Question

[NguyễnღViếtღGiaღBảo⁀ᶦᵈᵒᶫღ²Ⓚ⁹『𝕿𝖊𝖆𝖒....]

*Giúp mk vs mk hứa tik cho

Answer 1

[Nguyễn Quang Minh]

\(\left(\frac{2}{3}\right)^{17}:\left(\frac{2}{3}\right)^{15}+\frac{4}{9}.\left(-\frac{1}{2}\right)^3\)

\(=\left(\frac{2}{3}\right)^{17-15}+\frac{4}{9}.\left(-\frac{1}{8}\right)\)

\(=\left(\frac{2}{3}\right)^2+\frac{4}{9}.\left(-\frac{1}{8}\right)\)

\(=\frac{4}{9}+\frac{4}{9}.\left(-\frac{1}{8}\right)\).

\(=\frac{4}{9}.1+\frac{4}{9}.\left(-\frac{1}{8}\right)\)

\(=\frac{4}{9}.\left(-\frac{1}{8}+1\right)\)

\(=\frac{4}{9}.\frac{7}{8}\)

\(=\frac{7}{18}\)

Answer 2

[Member lỗi thời :>>]

\(\left(\frac{2}{3}\right)^{17}:\left(\frac{2}{3}\right)^{15}+\frac{4}{9}.\left(-\frac{1}{2}\right)^3\)

\(=\left(\frac{2}{3}\right)^{17-15}+\frac{2^2}{9}.\frac{-1}{2^3}\)

\(=\left(\frac{2}{3}\right)^2+\frac{-1}{18}\)\(=\frac{4}{9}-\frac{1}{18}=\frac{7}{18}\)