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4Na+O2----->2Na2O
Na2O+H2O--->2NaOH
2NaOH dư+CO2----->Na2CO3+H2O
Na2CO3+CaCl2------>CaCO3+2NaCl
CaCO3---t0---->CaO+CO2
CaO+H2O------>Ca(OH)2
Ca(OH)2+CO2 dư----->Ca(HCO3)2
-)2Na+2H2O----->2NaOH+H2
FeO+2NaOH----->Na2O+Fe(OH)2
Na2O+CO2------->Na2CO3
nNaOH=1,2(mol)
Ta có tỉ lệ :
nNaOH/nCO2=1,6⇒ Tạo hai muối.
CO2+2NaOH⇀Na2CO3+H2O
CO2+NaOH⇀NaHCO3
ta có hệ pt
⇒2x+y=1,2
x+y=0,75
⇒x=0,45;y=0,3
mNa2CO3=n.M=0,3.84=25,2(g)
mNaHCO3=n.M=0,45.106=47,7(g)
mA=25,2+47,7=72,9(g)
b,Na2CO3+BaCl2−−>BaCO3+2NaCl
0.45--------------------->0.45mol
mBaCO3BaCO3=197.0.45=88.65g
C + O2---t*--> CO2
CO2+ CaO--->CaCO3
CaCO3----t*--->CaO+CO2
2NaOH+CO2----->Na2CO3+H2O
Na2CO3 + Ba(OH)2---->2NaOH + BaCO3
2NaOH + Al2O3----->2NaAlO2 + H2O
2Ca + O2 ----.>2CaO
CaO + H2O----->Ca(OH)2
Ca(OH)2 + CO2----->CaCO3 + H2O
CaCO3 + BaCl2----->CaCl2 + BaCO3
Chi?
4Fe+3O2---t*--->2Fe2O3
Fe2O3+ 6HCl------>2FeCl3+3H2O
FeCl3+Al(OH)3------>AlCl3 + Fe(OH)3
AlCl3+3NaOH------>Al(OH)3+3NaCl
2Al(OH)3 ----t*---->Al2O3 + 3H2O
C+CO2->CO
CO+O2->CO2
CO2+NAOH->NaHCO3
NaHCO3+NaOH->Na2CO3+H2O
Na2CO3+BaCl2-->BaCO3+NaCl
NaCl+H2O-->NaOH+H2+Cl2
3Cl2+2Fe-->2FeCl3
2FeCl3+Zn-->ZnCl2+Fe
\(C+CO_2\rightarrow2CO\)
\(2CO+O_2\rightarrow2CO_2\)
\(CO_2+NaOH\rightarrow NaHCO_3\)
\(NaHCO_3+NaOH\rightarrow H_2O+Na_2CO_3\)
\(Na_2CO_3+BaCl_2\rightarrow2NaCl+BaCO_3\)
\(2NaCl\rightarrow2Na+Cl_2\)
\(3Cl_2+2Fe\rightarrow2FeCl_3\)
\(2FeCl_3+3Mg\rightarrow2Fe+3MgCl_2\)
a.
\(H_2SO_4+CuO\rightarrow CuSO_4+H_2O\)
\(Cu\left(OH\right)_2\rightarrow CuO+H_2O\)
\(CuO+2HCl\rightarrow CuCl_2+H_2O\)
\(CuCl_2+2AgNO_3\rightarrow2AgCl+Cu\left(NO_3\right)_2\)
\(Cu\left(NO_3\right)_2+Mg\rightarrow Mg\left(NO_3\right)_2+Cu\)
b.
\(Ca+H_2O\rightarrow Ca\left(OH\right)_2+H_2\)
\(Ca\left(OH\right)_2+FeCl_2\rightarrow Fe\left(OH\right)_2+CaCl_2\)
\(CaCl_2+Na_2CO_3\rightarrow CaCO_3+2NaCl\)
\(2NaCl+2H_2O\underrightarrow{^{đpdd}}2NaOH+Cl_2+H_2\)
\(NaOH+SO_3\rightarrow NaHSO_4\)
c.
\(4Na+O_2\underrightarrow{^{to}}2Na_2O\)
\(Na_2O+2HCl\rightarrow2NaCl+H_2O\)
\(2NaCl+2H_2O\underrightarrow{^{đpdd}}2NaOH+Cl_2+H_2\)
\(2NaOH+SO_2\rightarrow Na_2SO_3+H_2O\)
\(Na_2SO_3+2HCl\rightarrow2NaCl+SO_2+H_2O\)
Đề thi học sinh giỏi Hóa
1) 4FeS2 + 11O2 --> 2Fe2O3 + 8SO2
SO2 + O2 + H2O --> H2SO4\
H2SO4 + Ba(OH)2 --> BaSO4 + 2H2O
2) CaCO3 --> CaO + CO2
CaO + H2O --> Ca(OH)2
Ca(OH)2 + ... --> CO2 ?
