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13/5 x 2/3 + 7/3 x 2/3 = (13/5 + 7/3) x 2/3 = 74/15 x 2/3=28/5
21x - 5.2 + 3 - 7 = 7x
=> 21x - 10 - 4 = 7x
=> 2x - 14 = 7x
=> 2x - 7x = 14
=> -5x = 14
=> x = -14/5
Vậy...
\(3\frac{2}{5}\times2\frac{1}{7}\)
\(=\frac{17}{5}\times\frac{15}{7}\)
\(=\frac{17\times15}{5\times7}\)
\(=\frac{17\times3\times5}{5\times7}\)
\(=\frac{17\times3}{7}\)
\(=\frac{51}{7}\)
21x - 5.2 + 3 - 7 = 7x
=> 21x - 10 - 4 = 7x
=> 21x - 14 = 7x
=> 21x - 7x = 14
=> 14x = 14
=> x = 14 : 14
=> x = 1
3/4+2/3+5/12=11/6
7/8-7/16-11/32=3/32
3/5*2/7*5/6=1/7
15/16:3/8:3/4=10/3
bạn nhé
\(a,\frac{2}{5}:\frac{6}{5}+\frac{3}{4}.\frac{12}{5}\)
=\(\frac{2}{5}.\frac{5}{6}+\frac{9}{5}\)
=\(\frac{1}{3}+\frac{9}{5}\)
=\(\frac{32}{5}\)
b) \(\frac{17}{5}.\frac{3}{5}.\frac{17}{5}.\frac{2}{5}\)
=\(\frac{17}{5}.\left(\frac{3}{5}.\frac{2}{5}\right)\)
=\(\frac{17}{5}.\frac{6}{25}\)
=\(\frac{102}{125}\)
c)\(\frac{1}{4}+\frac{3}{4}.\frac{2}{3}-\frac{1}{2}\)
=\(\frac{1}{4}+\frac{1}{2}-\frac{1}{2}\)
=\(\frac{1}{4}\)
d)\(\frac{6}{7}+\frac{5}{8}:5\)
=\(\frac{6}{7}+\frac{5}{8}.\frac{1}{5}\)
=\(\frac{6}{7}+\frac{1}{8}\)
=\(\frac{48}{56}+\frac{7}{56}\)
=\(\frac{55}{56}\)
tk nhé bn!
1a,\(\frac{8}{5}\)=1\(\frac{3}{5}\)b,\(\frac{9}{2}\)=4\(\frac{1}{2}\)c,\(\frac{7}{4}\)=1\(\frac{3}{4}\)d,\(\frac{10}{3}\)
2a,1\(\frac{3}{4}\)+1\(\frac{5}{8}\)=\(\frac{7}{4}\)+\(\frac{13}{8}\)=\(\frac{14}{8}\)+\(\frac{13}{8}\)=\(\frac{27}{8}\)b,3\(\frac{4}{5}\)x2\(\frac{6}{8}\)=\(\frac{19}{5}\)x\(\frac{22}{8}\)=\(\frac{418}{40}\)=\(\frac{209}{20}\)
3,3\(\frac{2}{5}\)=\(\frac{17}{5}\),3\(\frac{4}{5}\)=\(\frac{19}{5}\) , 8\(\frac{2}{4}\)=\(\frac{34}{4}\),10\(\frac{6}{7}\)=\(\frac{76}{7}\) , 5\(\frac{1}{2}\)=\(\frac{11}{2}\),5\(\frac{3}{4}\)=\(\frac{23}{4}\)
=>\(\frac{17}{5}\)<\(\frac{19}{5}\)=>3\(\frac{2}{5}\)<3\(\frac{4}{5}\) =>\(\frac{34}{4}\)<\(\frac{76}{7}\)=>8\(\frac{2}{4}\)<10\(\frac{6}{7}\) =>\(\frac{11}{2}\)<\(\frac{23}{4}\)=>5\(\frac{1}{2}\)<5\(\frac{3}{4}\)
k mik nha ......
\(\dfrac{3}{5}\times\dfrac{2}{7}:\dfrac{4}{9}=\dfrac{6}{35}\times\dfrac{9}{4}=\dfrac{54}{140}=\dfrac{27}{70}\)