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Given a segment AB = 100cm. Let C be a point between A and B. Let M, N be respectively the midpoint of the segment BC, AC. Find the length of the segment MN.
Answer : MN = 50 cm
P/s : k mình nha bạn
REPLY: a) (A; 3cm) and (B; 2cm) intersect at C; D should: + C, D lie on the circle (A; 3cm), deduce AC = AD = 3cm. + C, D lie on the circle (B; 2cm), deduce BC = BD = 2cm. b) A circle (B; 2cm) cuts section AB at I should: + I lie on the circle (B; 2cm), deduce BI = 2cm. + I is on line AB, deduce IA + IB = AB. Where BI = 2cm; AB = 4cm so AI = 2cm. Hence BI = AI. Combined with I on the line AB deduce I is the midpoint AB. c) The circle (A; 3cm) cuts section AB at K so K belongs to the circle (A; 3cm), deducing AK = 3cm. On the line AB has AI <AK so I is between A and K. Hence AI + IK = AK. Which AK = 3cm; AI = 2cm so IK = 1cm
Given K is the midpoint of AB
If KA = 2x + 1 (cm)
BK = x + 5 (cm ) then AB = ....11.. (cm )
\(\text{Because M is the midpoint of line segment AB }\)
\(\Rightarrow AM=BM=60:2=30cm\)
I don't know???