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a) \(\frac{3}{7}-\frac{1}{7}x=\frac{2}{3}\)
=> \(\frac{1}{7}x=\frac{3}{7}-\frac{2}{3}=-\frac{5}{21}\)
=> \(x=-\frac{5}{21}:\frac{1}{7}=-\frac{5}{21}\cdot7=-\frac{5}{3}\)
b) \(3x^2-2=72\)=> 3x2 = 74 => x2 = 74/3 => x không thỏa mãn
c) \(\left(19x+2\cdot5^2\right):14=\left(13-8\right)^2-4^2\)
=> \(\left(19x+2\cdot25\right):14=5^2-4^2=9\)
=> \(\left(19x+50\right):14=9\)
=> \(19x+50=126\)
=> \(19x=76\)
=> x = 4
d) \(x:\frac{1}{2}+x:\frac{1}{4}+x:\frac{1}{8}+x:\frac{1}{16}+x:\frac{1}{32}=343\)
=> \(x\cdot2+x\cdot4+x\cdot8+x\cdot16+x\cdot32=343\)
=> \(x\left(2+4+8+16+32\right)=343\)
=> x . 62 = 343
=> x = 343/62
3^x-2.9=81
3^x-2=81:9
3^x-2=9
3^x=9+2
3^x=11
3^x= tap hop rong
Suy ra x = tap hop rong
a) \(\left(19x+2\cdot5^2\right):14=\left(13-8\right)^2-4^2\)
\(\left(19x+2\cdot5^2\right):14=9\)
\(19x+2\cdot5^2=9\cdot14=126\)
\(19x+50=126\)
\(19x=126-50=76\)
\(x=\frac{76}{19}=4\)
b) \(x+\left(x+1\right)+\left(x+2\right)+...+\left(x+30\right)=1240\)
\(\left(x+x+..+x\right)+\left(1+2+3+...+30=1240\right)\)(31 chữ số x)
\(31x+\frac{30\cdot31}{2}=1240\Leftrightarrow31x+465=1240\)
\(31x=1240-465=775\)
\(x=\frac{775}{31}=25\)
c) \(11-\left(-53+x\right)=97\)
\(11+53-x=97\Leftrightarrow64-x=97\)
\(x=64-97=-33\)
d) \(-\left(x+81\right)+213=-16\)
\(-x-81+213=-16\)
\(-x+132=-16\)
\(-x=-16-132=-148\)
\(x=148\)
..........
2.3x= 10.312+8.274
2.3x = 10.(33)4+ (33)4 . 8
2.3x= (33)4. 18
2.3x= (33)4.2.32
2.3x= 312+2.2
2.3x= 314.2
=> x = 14
Bn đánh thíu rùi, đề bài phải như này mới đúng
Tính:
(102 + 112 + 122) : (132 + 142)
= (100 + 121 + 144) : (169 + 196)
= 365 : 365
= 1
125 : 5^2 . (x-3) = 3
125 : 25 .(x-3) = 3
5 (x-3) =3
x-3 = 3 : 5
Đề bài sai hay sao ý?
2x -5 = 3
2x = 3+5 =8
x =4
(19 .x+2.5^2 ): 14 = (13-8)^2 - 4^2
19x + 50) : 14 = 25 - 16
(19x+50) : 14 = 9
19x+50 = 3*14 = 126
19x = 126-50 = 76
x = 76 / 19 = 4
\(a\)) \(125:5^2.\left(x-3\right)=3\)
\(5^3:5^2.\left(x-3\right)=3\)
\(5.\left(x-3\right)=3\)
\(5x-15=3\)
\(5x=3+15\)
\(5x=18\)
\(x=\frac{18}{5}\)\(.\)Vậy \(x=\frac{18}{5}\)
\(b\)) \(\left(2x-5\right)^3=27\)
\(\left(2x-5\right)^3=3^3\)
\(\Rightarrow2x-5=3\)
\(\Rightarrow2x=8\)
\(\Rightarrow x=4\)\(.\)Vậy \(x=4\)
\(c\))\(\left(19.x+2.5^2\right):14=\left(13-8\right)^2-4^2\)
\(\left(19.x+2.25\right):14=5^2-16\)
\(\left(19.x+2.25\right):14=25-16\)
\(\left(19.x+50\right):14=9\)
\(19.x+50=126\)
\(19.x=126-50\)
\(19.x=76\)
\(x=76:19\)
\(x=4\)\(.\)Vậy \(x=4\)
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( 19x + 2.52 ) : 14 = ( 13 - 8 )2- 4 2
( 19x + 2.52 ) : 14 = 52- 4 2
( 19x + 2.52 ) : 14 = 25- 16
( 19x + 2.52 ) : 14 =9
( 19x + 50 ) : 14 =9
19x + 50=9 . 14
19x + 50=126
19x=126-50
19x=76
x=76:19
x=4
(19x + 2.5²) : 14 = (13 - 8)² - 4²
(19x + 2.25) : 14 = 5² - 16
(19x + 50) : 14 = 25 - 16
(19x + 50) : 14 = 9
19x + 50 = 9 . 14
19x + 50 = 126
19x = 126 - 50
19x = 76
x = 76 : 19
x = 4