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( x - 3/2 ) mũ 2 = 9/16 , cứuuu

Nguyễn Huy Tú · Accepted Answer

$\left(x-\dfrac{3}{2}\right)^2=\dfrac{9}{16}=\left(\dfrac{3}{4}\right)^2$$\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{3}{2}=\dfrac{3}{4}\x-\dfrac{3}{2}=-\dfrac{3}{4}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{9}{4}\x=\dfrac{3}{4}\end{matrix}\right.$Câu trả lời: $\left(x-\dfrac{3}{2}\right)^2=\dfrac{9}{16}=\left(\dfrac{3}{4}\right)^2$$\Leftrightarrow\left[{}\begin{matrix}x-\dfrac{3}{2}=\dfrac{3}{4}\x-\dfrac{3}{2}=-\dfrac{3}{4}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{9}{4}\x=\dfrac{3}{4}\end{matrix}\right.$

HT.Phong (9A5) · Answer

$\left(x-\dfrac{3}{2}\right)^2=\dfrac{9}{16}\
\left(x-\dfrac{3}{2}\right)^2=\left(\dfrac{3}{4}\right)^2$TH1: $x-\dfrac{3}{2}=\dfrac{3}{4}\Rightarrow x=\dfrac{3}{4}+\dfrac{3}{2}\Rightarrow x=\dfrac{3}{4}+\dfrac{6}{4}\Rightarrow x=\dfrac{9}{4}$TH2: $x-\dfrac{3}{2}=-\dfrac{3}{4}\Rightarrow x=-\dfrac{3}{4}+\dfrac{3}{2}\Rightarrow x=-\dfrac{3}{4}+\dfrac{6}{4}\Rightarrow x=\dfrac{3}{4}$Câu trả lời: $\left(x-\dfrac{3}{2}\right)^2=\dfrac{9}{16}\
\left(x-\dfrac{3}{2}\right)^2=\left(\dfrac{3}{4}\right)^2$TH1: $x-\dfrac{3}{2}=\dfrac{3}{4}\Rightarrow x=\dfrac{3}{4}+\dfrac{3}{2}\Rightarrow x=\dfrac{3}{4}+\dfrac{6}{4}\Rightarrow x=\dfrac{9}{4}$TH2: $x-\dfrac{3}{2}=-\dfrac{3}{4}\Rightarrow x=-\dfrac{3}{4}+\dfrac{3}{2}\Rightarrow x=-\dfrac{3}{4}+\dfrac{6}{4}\Rightarrow x=\dfrac{3}{4}$

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