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29 tháng 11 2017

\(\dfrac{-12}{13}x-5=6\dfrac1{13} \\\Leftrightarrow \dfrac{-12}{13}x=6\dfrac1{13}+5 \\\Leftrightarrow \dfrac{-12}{13}x=\dfrac{144}{13} \\\Leftrightarrow x=\dfrac{144}{13}:\dfrac{-12}{13} \\\Leftrightarrow x=-12\)

29 tháng 11 2017

\(\dfrac{-12}{13}x-5=6\dfrac{1}{13}\)

\(\Leftrightarrow\dfrac{-12}{13}x=6\dfrac{1}{13}+5\)

\(\Leftrightarrow\dfrac{-12}{13}x=\dfrac{79}{13}+\dfrac{65}{13}\)

\(\Leftrightarrow\dfrac{-12}{13}x=\dfrac{79+65}{13}\)

\(\Leftrightarrow\dfrac{-12}{13}x=\dfrac{144}{13}\)

\(\Leftrightarrow x=\dfrac{144}{13}:\dfrac{-12}{13}\)

\(\Leftrightarrow x=\dfrac{144}{13}.\dfrac{13}{-12}\)

\(\Leftrightarrow x=\dfrac{1872}{156}\)

\(\Leftrightarrow x=12\)

Vậy \(x=12\)

26 tháng 12 2018

\(\dfrac{-12}{13}\)X-5=6\(\dfrac{1}{13}\)

\(\dfrac{-12}{13}\)X-5=\(\dfrac{79}{13}\)

X-5=\(\dfrac{79}{13}\): \(\dfrac{-12}{13}\)

X-5=\(\dfrac{79}{13}\)x\(\dfrac{-13}{12}\)

X-5=\(\dfrac{-1027}{156}\)

X-5=\(\dfrac{-79}{12}\)

X =\(\dfrac{-79}{12}\)+5

X =\(\dfrac{-79}{12}\)+\(\dfrac{60}{12}\)

X = \(\dfrac{-19}{12}\)

X = -1\(\dfrac{7}{12}\)

Mình giải rõ ràng vì sợ bạn không hiểu nên hơi dài bạn thông cảm nha.

26 tháng 12 2018

= -12/13x-5 = 79/13

=-12/13x=79/13+5

=-12/13x=144/13

x= 144/13 : -12/13

x= 144/13 . ( -13/12 )

x= -12

Vậy x=-12

18 tháng 6 2018

1)

\(\dfrac{0,375-0,3+\dfrac{3}{11}+\dfrac{3}{12}}{-0,625+0,5-\dfrac{5}{11}-\dfrac{5}{12}}+\dfrac{1,5+1-0,75}{2,5+\dfrac{5}{3}-1,25}\)
\(=\dfrac{\dfrac{3}{8}-\dfrac{3}{10}+\dfrac{3}{11}+\dfrac{3}{12}}{-\dfrac{5}{8}+\dfrac{5}{10}-\dfrac{5}{11}-\dfrac{6}{12}}+\dfrac{\dfrac{3}{2}+\dfrac{3}{3}-\dfrac{3}{4}}{\dfrac{5}{2}+\dfrac{5}{3}-\dfrac{5}{4}}\)
\(=\dfrac{3\left(\dfrac{1}{8}-\dfrac{1}{10}+\dfrac{1}{11}+\dfrac{1}{12}\right)}{-5\left(\dfrac{1}{8}-\dfrac{1}{10}+\dfrac{1}{11}+\dfrac{1}{12}\right)}+\dfrac{3\left(\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{4}\right)}{5\left(\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{4}\right)}\)
\(=\dfrac{3}{-5}+\dfrac{3}{5}\)
\(=-\dfrac{3}{5}+\dfrac{3}{5}\)
\(=0\)

22 tháng 7 2017

1. Tính:

a. \(\dfrac{\text{−1 }}{\text{4 }}+\dfrac{\text{5 }}{\text{6 }}=\dfrac{-3}{12}+\dfrac{10}{12}=\dfrac{7}{12}\)

b. \(\dfrac{\text{5 }}{\text{12 }}+\dfrac{\text{-7 }}{8}=\dfrac{10}{24}+\dfrac{-21}{24}=\dfrac{-11}{24}\)

c. \(\dfrac{-7}{6}+\dfrac{-3}{10}=\dfrac{-35}{30}+\dfrac{-9}{30}=\dfrac{-44}{30}=\dfrac{-22}{15}\)

d.\(\dfrac{-3}{7}+\dfrac{5}{6}=\dfrac{-18}{42}+\dfrac{35}{42}=\dfrac{17}{42}\)

