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25 : 0,5 x 0,2 : 0,25 x 0,5 x 0,25
= (0,5 : 0,5) x (0,25 : 0,25) x ( 25 x0,2)
= 1 x 1 x 5
= 5
a)9,18:0,2+9,18:0,25+9,18
=9,18x(0,2+0,25+1)
=13,311
b)9,18:0,2-6,18-0,2
=(9,18-6,18):0,2
=15
c)2,4:0,125+2,4:0,25-2,4:0,5
=2,4:(0,125+0,25-0,5)
=24
kink cho minh nhe
Banj có thể giải thích giúp là tại sao
2,4÷0,125 + 2,4 ÷0,25 - 2,4 ÷ 0,5
2,4÷(0,125 + 0,25 - 0,5)
= 24
(\(\dfrac{2}{3}\) + \(\dfrac{8}{9}\) + \(\dfrac{26}{27}\) + \(\dfrac{80}{81}\) + \(\dfrac{242}{243}\)) : y = 5
Đăt A = \(\dfrac{2}{3}\) + \(\dfrac{8}{9}\) + \(\dfrac{26}{27}\) + \(\dfrac{80}{81}\) + \(\dfrac{242}{243}\)
3A = 2 + \(\dfrac{8}{3}\) + \(\dfrac{26}{9}\) + \(\dfrac{80}{27}\) + \(\dfrac{242}{81}\)
3A - A = 2 + \(\dfrac{8}{3}\) + \(\dfrac{26}{9}\) + \(\dfrac{80}{27}\) + \(\dfrac{242}{81}\) - \(\dfrac{2}{3}\)-\(\dfrac{8}{9}\)-\(\dfrac{26}{27}\)-\(\dfrac{80}{81}\)-\(\dfrac{242}{243}\)
A x (3 - 1) = 2 - \(\dfrac{242}{243}\)+ (\(\dfrac{8}{3}\) - \(\dfrac{2}{3}\))+(\(\dfrac{26}{9}\) - \(\dfrac{8}{9}\))+(\(\dfrac{80}{27}\)-\(\dfrac{26}{27}\))+(\(\dfrac{242}{81}\)-\(\dfrac{80}{81}\))-\(\dfrac{242}{243}\)
A x 2 = 2 - \(\dfrac{242}{243}\) + 2 + 2 + 2 + 2
A x 2 = (2 + 2 + 2 +2 + 2) - \(\dfrac{242}{243}\)
A x 2 = 2x5 - \(\dfrac{242}{243}\)
A x 2 = 10 - \(\dfrac{242}{243}\)
A x 2 = \(\dfrac{2188}{243}\)
A = \(\dfrac{2188}{243}\) : 2
A = \(\dfrac{1094}{243}\)
\(\dfrac{1094}{243}\) : y = 5
y = \(\dfrac{1094}{243}\) : 5
y = \(\dfrac{1094}{1215}\)
13, 25 : 0. 125 + 13. 25 : 0. 25 - 13. 25 : 0. 5
= 13. 25 . 8 + 13. 25 . 4 - 13, 25 . 2
= 13, 25( 8 + 4 - 2 )
= 13, 25 . 10
= 132, 5
\(=21,5\times2+21,5\times5+21,5\times3\\ =21,5\times\left(2+5+3\right)\\ =21,5\times10\\ =215\)
21,5:0,5+21,5:0,2+21,5x3
=21,5×2+21,5×5+21,5×3
=21,5×(2+5+3)
=21,5×10
=215