Question

[Cao Tùng Lâm]

làm bài  3 nha 

Answer 1

[⚚ßé Só¡⁀ᶦᵈᵒᶫ]

A=\(\frac{-1}{9}:\left[\frac{-3}{2}.\left(1-\frac{4}{5}\right)-\frac{2}{3}.\left(\frac{-4}{5}-\frac{1}{-2}\right)\right]\)

=\(\frac{-1}{9}:\left[\frac{-3}{2}.\frac{1}{5}-\frac{2}{3}.\frac{-3}{10}\right]\)

=\(\frac{-1}{9}:\left(\frac{-3}{10}-\frac{-1}{5}\right)\)

=\(\frac{-1}{9}:\frac{-1}{10}=\frac{-1}{9}.\left(-10\right)=\frac{10}{9}\)

Answer 2

[⚚ßé Só¡⁀ᶦᵈᵒᶫ]

B=\(\frac{9}{2}:\left[\frac{1}{2}.\left(-1-\frac{3}{4}\right)+\frac{2}{3}.\left(\frac{-3}{4}-\frac{-1}{2}\right)\right]\)

B=\(\frac{9}{2}:\left[\frac{1}{2}.\frac{-7}{4}+\frac{2}{3}.\frac{-1}{4}\right]=\frac{9}{2}:\left(\frac{-7}{8}+\frac{-1}{6}\right)=\frac{9}{2}:\frac{-25}{24}=\frac{-108}{25}\)

C=\(\frac{5}{4}:\left[\frac{-5}{4}.\left(4-\frac{3}{5}\right)-\frac{3}{2}.\left(\frac{-3}{4}-\frac{3}{-5}\right)\right]\)

C=\(\frac{5}{4}:\left[\frac{-5}{4}.\frac{17}{5}-\frac{3}{2}.\frac{-3}{20}\right]=\frac{5}{4}:\left(\frac{-17}{4}-\frac{-9}{40}\right)=\frac{5}{4}:\frac{-161}{40}=\frac{-50}{161}\)

D=\(\frac{4}{7}.\left[\frac{-3}{4}:\left(\frac{5}{-4}-\frac{-4}{5}\right)+\frac{2}{3}:\left(\frac{-4}{5}-\frac{1}{-2}\right)\right]\)

=\(\frac{4}{7}.\left[\frac{-3}{4}:\frac{-9}{20}+\frac{2}{3}:\frac{-3}{10}\right]=\frac{4}{7}.\left(\frac{5}{3}+\frac{-20}{9}\right)=\frac{4}{7}.\frac{-5}{9}=\frac{-20}{63}\)

E=\(\frac{2}{-5}.\left[\frac{3}{2}:\left(\frac{-3}{4}+\frac{3}{5}\right)+\frac{2}{3}:\left(\frac{-7}{5}+\frac{4}{3}\right)\right]\)

E=\(\frac{2}{-5}.\left[\frac{3}{2}:\frac{-3}{20}+\frac{2}{3}:\frac{-1}{15}\right]=\frac{-2}{5}.\left[\left(-10\right)+\left(-10\right)\right]=\frac{-2}{5}.\left(-20\right)=8\)

F=)tương tự mấy câu trên)