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Gọi ct chung: \(K_x^ICl^I_y\)
Theo qui tắc hóa trị: \(I.x=y.I=\dfrac{x}{y}=\dfrac{I}{I}=1\)
\(\Rightarrow x=1;y=1\)
\(\Rightarrow CTHH:KCl\)
b, Gọi ct chung: \(Al_x^{III}\left(SO_4\right)^{II}_y\)
Theo qui tắc hóa trị: \(III.x=y.II=\dfrac{x}{y}=\dfrac{II}{III}=\dfrac{2}{3}\)
\(\Rightarrow x=2;y=3\)
\(\Rightarrow CTHH:Al_2\left(SO_4\right)_3\)
`@` `\text {dnammv}`
`1,`
`a,` Gọi ct chung: \(\text{C}^{\text{IV}}_x\text{O}^{\text{II}}_{\text{y}}\)
Theo qui tắc hóa trị: \(\text{IV}\cdot\text{x}=\text{II}\cdot\text{y}\rightarrow\dfrac{\text{x}}{\text{y}}=\dfrac{\text{II}}{\text{IV}}=\dfrac{1}{2}\)
`-> \text {x=1, y=2}`
`-> \text {CTHH: CO}_2`
\(\text{PTK}_{\text{CO}_2}=12+16\cdot2=44\text{ }< \text{amu}>\)
`b,`
Gọi ct chung: \(\text{Na}^{\text{I}}_{\text{x}}\left(\text{SO}_4\right)^{\text{II}}_{\text{y}}\)
Theo qui tắc hóa trị: \(\text{I}\cdot\text{x}=\text{II}\cdot\text{y}\rightarrow\dfrac{\text{x}}{\text{y}}=\text{ }\dfrac{\text{II}}{\text{I}}\)
`-> \text {x=2, y=1}`
`-> \text {CTHH: Na}_2 \text {SO}_4`
`@` `\text {Ans}`
`\downarrow`
`a)`
Gọi ct chung: \(\text{Mg}^{\text{II}}_x\text{(NO}_3\text{)}^{\text{I}}_y\)
Theo quy tắc hóa trị: \(\text{II.x = I.y }\rightarrow\dfrac{x}{y}=\dfrac{I}{II}=\dfrac{1}{2}\)
`=> x = 1, y=2`
`=> \text {CTHH: Mg(NO}_3)_2`
`b)`
Gọi ct chung: \(\text{K}^{\text{I}}_x\text{O}^{\text{II}}_{\text{y}}\)
Theo quy tắc hóa trị: \(\text{I.x = II.y }\rightarrow\dfrac{x}{y}=\dfrac{II}{I}=\dfrac{2}{1}\)
`=> x = 2; y = 1`
`=> \text {CTHH: K}_2 \text {O}`
`c)`
Gọi ct chung: \(\text{Ag}^{\text{I}}_{\text{x}}\text{Cl}^{\text{I}}_y\)
Theo quy tắc hóa trị: \(\text{I.x = I. y }\rightarrow\dfrac{x}{y}=\dfrac{I}{I}=\dfrac{1}{1}\)
`=> x=1; y=1`
`=> \text {CTHH: AgCl}`
`@` `\text {Kaizuu lv uuu}`
\(a,CTHH:KCl\) , \(\text{K.L.P.T}=39+35,5=74,5< amu>.\)
\(CTHH:BaS\) , \(\text{K.L.P.T}=137+32=169< amu>.\)
\(CTHH:Al_2O_3\) , \(\text{K.L.P.T}=27.2+16.3=102< amu>.\)
\(b,CTHH:K_2SO_4\) , \(\text{K.L.P.T}=39.2+32+16.4=174< amu>.\)
\(CTHH:Al_2\left(SO_4\right)_3\), \(\text{K.L.P.T}=27.2+\left(32+16.4\right).3=342< amu>.\)
\(CTHH:MgCO_3\), \(\text{K.L.P.T}=24+12+16.3=84< amu>.\)
Tham khảo
nguồn:Hoc24
Diệu Huyềna: BaO
b: \(FeCl_3\)
c: K2O