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`a, 18(x-16)=-36`
`=>x-16=-36:18`
`=>x-16=-2`
`=>x=-2+16`
`=>x= 14`
`b,(-12-x):(-5)=3`
`=>-12-x=3 . (-5)`
`=>-12-x=-15`
`=>x= -12-(-15)`
`=>x=-12+15`
`=>x= 3`
`c,11-(-53+x)=97`
`=>-53+x=11-97`
`=>-53+x=-86`
`=>x=-86-(-53)`
`=>x=-86+53`
`=>x= -33`
`d,-9.x+(-7).x=-48`
`=> [-9+(-7) ].x=-48`
`=>-16.x=-48`
`=>x=-48:(-16)`
`=>x= 3`
`e,(2x-1)^3=-27`
`=> (2x-1)^3=-3^3`
`=> 2x-1=-3`
`=>2x=-3+1`
`=>2x=-2`
`=>x=-2:2`
`=>x=-1`
bn tách ra nhé!
Bài 5 :
\(a,5x-16=40+x\)
\(\Leftrightarrow5x-x=40+16\)
\(\Leftrightarrow4x=56\)
\(\Leftrightarrow x=14\)
\(b,-41+2x-\left(-24\right)=4x-23-x\)
\(\Leftrightarrow-41+2x+24=4x-23-x\)
\(\Leftrightarrow2x-4x+x=41-24-23\)
\(\Leftrightarrow-x=-6\)
\(\Leftrightarrow x=6\)
\(c,2\left(x-5\right)-\left(x+6\right)=\left(-7\right)^2\)
\(\Leftrightarrow2x-10-x-6=49\)
\(\Leftrightarrow x=65\)
\(d,120-4\left(1-x\right)=106-3x\)
\(\Leftrightarrow120-4+4x=106-3x\)
\(\Leftrightarrow4x+3x=106-120+4\)
\(\Leftrightarrow7x=-10\)
\(\Leftrightarrow x=-\dfrac{10}{7}\)
(x - 1)(y - 4) = 3
=> x - 1; y - 4 thuộc Ư(3)
=> x - 1; y - 4 thuộc {1; 3; -1; -3}
ta có bảng :
x-1 | -1 | 1 | -3 | 3 |
y-4 | -3 | 3 | -1 | 1 |
x | 0 | 2 | -2 | 4 |
y | 1 | 7 | 3 | 5 |
vậy_
\(\left(x-1\right)\left(x-4\right)=3\)
\(\Rightarrow x-1;y-4\inƯ\left(3\right)\)
Vì \(\in\)Ư (3)=\(\left\{\mp1;\mp3\right\}\)
Tìm xTa có
\(x-1=-1;x=-1+1=0\)
\(x-1=1;x=1+1=2\)
\(x-1=-3;x=-3+1=-2\)
\(x-1=3;x=3+1=4\)
Vậy .....
Tìm y Ta có :
\(y-4=-3;y=-3+4=1\)
\(y-4=3;y=3+4=7\)
\(y-4=-1;y=-1+4=3\)
\(y-4=1;y=1+4=5\)
Bài 4:
Gọi thời gian cần tìm là x
Theo đề, ta có: -6+4x+0+2x=-3+3x
=>6x-6=3x-3
=>3x=3
=>x=1
4a.
$A=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+....+\frac{1}{2^{100}}$
$2A=1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{99}}$
$\Rightarrow 2A-A=(1+\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{99}})-(\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+....+\frac{1}{2^{100}})$
$\Rightarrow A=1-\frac{1}{2^{100}}$
4b.
$B=1+\frac{1}{3}+\frac{1}{3^2}+....+\frac{1}{3^{100}}$
$3B=3+1+\frac{1}{3}+...+\frac{1}{3^{99}}$
$\Rightarrow 3B-B=(3+1+\frac{1}{3}+...+\frac{1}{3^{99}})-(1+\frac{1}{3}+\frac{1}{3^2}+....+\frac{1}{3^{100}})$
$\Rightarrow 2B=3-\frac{1}{3^{100}}$
$\Rightarrow B=\frac{3}{2}-\frac{1}{2.3^{100}}$
Đặt A = 2 + 2² + 2³ + 2⁴ + ... + 2²⁰²²
= (2 + 2² + 2³) + (2⁴ + 2⁵ + 2⁶) + ... + (2²⁰²⁰ + 2²⁰²¹ + 2²⁰²²)
= 2.(1 + 2 + 2²) + 2⁴.(1 + 2 + 2²) + ... + 2²⁰²⁰.(1 + 2 + 2²)
= 2.7 + 2⁴.7 + ... + 2²⁰²⁰.7
= 7.(2 + 2⁴ + ... + 2²⁰²⁰) ⋮ 7
Vậy A ⋮ 7
Bài 1:
a: \(\Leftrightarrow-10< 3x< -7\)
=>3x=-9
hay x=-3
b: \(\Leftrightarrow-9< 2x< -6\)
=>2x=-8
hay x=-4
1)\(\dfrac{2}{9}+\dfrac{-3}{4}+\dfrac{5}{30}\)
\(=\dfrac{2.20}{9.20}+\dfrac{-3.45}{4.45}+\dfrac{5.6}{30.6}\)
\(=\dfrac{40}{180}+\dfrac{-135}{180}+\dfrac{30}{180}\)
\(=\dfrac{40+\left(-135\right)+30}{180}\)
\(=\dfrac{-65}{180}\)
\(=\dfrac{-13}{36}\)
2)\(\dfrac{-7}{12}-\dfrac{11}{18}\)
\(=\dfrac{-7.3}{12.3}-\dfrac{11.2}{18.2}\)
\(=\dfrac{-21}{36}-\dfrac{22}{36}\)
\(=\dfrac{-21-22}{36}\)
\(=\dfrac{-43}{36}\)
3)\(\dfrac{7}{8}-\dfrac{-5}{16}\)
\(=\dfrac{7.2}{8.2}-\dfrac{-5}{16}\)
\(=\dfrac{14}{16}-\dfrac{-5}{16}\)
\(=\dfrac{14-\left(-5\right)}{16}\)
\(=\dfrac{19}{16}\)
4)\(\dfrac{3}{8}-\dfrac{-9}{10}-\dfrac{5}{16}\)
\(=\dfrac{3.10}{8.10}-\dfrac{-9.8}{10.8}-\dfrac{5.5}{16.5}\)
\(=\dfrac{30}{80}-\dfrac{-72}{80}-\dfrac{25}{80}\)
\(=\dfrac{30-\left(-72\right)-25}{80}\)
\(=\dfrac{77}{80}\)