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\(\left(-6\right).3+6.\left(-11\right)+\left(-6\right).\left(-2\right)\)
\(=\left(-6\right).3+\left(-6\right).11+\left(-6\right).\left(-2\right)\)
\(=\left(-6\right).\left[3+11+\left(-2\right)\right]\)
\(=\left(-6\right).12\)
\(=-72\)
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\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+......+\frac{1}{99}-\frac{1}{100}=1-\frac{1}{100}=\frac{99}{100}\)
\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{99.100}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{99}-\frac{1}{100}\)
\(=1-\frac{1}{100}\)
\(=\frac{100}{100}-\frac{1}{100}\)
\(=\frac{99}{100}\)
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\(\frac{\left(3.4.2^4\right)^2}{5.2^5.4^2-16^2}\)
\(=\frac{\left(3.2^2.2^4\right)^2}{5.2^5\left(2^2\right)^2-\left(2^4\right)^2}\)
\(=\frac{\left(3.2^6\right)^2}{5.2^9-2^8}\)
\(=\frac{3^2.2^{12}}{2^8\left(5.2-1\right)}\)
\(=\frac{9.2^4}{9}\)
\(=16\)
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ta có: 3x+4y-xy=-21 <=> 4y-xy=-21-3x
<=> y(4-x)=-3(7+x)
suy ra 4-x=-3 và y=7+x
suy ra x=7 ; y=14
Cách này mình làm chưa chặc chẽ cho lắm nha! mong bạn thông cảm
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\(2\left(x-\frac{1}{2}\right)-5\left(\frac{3}{10}-1\right)=7\)
\(\Rightarrow\left(2x-1\right)-\left(\frac{3}{2}-5\right)=7\)
\(\Rightarrow\left(2x-1\right)-\frac{-7}{2}=7\)
\(\Rightarrow\left(2x-1\right)=7+\frac{-7}{2}=\frac{7}{2}\)
\(\Rightarrow2x=\frac{7}{2}+1\)
\(\Rightarrow x=\frac{9}{2}:2\)
\(\Rightarrow x=\frac{9}{4}\)
2(x-1/2)-5(3/10-1)=7
2x-1-3/2+5=7
2x=7+1+3/2-5
2x=9/2
x=9/4
Vậy x=9/4.