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30 tháng 9 2018

1) \(x^4-3x^2-x+3\)

\(=x\left(x^3-1\right)-3\left(x^2-1\right)\)

\(=x\left(x-1\right)\left(x^2+x+1\right)-3\left(x+1\right)\left(x-1\right)\)

\(=\left(x-1\right)\left(x^3+x^2+x-3x-3\right)\)

\(=\left(x-1\right)\left(x^3+x^2-2x-3\right)\)

2) \(3x+3y-x^2-2xy-y^2\)

\(=3\left(x+y\right)-\left(x^2+2xy+y^2\right)\)

\(=3\left(x+y\right)-\left(x+y\right)^2\)

\(=\left(x+y\right)\left(3-x-y\right)\)

3) \(x^4-x\)

\(=x\left(x^3-1\right)\)

\(=x\left(x-1\right)\left(x^2+x+1\right)\)

30 tháng 9 2018

4) \(x^2+5x+4\)

\(=x^2+x+4x+4\)

\(=x\left(x+1\right)+4\left(x+1\right)\)

\(=\left(x+1\right)\left(x+4\right)\)

5) \(4x^2+4x-8\)

\(=4\left(x^2+x-2\right)\)

\(=4\left(x^2-x+2x-2\right)\)

\(=4\left[x\left(x-1\right)+2\left(x-1\right)\right]\)

\(=4\left(x-1\right)\left(x+2\right)\)

6) \(x^2+x-42\)

\(=x^2-6x+7x-42\)

\(=x\left(x-6\right)+7\left(x-6\right)\)

\(=\left(x-6\right)\left(x+7\right)\)

7 tháng 10 2017

bài 1

a)\(x^2+5x+6=\left(x+2\right)\left(x+3\right)=0\Leftrightarrow\orbr{\begin{cases}x+3=0\\x+2=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=-3\\x=-2\end{cases}}}\)

4 tháng 12 2018

a. \(x^3+x^2-4x-4=x^2\left(x+1\right)-4\left(x+1\right)=\left(x+1\right)\left(x^2-4\right)=\left(x+1\right)\left(x+2\right)\left(x-2\right)\)

b. \(x^2-y^2-4x+4=\left(x^2-4x+4\right)-y^2=\left(x-2\right)^2-y^2=\left(x+y-2\right)\left(x-y-2\right)\)

c. \(\left(x^2+9\right)^2-36x^2=\left(x^2+6x+9\right)\left(x^2-6x+9\right)=\left(x+3\right)^2\left(x-3\right)^2\)

d. \(25-x^2+2xy-y^2=25-\left(x-y\right)^2=\left(5+x-y\right)\left(5-x+y\right)\)

còn lại làm tương tự

4 tháng 12 2018

a) \(x^3+x^2-4x-4=x^2\left(x+1\right)-4\left(x+1\right)=\left(x+1\right)\left(x-2\right)\left(x+2\right)\)

b) \(x^2-y^2-4x+4=\left(x-2\right)^2-y^2=\left(x-y-2\right)\left(x+y-2\right)\)

c) \(\left(x^2+9\right)^2-36x^2=\left(x^2+9\right)^2-\left(6x\right)^2=\left(x^2-6x+9\right)\left(x^2+6x+9\right)\)

\(=\left(x-3\right)^2\left(x+3\right)^2\)

d) \(25-x^2+2xy-y^2=5^2-\left(x-y\right)^2=\left(5-x+y\right)\left(5+x-y\right)\)

e) \(x^3-4x^2+4x-1=\left(x-1\right)\left(x^2+x+1\right)-4x\left(x-1\right)\)

\(=\left(x-1\right)\left(x^2+x+1-4x\right)=\left(x-1\right)\left(x^2-3x+1\right)\)

f) \(3x-3y-x^2+2xy-y^2=3\left(x-y\right)-\left(x-y\right)^2\)

\(=\left(x-y\right)\left(3-x+y\right)\)

g) \(2x^2-9x+10=2x^2-4x-5x+10=2x\left(x-2\right)-5\left(x-2\right)=\left(x-2\right)\left(2x-5\right)\)

h) \(x^2-5x-14=x^2-7x+2x-14=x\left(x-7\right)+2\left(x-7\right)=\left(x-7\right)\left(x+2\right)\)

i) \(x^3-3x^2+2=x^3-2x^2-x^2+2=x^2\left(x-1\right)-2\left(x^2-1\right)\)

\(=x\left(x-1\right)-2\left(x-1\right)\left(x+1\right)=\left(x-1\right)\left(x-2x-2\right)\)

k) \(x^4+4=\left(x^2\right)^2+2\cdot x^2\cdot2+2^2-2\cdot x^2\cdot2\)

\(=\left(x^2+2\right)^2-\left(2x\right)^2=\left(x^2-2x+2\right)\left(x^2+2x+2\right)\)

21 tháng 3 2016

het thoirui pan oi

Bài 3:

3: \(6x\left(x-y\right)-9y^2+9xy\)

\(=6x\left(x-y\right)+9xy-9y^2\)

\(=6x\left(x-y\right)+9y\left(x-y\right)\)

\(=\left(x-y\right)\left(6x+9y\right)\)

\(=3\left(2x+3y\right)\left(x-y\right)\)

Bài 4:

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