Question

[Phạm Tuấn Long]

I; chuyển vế đổi dấu

a) -3x+4+5x=-10-x

b)-x+1=-3x-8

c)8-(x-1)=10+(x+5)

d)100+(x+7)-(-2x+3)=8+(x+100)

e) |2x+5|=|x-1|

g)|-x+4|=|-3x-8|

h)|x+4|=|-3-8|

Answer 1

[Phạm Thị Thạch Thảo]

a) -3x+4+5x=-10-x

-3x+4+5x+10+x=0

(-3x+5x+x)+10=0

3x+10=0

3x=-10

x=\(\dfrac{-10}{3}\)

Vậy x=\(\dfrac{-10}{3}\)

b)-x+1=-3x-8

-x+1+3x+8=0

(-x+3x)+(1+8)=0

2x+9=0

2x=-9

x=\(\dfrac{-9}{2}\)

Vậy x=\(\dfrac{-9}{2}\)

c)8-(x-1)=10+(x+5)

8-x+1=10+x+5

9-x=15+x

9-x-15-x=0

(9-15)-(x+x)=0

-6-2x=0

2x=-6

x=-3

Vậy x=-3

d)100+(x+7)-(-2x+3)=8+(x+100)

100+x+7+2x-3=8+x+100

(x+2x)+(100+7-3)=(8+100)+x

3x+104=108+x

3x+104-108-x=0

(3x-x)+(104-108)=0

2x-4=0

2x=4

x=2

Vậy x=2

Answer 2

[Đức Hiếu]

e, \(\left|2x+5\right|=\left|x-1\right|\)

\(\Rightarrow\left\{{}\begin{matrix}2x+5=1-x\\2x+5=x-1\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}3x=-4\\x=-6\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=-\dfrac{4}{3}\\x=-6\end{matrix}\right.\)

g, \(\left|-x+4\right|=\left|-3x-8\right|\)

\(\Rightarrow\left\{{}\begin{matrix}-x+4=3x+8\\-x+4=-3x-8\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}-4x=4\\2x=-12\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=-1\\x=-6\end{matrix}\right.\)

h, \(\left|x+4\right|=\left|-3-8\right|\)

\(\Rightarrow\left|x+4\right|=\left|-11\right|=11\)

\(\Rightarrow\left\{{}\begin{matrix}x+4=-11\\x+4=11\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=-15\\x=7\end{matrix}\right.\)

Chúc bạn học tốt!!!