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12 tháng 12 2019
\(\left(\frac{1}{2}\right)^{15}\cdot\left(\frac{1}{4}\right)^{20}=\left(\frac{1}{2}\right)^{15}\cdot\left[\left(\frac{1}{2}\right)^2\right]^{20}=\left(\frac{1}{2}\right)^{15}\cdot\left(\frac{1}{2}\right)^{40}=\left(\frac{1}{2}\right)^{15+40}=\left(\frac{1}{2}\right)^{55}\)
\(\left(\frac{1}{9}\right)^{25}:\left(\frac{1}{3}\right)^{30}=\left[\left(\frac{1}{3}\right)^2\right]^{25}:\left(\frac{1}{3}\right)^{30}=\left(\frac{1}{3}\right)^{50}:\left(\frac{1}{3}\right)^{30}=\left(\frac{1}{3}\right)^{50-30}=\left(\frac{1}{3}\right)^{20}\)
NẾU THẤY ĐÚNG THÌ NHỚ K CHO MÌNH VỚI ĐÓ !!! :33
22 tháng 6 2015
\(\frac{1}{2}^{15}.\frac{1}{4}^{20}=\frac{1}{2}^{15}.\left(\frac{1}{2}^2\right)^{20}=\frac{1}{2}^{15}.\frac{1}{2}^{40}=\frac{1}{2}^{55}\)
T
22 tháng 2 2020
C = \(25.\left(\frac{-1}{3}\right)^3\) \(+\frac{1}{5}\) \(-2.\left(\frac{-1}{2}\right)^2\) \(-\frac{1}{2}\)
C = \(25.\left(\frac{-1}{27}\right)+\frac{1}{5}\) \(-2.\frac{1}{4}\) \(-\frac{1}{2}\)
C = \(\frac{-25}{27}\) \(+\frac{1}{5}\) \(-\frac{1}{2}\) \(-\frac{1}{2}\)
C = \(\frac{-25}{27}\) \(+\frac{1}{5}\) \(-1\)
C = \(\frac{-125}{135}\) \(+\frac{27}{135}\) \(-\frac{135}{135}\)
C = \(\frac{-233}{135}\)
D = \(-8.\left(\frac{3}{4}-\frac{1}{4}\right):\left(\frac{9}{4}-\frac{7}{6}\right)\)
D = \(-8.\frac{1}{2}\) \(.\frac{12}{13}\)
D = \(-4.\frac{12}{13}\)
D = \(\frac{-48}{13}\)
E = \(5\sqrt{16}\) \(-4\sqrt{9}\) \(+\sqrt{25}\) \(-0,3\sqrt{400}\)
E = \(5.4-4.3+5-0,3.20\)
E = \(20-12+5-6\)
E = \(8+\left(-1\right)\)
E = \(7\)
F = \(\left(\frac{-3}{2}\right)\) \(+\left|\frac{-5}{6}\right|\) \(-1\frac{1}{2}\) \(:6\)
F = \(\left(\frac{-3}{2}\right)\) \(+\frac{5}{6}\) \(-\frac{3}{2}\) \(.\frac{1}{6}\)
F = \(\left(\frac{-3}{2}\right)\) \(+\frac{5}{6}\) \(-\frac{1}{4}\)
F = \(\left(\frac{-18}{12}\right)\) \(+\frac{10}{12}\) \(-\frac{3}{12}\)
F = \(\frac{-11}{12}\)
Chúc cậu hk tốt ~
27 tháng 9 2016
thần tượng của tớ là anhxtanh
= (1/3)50 : (1/3)30
= (1/3)20
23 tháng 8 2016
a) \(\left(\frac{2}{3}\right)^x=\left(\frac{4}{9}\right)^{50}\)
\(\Rightarrow\left(\frac{2}{3}\right)^x=\left(\frac{2^2}{3^2}\right)^{50}\)
\(\Rightarrow\left(\frac{2}{3}\right)^x=\left(\frac{2}{3}\right)^{100}\)
\(\Rightarrow x=100\)
Vậy x = 100
b) \(\left(\frac{2}{3}-x\right)^2=\frac{1}{36}\)
\(\Rightarrow\left(\frac{2}{3}-x\right)^2=\left(\frac{1}{6}\right)^2\)
\(\Rightarrow\frac{2}{3}-x=\frac{1}{6}\)
\(\Rightarrow x=\frac{2}{3}-\frac{1}{6}\)
\(\Rightarrow x=\frac{1}{2}\)
Vậy \(x=\frac{1}{2}\)
2)
Ta có:
\(74^{m+1}+74^m=74^m.74^1+74^m=74^m.\left(74+1\right)=74^m.75⋮25\)
( vì \(75⋮25\) )
\(\Rightarrowđpcm\)
\(\left(\frac{1}{9}\right)^{25}:\left(\frac{1}{3}\right)^{30}\)
\(=\left(\left(\frac{1}{3}\right)^2\right)^{25}:\left(\frac{1}{3}\right)^{30}\)
\(=\left(\frac{1}{3}\right)^{25\cdot2}:\left(\frac{1}{3}\right)^{30}\)
\(=\left(\frac{1}{3}\right)^{50}:\left(\frac{1}{3}\right)^{30}=\left(\frac{1}{3}\right)^{20}\)
Ta có: \(\left(\frac{1}{9}\right)^{25}=\left(\left(\frac{1}{3}\right)^2\right)^{25}=\left(\frac{1}{3}\right)^{50}\)
=> \(\left(\frac{1}{9}\right)^{25}\div\left(\frac{1}{3}\right)^{30}=\left(\frac{1}{3}\right)^{50}\div\left(\frac{1}{3}\right)^{30}=\left(\frac{1}{3}\right)^{50-30}=\left(\frac{1}{3}\right)^{20}\)