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22 tháng 3 2018
\(tuA=1003+1007+\dfrac{2010}{113}+\dfrac{2010}{117}-\dfrac{2010}{119}=2010\left(1+\dfrac{1}{113}+\dfrac{1}{117}-\dfrac{1}{119}\right)\)\(mauA=1003+1008+\dfrac{2011}{113}+\dfrac{2011}{117}-\dfrac{2011}{119}=2011\left(1+\dfrac{1}{113}+\dfrac{1}{117}-\dfrac{1}{119}\right)\)có \(\left(1+\dfrac{1}{113}+\dfrac{1}{117}-\dfrac{1}{119}\right)\ne0=>A=\dfrac{2010}{2011}\)
TN
2
D
10 tháng 1 2023
`(2345-45)+2345`
`=2300+2345`
`=4645`
__________________
`(-2010)-(119-2010)`
`=-2010-119+2010`
`=(-2010+2010)-119`
`=0-119`
`=-119`
10 tháng 1 2023
(2345−45)+2345
=2300+2345=2300+2345
=4645=4645
(−2010)−(119−2010)
=-2010-119+2010=−2010−119+2010
=(-2010+2010)-119=(−2010+2010)−119
=0-119=0−119
=-119=−119
KN
30 tháng 4 2019
Đề ???
\(A=\frac{1003+1007+\frac{2010}{113}+\frac{2010}{117}-\frac{1003}{119}-\frac{1007}{119}}{1003+1008+\frac{2011}{113}+\frac{2011}{117}-\frac{1003}{119}-\frac{1008}{119}}\)
\(=\frac{2010+\frac{2010}{113}+\frac{2010}{117}-\frac{2010}{119}}{2011+\frac{2011}{113}+\frac{2011}{117}-\frac{2011}{119}}\)
\(=\frac{2010.\left(1+\frac{1}{113}+\frac{1}{117}-\frac{1}{119}\right)}{2011.\left(1+\frac{1}{113}+\frac{1}{117}-\frac{1}{119}\right)}\)
\(=\frac{2010}{2011}\)
30 tháng 4 2019
\(A=\frac{1003+1007+\frac{2010}{113}+\frac{2010}{117}-\frac{100}{119}-\frac{1007}{119}}{1003+1008+\frac{2011}{113}+\frac{2011}{117}-\frac{1003}{119}-\frac{1008}{119}}\)
\(A=\frac{1003+1008+\frac{2011}{113}+\frac{2011}{117}-\frac{1003}{119}-\frac{1008}{119}}{1003+1008+\frac{2011}{113}+\frac{2011}{117}-\frac{1003}{119}-\frac{1008}{119}}\)+ \(\frac{1+\frac{1}{113}+\frac{1}{117}-\frac{903}{119}-\frac{1}{119}}{1003+1008+\frac{2011}{113}+\frac{2011}{117}-\frac{1003}{119}-\frac{1008}{119}}\)
\(A=1+\frac{1+\frac{1}{113}+\frac{1}{117}-\frac{904}{119}}{2011+\frac{2011}{113}+\frac{2011}{117}-\frac{2011}{119}}\)
\(A=\frac{1+\frac{1}{113}+\frac{1}{117}-\frac{1}{119}-\frac{90.}{119}}{2011+2011.\left(\frac{1}{113}+\frac{1}{117}-\frac{1}{119}\right)}\)
\(A=\frac{\frac{90}{119}}{2010+2011}\)
\(A=\frac{\frac{90}{119}}{4021}\)
PT
23 tháng 7 2017
Ta có:
\(A=\dfrac{1003+1007+\dfrac{2010}{113}+\dfrac{2010}{117}-\dfrac{1003}{119}-\dfrac{1007}{119}}{1003+1008+\dfrac{2011}{113}+\dfrac{2011}{117}-\dfrac{1003}{119}-\dfrac{1007}{119}}\)
\(A=\dfrac{2010+\dfrac{2010}{113}+\dfrac{2010}{117}-\dfrac{2010}{119}}{2011+\dfrac{2011}{113}+\dfrac{2011}{117}-\dfrac{2011}{119}}\)
\(A=\dfrac{2010.\left(\dfrac{1}{1}+\dfrac{1}{113}+\dfrac{1}{117}-\dfrac{1}{119}\right)}{2013.\left(\dfrac{1}{1}+\dfrac{1}{113}+\dfrac{1}{117}+\dfrac{1}{119}\right)}\)
\(\Rightarrow A=\dfrac{2010}{2013}\)
- 4139
TL
\(\left(-2010\right)-\left(119-2010\right)\)
\(=\)\(\left(-2010\right)-119+2010\)
\(=\)\(\left(-2010+2010\right)-119\)
\(=\)\(0-119\)
\(=\)\(-119\)