27
x=3
\(\dfrac{11}{8}-\dfrac{3}{8}\cdot x=\dfrac{1}{8}\)
\(\dfrac{3}{8}\cdot x=\dfrac{11}{8}-\dfrac{1}{8}\)
\(\dfrac{3}{8}\cdot x=\dfrac{5}{4}\)
\(x=\dfrac{5}{4}:\dfrac{3}{8}\)
\(x=\dfrac{10}{3}\)
` 11/8 - 3/8 . x = 1/8 <=> 2/8 . x = 11/8 - 1/8 <=> 2/8x = 10/8 <=> x = 10/8 : 2/8 <=> x = 5 `
\(=>x\left(\dfrac{1}{2}+\dfrac{2}{3}\right)=\dfrac{10}{3}+1=\dfrac{13}{3}\)
\(=>x=\dfrac{13}{3}:\left(\dfrac{1}{2}+\dfrac{2}{3}\right)=\dfrac{13}{3}:\dfrac{7}{6}=\dfrac{26}{7}\)
5/6x - 1 = 10/3
5/6x = 10/3 + 1 = 13/3
X = 13/3 : 5/6 = 26/5