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Lời giải:
a. $=128-78+100-128=(128-128)+100-78=0+100-78=22$
b. $=125-100+93-218= (125+93-218)-100=0-100=-100$
c. $=453+74-79-527$
$=(453+74-527)-79 =0-79=-79$
d.
$=-825+775+825=(825-825)+775=0+775=775$
e.
$=163-413-187+637 = (163+637)-(413+187) = 800-600=200$
\(a.83-\left(-756-17\right)+\left(50-756\right)=83+756+17+50-756=\left(83+17\right)+50+\left(756-756\right)=100+50=150\)
\(b.-105+\left(-34-95\right)-166=-105+\left(-34\right)-95-166=\left(-105-95\right)-\left(34+166\right)=\left(-200\right)-200=-400\)
\(c,-\left(39+228-407\right)+\left(118-161\right)=-39-228+407+118-161=\left(-39-161\right)-\left(228-118\right)+407=\left(-200\right)-110=-310\)
\(d,5^{10}:5^8+60:12+\left(-10\right)=5^2+5+\left(-10\right)=5\left(5+1-2\right)=5.4=20\)
\(e,-342-\left(161-342\right)-39=-342-161+342-39=\left(-342+342\right)-\left(161+39\right)=-200\)\(g,7^5:7^3+\left(-187-149\right)-213=7^2+\left(-187\right)-149-213=\left(49-149\right)-\left(187+213\right)=\left(-100\right)-400=-500\)
1.
a)=315-315-200-(21+79)=-200-100=-300
b)=413-413-210+70+30=-210+100=-110
a)\(B=2022.2022\)
\(=\left(2021+1\right)2022\)
\(=2021.2022+2022\)
Vì \(2020< 2022\Rightarrow2021.2020< 2021.2022\Rightarrow2021.2020< 2021.2022+2022\)
hay \(A< B\)
b)\(M=360.345-200\)
\(=360\left(344+1\right)-200\)
\(=360.344+360-200\)
\(=360.344+160< 340.344+161=N\)
\(\Rightarrow M< N\)
b: =800-600-200=0