2. Tính :

a. \(\dfrac{2}{14}-\dfrac{5}{2}=\dfrac{2}{14}-\dfrac{35}{14}=\dfrac{-33}{14}\)

b.\(\dfrac{-13}{12}-\dfrac{5}{18}=\dfrac{-39}{36}-\dfrac{10}{36}=\dfrac{49}{36}\)

c.\(\dfrac{-2}{5}-\dfrac{-3}{11}=\dfrac{-2}{5}+\dfrac{3}{11}=\dfrac{-22}{55}+\dfrac{15}{55}=\dfrac{-7}{55}\)

d. \(0,6--1\dfrac{2}{3}=\dfrac{6}{10}--\dfrac{5}{3}=\dfrac{3}{5}+\dfrac{5}{3}=\dfrac{9}{15}+\dfrac{25}{15}=\dfrac{34}{15}\)

3. Tính :

a.\(\dfrac{-1}{39}+\dfrac{-1}{52}=\dfrac{-4}{156}+\dfrac{-3}{156}=\dfrac{-7}{156}\)

b.\(\dfrac{-6}{9}-\dfrac{12}{16}=\dfrac{2}{3}-\dfrac{3}{4}=\dfrac{8}{12}-\dfrac{9}{12}=\dfrac{-17}{12}\)

c. \(\dfrac{-3}{7}-\dfrac{-2}{11}=\dfrac{-3}{7}+\dfrac{2}{11}=\dfrac{-33}{77}+\dfrac{14}{77}=\dfrac{-19}{77}\)

d.\(\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+...\dfrac{1}{8.9}+\dfrac{1}{9.10}\)

\(=\dfrac{1}{1}+\dfrac{1}{10}\)

\(=\dfrac{10}{10}-\dfrac{1}{10}\)

= \(\dfrac{9}{10}\)

Chế Kazuto Kirikaya thử tham khảo thử đi !!!

23 tháng 7 2017

Mấy câu trên kia dễ rồi mình chữa mình câu \(c\) bài \(3\) thôi nhé Kazuto Kirikaya

d) \(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+...+\dfrac{1}{9\cdot10}\)

\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{9}-\dfrac{1}{10}\)

\(=1-\dfrac{1}{10}\)

\(=\dfrac{9}{10}\)

5 tháng 7 2017

b, \(-x-2=\dfrac{5}{4}\Rightarrow-x=\dfrac{13}{4}\Rightarrow x=-\dfrac{13}{4}\)

c, \(\dfrac{4}{3}-\left(x-\dfrac{1}{5}\right)=\left|-\dfrac{3}{10}+\dfrac{1}{2}\right|-\dfrac{1}{6}\)

\(\Rightarrow\dfrac{4}{3}-x+\dfrac{1}{5}=\left|\dfrac{1}{5}\right|-\dfrac{1}{6}\)

\(\Rightarrow-x=\dfrac{1}{5}-\dfrac{1}{6}-\dfrac{4}{3}-\dfrac{1}{5}\)

\(\Rightarrow-x=-\dfrac{3}{2}\Rightarrow x=\dfrac{3}{2}\)

d, \(\dfrac{1}{3}-\left(\dfrac{2}{3}-x+\dfrac{5}{4}\right)=\dfrac{7}{12}-\left(\dfrac{5}{2}-\dfrac{13}{6}\right)\)

\(\Rightarrow\dfrac{1}{3}-\dfrac{2}{3}+x-\dfrac{5}{4}=\dfrac{7}{12}-\dfrac{5}{2}+\dfrac{13}{6}\)

\(\Rightarrow x=\dfrac{7}{12}-\dfrac{5}{2}+\dfrac{13}{6}-\dfrac{1}{3}+\dfrac{2}{3}+\dfrac{5}{4}\)

\(\Rightarrow x=\dfrac{11}{6}\)

Chúc bạn học tốt!!!

