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a: \(=\dfrac{2^6\cdot3^3}{3^{-4}\cdot2^6}=\dfrac{3^3}{3^{-4}}=3^7\)
c: \(=5^4\cdot5^3\cdot\left(\dfrac{5}{2}\right)^{-5}\cdot\dfrac{4}{100}\)
\(=5^7\cdot\left(\dfrac{2}{5}\right)^5\cdot\left(\dfrac{1}{5}\right)^2\)
\(=5^2\cdot\left(\dfrac{1}{5}\right)^2\cdot5^5\cdot\left(\dfrac{2}{5}\right)^5=2^5\)
Bài làm:
\(64^3.4^5.16^2=2^{18}.2^{10}.2^8=2^{36}\)
\(25^{20}.125^4=5^{40}.5^{12}=5^{52}\)
\(x^7.x^4.x^3=x^{14}\)
64^3.4^5.16^2=2^18.2^10..2^8=36
25^20.125^4=5^40.5^12=5^52
x^7.x^4.x^3=x^14
a) \(x^5\cdot x^3\cdot x^2=x^{5+3+2}=x^{10}\)
b) \(\left(0,2\right)^8:0,04=\left(0,2\right)^8:\left(0,2\right)^2=\left(0,2\right)^{8-2}=\left(0,2\right)^6\)
CHÚC BẠN HỌC TỐT!!!!!!!!!!!
a)x^5.x^3.x^2=x^5+3+2=x^10
b)0,2^8:0,04=0,2^8:0,2^2=0,2^8-2=0,2^6
a) 4x32:(\(^{2^3}\)x\(\frac{1}{16}\))=\(^{2^2}\)x\(2^5\):[\(2^3\)x\(\left(\frac{1}{2}\right)^4\)] =\(2^7\):(\(2^3\)x\(2^{-4}\))=\(2^7\):\(2^{-1}\)=\(2^{7-\left(-1\right)}\)=\(2^8\)
b)\(3^4\)x\(3^5\):\(\frac{1}{27}\)=\(3^9\):\(\left(\frac{1}{3}\right)^3\)=\(3^9\):\(3^{-3}\)=\(3^{9-\left(-3\right)}\)=\(3^{12}\)
a)\(4.32:\left(2^3.\frac{1}{16}\right)=2^2.2^5:\left(2^3.\frac{1}{2^4}\right)=2^7:\frac{1}{2}=2^7.2=2^8\)
b)\(3^4.3^5:\frac{1}{27}=3^9:\frac{1}{3^3}=3^9.3^3=3^{12}\)