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1) (x-2)3
2) (x-1+5x)(x-1-5x)=(6x-1)(-4x-1)
3) (6x-2x-1)(6x+2x+1)=(4x-1)(8x+1)
4) (x+3-2x+1)(x+3+2x-1) = (4-x)(3x+2)
1. \(x^3-6x^2+12x-8=\left(x-2\right)^3\)
2. \(\left(x-1\right)^2-25x^2=\left(x-1-5x\right)\left(x-1+5x\right)\)
= \(\left(-4x-1\right)\left(6x-1\right)\)
3. \(36x^2-\left(2x+1\right)^2=\left(6x-2x-1\right)\left(6x+2x+1\right)\)
= \(\left(4x-1\right)\left(8x+1\right)\)
4. \(\left(x+3\right)^2-\left(2x-1\right)^2=\left(x+3-2x+1\right)\left(x+3+2x-1\right)\)
= \(\left(4-x\right)\left(3x+2\right)\)
Chúc bạn làm bài tốt
GIẢI PT
- (4x2-3x-2)2-(3x2+5x-14)2=0
- (3x2+3x-2)2=x2(x-1)2=0
- 4x2(7/2x+1/2)2-(x2+5x-5)2=0
GIẢI HỘ MÌNH VỚI
1/ x² - 5x + 6 = 0
⇔ x² - 2x - 3x + 6 = 0
⇔ x(x - 2) - 3(x - 2) = 0
⇔ (x - 2)(x - 3) = 0
⇒S = {2 ; 3}.
1) \(x^2+5x+6=0\)
\(\Leftrightarrow x^2+2x+3x+6=0\)
\(\Leftrightarrow x\left(x+2\right)+3\left(x+2\right)=0\)
\(\Leftrightarrow\left(x+2\right)\left(x+3\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x+2=0\\x+3=0\end{array}\right.\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x=-2\\x=-3\end{array}\right.\)
2) \(2\left(x+3\right)-x^2-3x=0\)
\(\Leftrightarrow2\left(x+3\right)-x\left(x+3\right)=0\)
\(\Leftrightarrow\left(x+3\right)\left(2-x\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x+3=0\\2-x=0\end{array}\right.\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x=-3\\x=2\end{array}\right.\)
3) \(x^2+4x+3=0\)
\(\Leftrightarrow x^2+x+3x+3=0\)
\(\Leftrightarrow x\left(x+1\right)+3\left(x+1\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(x+3\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x+1=0\\x+3=0\end{array}\right.\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x=-1\\x=-3\end{array}\right.\)
4) \(2x^2-3x-5=0\)
\(\Leftrightarrow2x^2+2x-5x-5=0\)
\(\Leftrightarrow2x\left(x+1\right)-5\left(x+1\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(2x-5\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x+1=0\\2x-5=0\end{array}\right.\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x=-1\\x=\frac{5}{2}\end{array}\right.\)