20 tháng 12 2017

a,\(\dfrac{5}{6}+\left(-\dfrac{1}{2}\right)+\dfrac{3}{4}\)

\(=\dfrac{10}{12}+\left(-\dfrac{6}{12}\right)+\dfrac{9}{12}\)

\(=\dfrac{10-6+9}{12}=\dfrac{13}{12}\)

b,\(\left(0,75-\dfrac{1}{3}\right):\dfrac{7}{15}\)

\(=\left(\dfrac{3}{4}-\dfrac{1}{3}\right):\dfrac{7}{15}\)

\(=\left(\dfrac{9}{12}-\dfrac{4}{12}\right):\dfrac{7}{15}\)

\(=\dfrac{5}{12}:\dfrac{7}{15}\)

\(=\dfrac{25}{28}\)

c,\(\dfrac{7}{12}-\dfrac{3}{4}.\dfrac{5}{6}\)

\(=\dfrac{7}{12}-\dfrac{5}{8}\)

\(=\dfrac{14}{24}-\dfrac{15}{24}\)

\(=-\dfrac{1}{24}\)

d,\(\left(2\dfrac{1}{3}+1\dfrac{3}{4}\right).\dfrac{12}{13}\)

\(=\left(\dfrac{7}{3}+\dfrac{7}{4}\right).\dfrac{12}{13}\)

\(=\left(\dfrac{28}{12}+\dfrac{21}{12}\right).\dfrac{12}{13}\)

\(=\dfrac{49}{12}.\dfrac{12}{13}\)

\(=\dfrac{49}{13}\)

20 tháng 12 2017

a) \(\dfrac{5}{6}+\left(\dfrac{-1}{2}\right)+\dfrac{3}{4}\)

\(=\dfrac{10}{12}-\dfrac{6}{12}+\dfrac{9}{12}\)

\(=\dfrac{13}{12}\)

b) \(\left(0,75-\dfrac{1}{3}\right):\dfrac{7}{15}\)

\(=\left(\dfrac{3}{4}-\dfrac{1}{3}\right).\dfrac{15}{7}\)

\(=\left(\dfrac{9}{12}-\dfrac{4}{12}\right).\dfrac{15}{7}\)

\(=\dfrac{5}{12}.\dfrac{15}{7}\)

\(=\dfrac{25}{28}\)

c) \(\dfrac{7}{12}-\dfrac{3}{4}.\dfrac{5}{6}\)

\(=\dfrac{7}{12}-\dfrac{5}{8}\)

\(=\dfrac{14}{24}-\dfrac{15}{24}\)

\(=\dfrac{-1}{24}\)

d) \(\left(2\dfrac{1}{3}+1\dfrac{3}{4}\right).\dfrac{12}{13}\)

\(=\left(\dfrac{7}{3}+\dfrac{7}{4}\right).\dfrac{12}{13}\)

\(=\left(\dfrac{28}{12}+\dfrac{21}{12}\right).\dfrac{12}{13}\)

\(=\dfrac{49}{12}.\dfrac{12}{13}\)

\(=\dfrac{49}{13}\)

21 tháng 10 2017

a. \(\dfrac{11}{24}-\dfrac{5}{41}+\dfrac{13}{24}+0,5-\dfrac{36}{41}\)

\(=\left(\dfrac{11}{24}+\dfrac{13}{24}\right)+\left(\dfrac{-5}{41}-\dfrac{36}{41}\right)+0,5\)

\(=1+\left(-1\right)+0,5\)

\(=0,5\)

b. \(-12:\left(\dfrac{3}{4}-\dfrac{5}{6}\right)^2\)

\(=-12:\left(\dfrac{-1}{12}\right)^2\)

\(=-12:\dfrac{1}{144}\)

\(=-1728\)

c. \(\dfrac{7}{23}.\left[\left(-\dfrac{8}{6}\right)-\dfrac{45}{18}\right]\)

\(=\dfrac{7}{23}.\dfrac{-23}{6}\)

\(=\dfrac{-7}{6}\)

d. \(23\dfrac{1}{4}.\dfrac{7}{5}-13\dfrac{1}{4}:\dfrac{5}{7}\)

\(=23\dfrac{1}{4}.\dfrac{7}{5}-13\dfrac{1}{4}.\dfrac{7}{5}\)

\(=\left(23\dfrac{1}{4}-13\dfrac{1}{4}\right).\dfrac{7}{5}\)

\(=10.\dfrac{7}{5}\)

\(=14\)

e. \(\left(1+\dfrac{2}{3}-\dfrac{1}{4}\right).\left(0,8-\dfrac{3}{4}\right)^2\)

\(=\dfrac{17}{12}.\left(\dfrac{1}{20}\right)^2\)

\(=\dfrac{17}{12}.\dfrac{1}{400}=\dfrac{17}{4800}\)

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