Question

[Hồ Tuyết Anh]

\(\left(\dfrac{1}{5}x^3y\right).\left(-5xy^3\right)^0.\left(xy^3\right)^2=\)

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Answer 1

[Nguyễn Lê Phước Thịnh]

\(=\dfrac{1}{5}x^3y\cdot x^2y^6=\dfrac{1}{5}x^5y^7\)

Answer 2

[TV Cuber]

\(=\dfrac{1}{5}.\left(x^3x^2\right)\left(yy^{3.2}\right)=\dfrac{1}{5}x^5y^7\)