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a) \(\frac{x}{4}=\frac{x+1}{16}\Leftrightarrow16x=4x+4\Leftrightarrow x=\frac{1}{3}\)
b) \(\frac{x-7}{12}=\frac{2x-3}{16}\Leftrightarrow4x-28=6x-9\Leftrightarrow x=-\frac{19}{2}\)
a,\(\frac{x}{4}=\frac{x+1}{16}\Leftrightarrow4x+4=16x\Leftrightarrow12x=4\Leftrightarrow x=\frac{1}{3}\)
b,\(\frac{x-7}{12}=\frac{2x-3}{16}\Leftrightarrow16x-112=24x-36\Leftrightarrow8x=-76\Leftrightarrow x=\frac{-19}{2}\)
a) \(6x+15\times8=12\times\left(19-x\right)\)
\(6x+120=228-12x\)
\(6x+120-228+12x=0\)
\(18x-108=0\)
\(18x=108\)
\(x=6\)
b) \(160-\left(35\div x+3\right)\times15=15\)
\(160-\left(35\div x+3\right)=1\)
\(35\div x+3=159\)
\(35\div x=156\)
\(x=\dfrac{35}{156}\)
c) \(2x-\left(1309\div11-19\right)-2=0\)
\(2x-1309\div11-19=2\)
\(2x-119-19=2\)
\(2x-119=21\)
\(2x=140\)
\(x=70\)
d) \(\left(x-7\right)\times\left(2x-16\right)=0\)
\(x-7=0;2x-16=0\)
\(x=7;2x=16\)
\(x=7;x=8\)
I don't now
mik ko biết
sorry
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a) \(1+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\)
\(=\frac{16}{16}+\frac{4}{16}+\frac{2}{16}+\frac{1}{16}\)
\(=\frac{23}{16}\)
b) \(2-\frac{1}{8}-\frac{1}{12}-\frac{1}{16}\)
\(=\frac{96}{48}-\frac{6}{48}-\frac{4}{48}-\frac{3}{48}\)
\(=\frac{83}{48}\)
c) \(\frac{4}{99}\cdot\frac{18}{5}\div\frac{12}{11}+\frac{3}{5}\)
\(=\frac{4\cdot18\cdot11}{99\cdot5\cdot12}+\frac{3}{5}\)
\(=\frac{4\cdot9\cdot2\cdot11}{9\cdot11\cdot5\cdot4\cdot3}+\frac{3\cdot3}{3\cdot5}\)
\(=\frac{2}{15}+\frac{9}{15}=\frac{11}{15}\)
d) \(\left(1-\frac{3}{4}\right)\left(1+\frac{1}{3}\right)\div\left(1-\frac{1}{3}\right)\)
\(=\frac{1}{4}\cdot\frac{4}{3}\div\frac{2}{3}\)
\(=\frac{1\cdot4\cdot3}{4\cdot3\cdot2}=\frac{1}{2}\)