
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.


\(\frac{8^{10}+4^{10}}{8^4+4^{11}}\)
\(=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}\)
\(=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}\)
\(=\frac{2^{20}.\left(2^{10}+1\right)}{2^{12}.\left(2^{10}+1\right)}\)
\(=\frac{2^{20}}{2^{12}}\)
\(=2^8=256\)

Tìm x hả bạn ?
a ) \(\left(3x+\frac{1}{4}\right)^3=-27\)
\(\left(3x+\frac{1}{4}\right)^3=\left(-3\right)^3\)
\(\Rightarrow3x+\frac{1}{4}=-3\)
\(\Rightarrow3x=-3-\frac{1}{4}=-\frac{13}{4}\)
\(\Rightarrow x=-\frac{13}{4}:3=-\frac{13}{12}\)
Vậy x = \(-\frac{13}{12}\)
cho em hoi câu này xin các anh chị:
10mux x+4y = 2013

\(a=4^5.9^4-2.\dfrac{6^9}{2^{10}}.3^8+6^8.20\)
Đề là như vầy đúng ko bn?

Bài làm :
\(\frac{125^6.3^{61}.8^{10}}{4^{15}.25^9.9^{30}}\)
\(=\frac{\left(5^3\right)^6.3^{61}.\left(2^3\right)^{10}}{\left(2^2\right)^{15}.\left(5^2\right)^9.\left(3^2\right)^{30}}\)
\(=\frac{5^{18}.3^{61}.2^{30}}{2^{30}.5^{18}.3^{60}}\)
\(=3\)
Học tốt nhé
Bài làm :
Ta có :
\(\frac{125^6.3^{61}.8^{10}}{4^{15}.25^9.9^{30}}\)
\(=\frac{\left(5^3\right)^6.3^{61}.\left(2^3\right)^{10}}{\left(2^2\right)^{15}.\left(5^2\right)^9.\left(3^2\right)^{30}}\)
\(=\frac{5^{18}.3^{61}.2^{30}}{2^{30}.5^{18}.3^{60}}\)
\(=\frac{3^{61}}{3^{60}}\)
\(=3\)


\(16^8-8^{10}+4^{14}\)
\(=2^{32}-2^{30}+2^{28}\)
\(=2^{28}\cdot\left(2^4-2^2+1\right)\)
\(=2^{24}\cdot2^4\cdot13\)
\(=2^{24}\cdot208⋮208\left(đpcm\right)\)
\(\frac{8^{10}+4^{10}}{8^4+4^{11}}=\frac{\left(2^3\right)^{10}+\left(2^2\right)^{10}}{\left(2^3\right)^4+\left(2^2\right)^{11}}=\frac{2^{30}+2^{20}}{2^{12}+2^{22}}=\frac{2^{20}\left(2^{10}+1\right)}{2^{12}\left(2^{10}+1\right)}=\frac{2^{20}}{2^{12}}=2^8\)