Question

[Khánh Linh]

Giúp t với mn ơi!!

Answer 1

[๖ۣۜDũ๖ۣۜN๖ۣۜG]

Câu 3:

Gọi số mol C₂H₄, C₂H₂ là a, b (mol)

=> \(a+b=\dfrac{6,72}{22,4}=0,3\left(mol\right)\) (1)

\(n_{Br_2}=\dfrac{64}{160}=0,4\left(mol\right)\)

PTHH: C₂H₄ + Br₂ --> C₂H₄Br₂

              a--->a

             C₂H₂ + 2Br₂ --> C₂H₂Br₄

               b---->2b

=> a + 2b = 0,4 (2)

(1)(2) => a = 0,2; b = 0,1

=> \(\left\{{}\begin{matrix}\%V_{C_2H_4}=\dfrac{0,2}{0,3}.100\%=66,67\%\\\%V_{C_2H_2}=\dfrac{0,1}{0,3}.100\%=33,33\%\end{matrix}\right.\)

Answer 2

[๖ۣۜDũ๖ۣۜN๖ۣۜG]

Câu 4:

Chỉ có Propin pư với AgNO₃/NH₃

\(n_{C_3H_3Ag}=\dfrac{44,1}{147}=0,3\left(mol\right)\)

=> \(n_{C_3H_4}=0,3\left(mol\right)\)

=> \(n_{C_4H_6}=\dfrac{17,4-0,3.40}{54}=0,1\left(mol\right)\)

=> \(\left\{{}\begin{matrix}\%V_{C_3H_4}=\dfrac{0,3}{0,3+0,1}.100\%=75\%\\\%V_{C_4H_6}=\dfrac{0,1}{0,3+0,1}.100\%=25\%\end{matrix}\right.\)