Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a) \(x+\frac{1}{2}=\frac{3}{4}\Rightarrow x=\frac{3}{4}-\frac{1}{2}\)\(\Rightarrow x=\frac{1}{4}\)
b)\(\frac{4}{5}\cdot x=\frac{4}{7}\Rightarrow x=\frac{4}{7}:\frac{4}{5}\)\(\Rightarrow x=\frac{5}{7}\)
c) \(8x=7,8x+25\Rightarrow8x-7,8x=25\)\(\Rightarrow0,2x=25\Rightarrow x=\frac{25}{0,2}\Rightarrow x=125\)
x+1/2=3/4
x=3/4-1/2
x=6/8--4/8
x=2/8=1/4
4/5.x=4/7
x=4/7:4/5
x=4/7.5/4
x=5/7
a, ( 1+x )^3 = (2x)^3
b, ( x-1 )^2=16
c, (x+1)^2=25
d, 4x^3+15=47
e,(2x-1)^5=x^5
Mn giải nhanh giúp mk vs
a,\(\left(1+x\right)^3=\left(2x\right)^3\)
=>\(1+x=2x\)
=>\(x-2x=-1\)
=>\(-x=-1\)
=>\(x=1\)
vậy \(x=1\)
b,\(\left(x-1\right)^2=16\)
=>\(\left(x-1\right)^2=4^2\)
=>\(x-1=4\)
=>\(x=4+1\)
=>\(x=5\)
Vậy\(x=5\)
c,\(\left(x+1\right)^2=25\)
=>\(\left(x+1\right)^2=5^2\)
=>\(x+1=5\)
=>\(x=5-1\)
=>\(x=4\)
Vậy \(x=4\)
d,\(4x^3+15=47\)
=>\(4x^3=47-15\)
=>\(4x^3=32\)
=>\(x^3=32:4\)
=>\(x^3=8\)
=>\(x^3=2^3\)
=>\(x=2\)
Vậy\(x=2\)
e,\(\left(2x-1\right)^5=x^5\)
=>\(2x-1=x\)
=>\(2x-x=1\)
=>\(x=1\)
Vậy\(x=1\)
ĐÚNG K MÌNH NHA
a. x+1/2=3/4
x =3/4 - 1/2
x = 1/4
b. 4/5.x=4/7
x =4/7 : 4/5
x = 4/7 . 5/4
x = 5/7
c. 8x=7,8+25
8x=32,8
x= 32,8 : 8
x= 4,1
a) x=\(\frac{3}{4}-\frac{1}{2}\)
=\(\frac{1}{4}\)
b)x\(=\frac{4}{7}:\frac{4}{5}\)
x\(=\frac{4}{7}.\frac{5}{4}\)
x\(=\frac{5}{7}\)
c)8x= 32,8
x=4,1
3 X +1 -32=2.32
3 X +1 = 2.32 + 32
3 X +1 = 2.32 + 32 .1
3 X +1 = 32 . ( 2+1)
3 X +1 = 32 .31
3 X +1 = 33
=> x+1= 3
x= 3+1
x= 4
1. 6/14+3/x=y/7
3/x= y/7-6/14
3/x=2y-6/14
=> 3/x= y-3/7
=>.21=(y-3)x=7x3=3x7=-7x(-3)=-3x(-7)
=> Lập bảng
.....tự giải nốt
\(x^3=x^2\)
\(\Leftrightarrow x^3-x^2=0\)
\(\Leftrightarrow x^2\left(x-1\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x^2=0\\x-1=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=0\\x=1\end{cases}}}\)
Vậy x = 0 hoặc x = 1
1/2 - (2/3x - 1/3) = 2/3
=> 1/2 - 2/3x + 1/3 = 2/3
=> 5/6 - 2/3x = 2/3
=> 2/3x = 5/6 - 2/3
=> 2/3x = 1/6
=> x = 1/6 : 2/3
=> x = 1/4
8x = 7,8x + 25
=> 8x - 7,8x = 25
=> 0,2x = 25
=> x = 25 : 0,2
=> x = 125
\(\frac{1}{2}-\left(\frac{2}{3}x-\frac{1}{3}\right)=\frac{2}{3}\)
\(\frac{1}{2}-\frac{2}{3}x+\frac{1}{3}=\frac{2}{3}\)
\(-\frac{2}{3}x=-\frac{1}{6}\)
\(x=\frac{1}{4}\)
\(8x=7,8x+25\)
\(02,x=25\)
\(x=125\)
=.= hk tốt!!