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\(\frac{...}{21}-\frac{2}{3}=\frac{5}{21}=>\frac{...}{21}=\frac{5}{21}+\frac{2}{3}=>\frac{...}{21}=\frac{19}{21}\)
học tốt
\(\frac{2x+15}{9}=\frac{14}{18}=\frac{7}{9}\)
\(\Rightarrow2x+15=7\)
\(\Rightarrow2x=7-15=\left(-8\right)\)
\(x=\left(-8\right):2\)
\(x=\left(-4\right)\)
Vậy x=(-4)
Ta có :
\(\frac{2x+15}{9}\)\(=\)\(\frac{14}{18}\)\(\Rightarrow\)\(\frac{2x+15}{9}\)\(=\)\(\frac{7}{9}\)
\(\Rightarrow\)2x + 15 = 7
=> 2x = 7 - 15
=> 2x = - 8
=> x = - 8 : 2 = - 4
c )
\(1+\frac{1}{1+\frac{1}{1+\frac{1}{1+\frac{1}{2}}}}=1+\frac{1}{1+\frac{1}{1+\frac{1}{\frac{3}{2}}}}=1+\frac{1}{1+\frac{1}{1+\frac{5}{3}}}=1+\frac{1}{1+\frac{1}{\frac{8}{3}}}=1+\frac{1}{\frac{11}{8}}=\frac{19}{11}\)
\(\frac{-11}{14}-\frac{-4}{...}=\frac{-3}{14}\)
\(\frac{-11}{14}+\frac{4}{...}=\frac{-3}{14}\)
\(\frac{4}{...}=\frac{-3}{14}-\frac{-11}{14}\)
\(\frac{4}{...}=\frac{-3}{14}+\frac{11}{14}\)
\(\frac{4}{...}=\frac{8}{14}\)
\(\frac{4}{...}=\frac{4}{7}\)
\(\frac{1}{...}-\frac{-2}{15}=\frac{7}{15}\)
\(\frac{1}{...}+\frac{2}{15}=\frac{7}{15}\)
\(\frac{1}{...}=\frac{7}{15}-\frac{2}{15}\)
\(\frac{1}{...}=\frac{5}{15}\)
\(\frac{1}{...}=\frac{1}{3}\)
Hok tốt !!!!!!!!!