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3 x7/10 + 7/10x5 + 2 x 7/10
=( 3 + 5 + 2 ) x 7/10
= 10 x 7/10
= 7
`a) 5 / 13 xx 4 / 15 xx 13 = [ 5 xx 4 xx 13 ] / [ 13 xx 5 xx 3 ] = 4 / 3`
`b) ( 3 / 7 + 5 / 2 ) xx 7 / 5 = 3 / 7 xx 7 / 5 + 5 / 2 xx 7 / 5 = 3 / 5 + 7 / 2 = 6 / 10 + 35 / 10 = 41 / 10`
`c) 1 / 5 xx 11 / 18 + 11 / 18 xx 3 / 5 = 11 / 18 xx ( 1 / 5 + 3 / 5 ) = 11 / 18 xx 4 / 5 = [ 11 xx 2 xx 2 ] / [ 2 xx 9 xx 5 ] = 22 / 45`
\(a,\dfrac{5}{13}\times\dfrac{4}{15}\times13=\dfrac{4}{3}\)
\(b,\left(\dfrac{3}{7}+\dfrac{5}{2}\right)\times\dfrac{7}{5}=\left(\dfrac{6}{14}+\dfrac{35}{14}\right)\times\dfrac{7}{5}=\dfrac{41}{14}\times\dfrac{7}{15}=\dfrac{41}{30}\)
\(c,\dfrac{1}{5}\times\dfrac{11}{18}+\dfrac{11}{18}\times\dfrac{3}{5}=\dfrac{11}{18}\times\left(\dfrac{1}{5}+\dfrac{3}{5}\right)=\dfrac{11}{18}\times\dfrac{4}{5}=\dfrac{22}{45}\)
11x21x18/9x22x14
=231x18/9x22x14
=462x22x14
=10164x14
=142296
a) = \(\frac{5\cdot7\cdot8\cdot9\cdot10}{7\cdot8\cdot9\cdot10\cdot11}\)
= \(\frac{5}{11}\) gạch hết các chữ số 7 , 8 , 9 , 10.
b) = \(\frac{3\cdot145+3\cdot55}{6\cdot215+6\cdot85}\)
= \(\frac{3\cdot\left(145+55\right)}{6\cdot\left(215+85\right)}\)
= \(\frac{3\cdot200}{6\cdot300}\)
= \(\frac{1}{3}\)
3, A= 2007 X 2009
= 2007 X (2008+ 1)
= 2007 X 2008+ 2007
B= 2008 X 2008
= 2008 X (2007+ 1)
= 2008 X 2007+ 2008
Vì 2007 < 2008 nên 2008 X 2007+ 2007 < 2008 X 2007+ 2008
Vậy A < B
A) 5/4 x X = 3/8 + 5/12
5/4 x X = 19/24
X = 19/24 : 5/4
X = 19/30
vậy x =...
B, 3 x 7/10 + 7/10 x 5 + 2 x 7/10
= 7/10 x ( 3 + 5 + 2)
= 7/10 x 10
= 7
tính = cách thuận tiện nhất
a/ 5/11 nhân 7/25 trừ 15/11 nhân 1/5
b/ 3/7 nhân 25/19 trừ 1/7 nhân 18/19
a ) \(\frac{5}{11}\times\frac{7}{25}\times\frac{15}{11}\times\frac{1}{5}\)
\(=\frac{5\times7\times15\times1}{11\times25\times11\times5}\)
\(=\frac{1\times7\times3\times1}{11\times5\times11\times1}\)
\(=\frac{21}{\left(10\times5+5\times1\right)\times11}\)
\(=\frac{21}{55\times11}\)
\(=\frac{21}{55\times10+55}\)
\(=\frac{21}{550+55}\)
\(=\frac{21}{605}\) ( quá đơn giản )
\(\)
A) \(\frac{5}{11}\times\frac{7}{25}-\frac{15}{11}\times\frac{1}{5}\)
\(=\frac{5\times7}{11\times25}-\frac{15\times1}{11\times5}\)
\(=\frac{35}{10\times25+25}-\frac{15}{55}\)
\(=\frac{35}{250+25}-\frac{15}{55}\)
\(=\frac{35}{275}-\frac{15}{55}\)
\(=\frac{7}{55}-\frac{15}{55}\)
\(=\frac{7-15}{55}\)
\(=\frac{-8}{55}\)
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a=3
b=0