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Bài 1:
uses crt;
var n,t,i,d,x:integer;
st:string;
begin
clrscr;
readln(n);
str(n,st);
d:=length(st);
t:=0;
for i:=1 to d do
begin
val(st[i],x);
t:=t+x;
end;
writeln(t);
readln;
end.
1:
uses crt;
var a,b:integer;
begin
clrscr;
write('Nhap a='); readln(a);
write('Nhap b='); readln(b);
if (a>0) and (b>0) then writeln('Cung dau');
if (a<0) and (b<0) then writeln('Cung dau');
if (a>0) and (b<0) then writeln('Khac dau');
if (a<0) and (b>0) then writeln('Khac dau');
readln;
end.
2:
uses crt;
var n,i,d,t,x,y:integer;
st:string;
begin
clrscr;;
repeat
write('Nhap n='); readln(n);
until (100<=n) and (n<=999);
str(n,st);
d:=length(st);
t:=0;
for i:=1 to d do
begin
val(st[i],x,y);
if x mod 2=1 then t:=t+x;
end;
writeln('Tong cac chu so le cua ',n,' la: ',t);
readln;
end.
Câu 1:
#include <bits/stdc++.h>
using namespace std;
long long n;
int main()
{
cin>>n;
int t=0;
while (n>0)
{
int x=n%10;
t=t+x;
n=n/10;
}
cout<<t;
return 0;
}
Mình dùng C++ nên div = /; mod = % nha bn!
#include <bits/stdc++.h>
using namespace std;
int main() {
int a, S;
cin >> a;
S=0;
while(a>0)
{
S+=a%10, a=a/10;
}
cout << S << endl;
return 0;
}
Chúc bn học tốt!
uses crt;
var n,i,t,x,y,d:integer;
st:string;
begin
clrscr;
write('Nhap n='); readln(n);
str(n,st);
d:=length(st);
t:=0;
for i:=1 to d do
begin
val(st[i],x,y);
t:=t+x;
end;
writeln('Tong cac chu so cua ',n,' la: ',t);
readln;
end.
Câu 2:
uses crt;
var a,b:array[1..100]of integer;
i,n,t,dem,j,kt,dem1:integer;
begin
clrscr;
readln(n);
for i:=1 to n do
readln(a[i]);
t:=0;
for i:=1 to n do t:=t+a[i];
writeln(t);
dem:=1;
b[1]:=a[1];
for i:=1 to n do
begin
kt:=0;
for j:=1 to dem do
if b[j]=a[i] then kt:=1;
if kt=0 then
begin
inc(dem);
b[dem]:=a[i];
end;
end;
for i:=1 to dem do
begin
dem1:=0;
for j:=1 to n do
if a[j]=b[i] then inc(dem1);
writeln(b[i],' xuat hien ',dem1,' lan');
end;
readln;
end.
uses crt;
var a,b,c,t:integer;
begin
write('nhap 3 so bat ki');readln(a,b,c);
t:=a+b+c;
write('tong la : ',t:2:3);
readln;
end.
uses crt;
var n,x,t:integer;
begin
clrscr;
readln(n);
t:=0;
while (n>0) do
begin
x:=n mod 10;
t:=t+x;
n:=n div 10;
end;
writeln(t);
readln;
end.