Question

[Nguyễn Lê Minh Triết]

\(\left(\dfrac{1}{3}+\dfrac{3}{4}+\dfrac{13}{12}\right):\left(\dfrac{12}{23}+\dfrac{123}{234}+\dfrac{1234}{2345}\right)\) Giúp mình với. CẢM ƠN

Answer 1

[Nguyễn Lê Phước Thịnh]

Sửa đề: \(\left(\dfrac{1}{3}+\dfrac{3}{4}-\dfrac{13}{12}\right):\left(\dfrac{12}{23}+\dfrac{123}{234}+\dfrac{1234}{2345}\right)\)

\(=\left(\dfrac{4+9-13}{12}\right):\left(\dfrac{12}{23}+\dfrac{123}{234}+\dfrac{1234}{2345}\right)\)

=0