3) S + O2 --> SO2
SO2 + H2O --> H2SO3
H2SO3 + 2NaOH --> Na2SO3 + 2H2O
Na2SO3 + HCl --> NaCl + SO2 + H2O
SO2 + O2 --> SO3
SO3 + H2O --> H2SO4
4) S + O2 --> SO2
SO2 + O2 --> SO3
SO3 + H2O --> H2SO4
H2SO4 + CuO --> CuSO4 + H2O
5) 2Ca + O2 --> 2CaO
CaO + CO2 --> CaCO3
CaCO3 --> CaO + CO2
CaO + H2O --> Ca(OH)2
Ca(OH)2 + CO2 --> CaCO3 + H2O
6) 4Na + O2 --> 2Na2O
Na2O + H2O --> 2NaOH
2NaOH + SO2 --> Na2SO3 + H2O
Na2SO3 + O2 --> Na2SO4
\(\text{2Na+2H2O}\rightarrow\text{2NaOH+H2↑}\)
\(\text{2NaOH(đậm đặc)+CO2}\rightarrow\text{Na2CO3+H2O}\)
\(\left\{{}\begin{matrix}\text{CO2+NaOH}\rightarrow\text{NaHCO3}\\\text{H2CO3+NaOH}\rightarrow\text{NaHCO3+H2O}\end{matrix}\right.\)
\(\text{Na2CO3+Ca(OH)2}\rightarrow\text{CaCO3↓+2NaOH}\)
\(\text{CaCO3 + 2HCl → H2O + CO2 + CaCl2}\)
\(\text{CaCl2+Na2CO3}\rightarrow\text{CaCO3↓+2NaCl}\)
\(\text{CaCO3(thể rắn)+CO2+H2O}\rightarrow\text{Ca(HCO3)2(dung dịch pha loãng)}\)
\(\text{Ca(HCO3)2 → CaCO3 + H2O + CO2}\)
\(\text{Ca(HCO3)2 + 2HCl → 2H2O + 2CO2 + CaCl2}\)
\(\text{2Li3PO4+3CaCl2(đậm đặc)}\rightarrow\text{6LiCl↓+Ca3(PO4)2↓}\)
\(\text{NaHCO3+HCl}\rightarrow\text{NaCl+CO2↑+H2O}\)
\(\text{2NaCl+2H2O}\rightarrow\text{H2↑+2NaOH+Cl2↑}\)
a) 1. Fe + 2HCl -> FeCl2 + H2
2. FeCl2 + Ba(OH)2 ->Fe(OH)2 +BaCl2
3. Fe(OH)2 + H2SO4 -> FeSO4 + 2H2O
4. FeSO4 + BaCl2 -> FeCl2 + BaSO4
b) 1. 2Fe + 3Cl2 -> 2FeCl3 (đk: to > 250oC)
2. 2FeCl3+ 3Ba(OH)2 -> 2Fe(OH)3 + 3BaCl2
3. 2Fe(OH)3 -> Fe2O3 + 3H2O (đk: to)
4. Fe2O3 + 3H2 -> 2Fe + 3H2O
b)
(1) 2Fe +6 HCl -> 2FeCl3 + 3H2\(\uparrow\)
(2) 2FeCl3 + 3Ba(OH)2 -> 2Fe(OH)3 + 3BaCl2
(3) 2Fe(OH)3 -> Fe2O3 +3 H2O ( pứ cần to)
(42 Fe2O3 + 6H2 ->2 Fe + 3H2O
2: \(Zn+2HCl\rightarrow ZnCl_2+H_2\)
4: \(CaCO_3+2HCl\rightarrow CaCl_2+CO_2+H_2O\)
CH4 + Cl2 -> (askt) CH3Cl + HCl
Zn + 2 HCl -> ZnCl2 + H2
CaCO3 -to-> CaO + CO2
Nếu câu 3 là: CH2=CH2 + Br2 -> CHBr-BrCH
$4Na + O_2 \xrightarrow{t^o} 2Na_2O$
$Na_2O + H_2O \to 2NaOH$
$2NaOH + CO_2 \to Na_2CO_3 + H_2O$
$Na_2CO_3 + 2HCl\to 2NaCl + CO_2 + H_2O$
$CO_2 + Ca(OH)_2 \to CaCO_3 + H_2O$
$CaCO_3 + 2HCl \to CaCl_2 + CO_2 + H_2O$
4Na+O2→2Na2O
Na2O+H2O→2NaOH
NaOH+CO2→Na2CO3
Na2CO3+CaCl2−to→CaO+CO2+2NaCl
CaO+2HCl→CaCl2+H2O