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a: UM=AU=2,5/2=1,25cm
VA=VE=AE/2=1,25cm
b: UV=1,25+1,25=2,5cm
`2x-15 = 17``
`=> 2x = 17 + 15`
`=> 2x = 32`
`=> X = 32 : 2`
`=> x = 16`
`156 - (x + 61) = 82`
`=> x + 61 = 156 - 82`
`=> x + 61 = 74`
`=> x = 13`
`2x - 138 = 2^3 . 3^2`
`=>2x - 138 = 72`
`=> 2x = 210`
`=> x = 105`
bài 2:
`23-3x = 8`
`=> 3x = 23 - 8`
`=> 3x = 15`
`=> x = 5`
`(x-35) - 120 = 0`
`=>(x-35) = 120`
`=> x = 120 +35`
`=> x = 155`
`3^x + 2 = 29`
`=> 3^x = 27`
`=> 3^x = 3^3`
`=> x = 3`
a. |7x + 1| = 20
+) 7x + 1 = 20
=> 7x = 19
=> x = 19/7
+) 7x + 1 = -20
=> 7x = -21
=> x = -21 : 7
=> x = -3
Vậy...
b. +) x - 7 < 0; x + 3 > 0
=> x < 7; x > -3
=>-3 < x < 7
=> x \(\in\){-2; -1; 0; 1; 2; 3; 4; 5; 6}
+) x - 7 > 0; x + 3 < 0
=> x > 7; x < -3
=> 7 < x < -3 (vô lí)
Vậy x...
a ) \(\left|x-1\right|\ge0\)
\(\Rightarrow x-1\in\left\{0;-1;1;-2;2\right\}\)
\(\Rightarrow x=1;0;2;-2;3\)
b )cug giong tu lm
bn lam not cau b cho mik voi. mik chuan bi di hok roi,nhanh nha
\(1,\dfrac{8}{13}+\dfrac{5}{13}=\dfrac{8+5}{13}=\dfrac{13}{13}=1\)
\(2,\dfrac{-8}{7}+\dfrac{-6}{7}=\dfrac{\left(-8\right)+\left(-6\right)}{7}=\dfrac{-14}{7}=-2\)
\(5,\dfrac{7}{-9}-\dfrac{13}{9}=\dfrac{\left(-7\right)-13}{9}=\dfrac{-20}{9}\)
\(6,\dfrac{5}{7}-\dfrac{-3}{21}=\dfrac{15}{21}-\dfrac{-3}{21}=\dfrac{15-\left(-3\right)}{21}=\dfrac{18}{21}=\dfrac{6}{7}\)
\(9,\dfrac{7}{-10}-\dfrac{2}{-15}=\dfrac{-105}{150}-\dfrac{-20}{150}=\dfrac{-\left(105-20\right)}{150}=\dfrac{-85}{150}\)
\(10,\dfrac{6}{13}-\dfrac{-15}{39}=\dfrac{18}{39}-\dfrac{-15}{39}=\dfrac{18-\left(-15\right)}{39}=\dfrac{33}{39}=\dfrac{11}{13}\)
1) \(\dfrac{8}{13}+\dfrac{5}{13}=\dfrac{13}{13}=1\)
2 ) \(\dfrac{-8}{7}+\dfrac{-6}{7}=\dfrac{-14}{7}=-2\)
3 ) \(\dfrac{-4}{3}-\dfrac{-7}{3}\)\(=\dfrac{3}{3}=1\)
4 ) \(\dfrac{-8}{5}+\dfrac{6}{-5}=\dfrac{-8}{5}+\dfrac{-6}{5}\)\(=\dfrac{-14}{5}\)
5 ) \(\dfrac{7}{-9}-\dfrac{13}{9}=\dfrac{-7}{9}-\dfrac{13}{9}=\dfrac{-20}{9}\)
6 ) \(\dfrac{5}{7}-\dfrac{-3}{21}=\dfrac{5\times3}{7\times3}=\dfrac{15}{21}-\dfrac{-3}{21}=\dfrac{18}{21}\)\(=\dfrac{6}{7}\)
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