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a) \(3x-18.28:14=308\)
\(=>3x-36=308\)
\(=>3x=344\)\(\)
\(=>x=\frac{344}{3}\)
\(\)b)\(38+\left|x\right|=\left(-12\right)+65\)
\(=>38+\left|x\right|=53=>\left|x\right|=15=>\orbr{\begin{cases}x=15\\x=-15\end{cases}}\)
c)\(15+3.\left(x-1\right):5=30\)
\(=>15+3.\left(x-1\right)=150\)
\(=>3.\left(x-1\right)=135\)
\(x-1=45=>x=46\)
d) \(5.\left(7-3x\right)+7.\left(2+2x\right)=1\)
\(=>35-15x+14+14x=1\)
\(=>49-x=1=>x=48\)
e)\(3.\left(x-7\right)=21\)
\(=>x-7=7=>x=14\)
g)\(\left[\left(6x-72\right):2-84\right]:28=5628\)
\(\left(6x-72\right):2-84=157584\)
\(\left(6x-72\right):2=157668\)
\(6x-72=315336\)
\(6x=315408=>x=52568\)
h)\(123-5\left(x+4\right)=28\)
\(5.\left(x+4\right)=95\)
\(x+4=19=>x=15\)
p)\(14.\left(x-3\right)-138=73\)
\(14.\left(x-3\right)=211\)
\(x-3=\frac{211}{14}=>x=\frac{253}{14}\)
\(t\)
\(\left|x\right|-5=2\)
\(\left|x\right|=7=>\orbr{\begin{cases}x=7\\x=-7\end{cases}}\)
v)\(4x-72=\left|100-8.25\right|\)
\(4x-72=\left|-100\right|\)
\(4x-72=100=>4x=172=>x=43\)
cậu có thể tham khảo bài làm trên đây ạ, chúc cậu học tốt ^^
1.
a, \(x-14=3x+18\)
\(\Rightarrow x-3x=18+14\)
\(\Rightarrow-2x=32\Rightarrow x=\frac{32}{-2}=-16\)
b, \(\left(x+7\right).\left(x-9\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x+7=0\\x-9=0\end{cases}\Rightarrow\orbr{\begin{cases}x=-7\\x=9\end{cases}}}\)
c, \(\left|2x-5\right|-7=22\)
\(\Rightarrow\left|2x-5\right|=22+7\)
\(\Rightarrow\left|2x-5\right|=29\)
\(\Rightarrow\orbr{\begin{cases}2x+5=29\\2x-5=29\end{cases}}\Rightarrow\orbr{\begin{cases}2x=24\\2x=34\end{cases}\Rightarrow}\orbr{\begin{cases}x=12\\x=17\end{cases}}\)
d, \(\left(\left|2x\right|-5\right)-7=22\)
\(\Rightarrow\left(\left|2x\right|-5\right)=29\)
\(\Rightarrow\left|2x\right|=29+5\Rightarrow\left|2x\right|=34\Rightarrow x=\pm17\)
e, \(\left|x+3\right|+\left|x+9\right|+\left|x+5\right|=4x\)
Vì \(\left|x+3\right|\ge0;\left|x+9\right|\ge0;\left|x+5\right|\ge0;4x\ge0\)
Nên \(\left|x+3\right|+\left|x+9\right|+\left|x+5\right|=4x\ge0\)
\(\Rightarrow\left|x+3\right|>0\Rightarrow\left|x+3\right|=x+3\)
\(\left|x+9\right|>0\Rightarrow\left|x+9\right|=x+9\)
\(\left|x+5\right|>0\Rightarrow\left|x+5\right|=x+5\)
Ta có :
\(x+3+x+9+x+5=4x\)
\(\Rightarrow3x+\left(3+9+5\right)=4x\)
\(\Rightarrow4x-3x=17\)
\(\Rightarrow x=17\)
2. a , b sai đề bn
c, \(\left(5x+1\right).\left(y-1\right)=4\)
\(\Rightarrow\left(5x+1\right).\left(y-1\right)\inƯ\left(4\right)\)
\(\text{ }Ư\left(4\right)=\left\{1;-1;2;-2;4;-4\right\}\)
Ta có bảng sau :
5x+1 | 1 | -1 | 2 | -2 | 4 | -4 |
y-1 | -4 | 4 | -2 | 2 | -1 | 1 |
x | 0 | -2/5 | 1/5 | -3/5 | 3/5 | -1 |
y | -3 | 5 | -1 | 3 | 0 | 2 |
d, \(5xy-5x+y=5\)
\(\Rightarrow\left(5xy-5x\right)+y=5\)
\(\Rightarrow5x.\left(y-1\right)+y=5\)
\(\Rightarrow\left(5x+1\right).\left(y-1\right)=4\)
\(\Rightarrow\left(5x+1\right).\left(y-1\right)\inƯ\left(4\right)\)
\(Ư\left(4\right)=\left\{1;-1;2;-2;4;-4\right\}\)
Ta có bảng sau :
5x+1 | 1 | -1 | 2 | -2 | 4 | -4 |
y-1 | -4 | 4 | -2 | 2 | -1 | 1 |
x | 0 | -2 | 1/5 | -3/5 | 3/5 | -1 |
y | -3 | 5 | -1 | 3 | 0 | 2 |
a. 8 + (x - 9) = 125 - 64
8 + (x - 9) = 61
x - 9 = 53
x = 62
b. 5 x (X + 7) - 10 = 8 x 5
5 x (X + 7) - 10 = 40
5 x (X + 7) = 50
X + 7 = 10
X = 3
a) x+30%x=-1.31
=> 100%x+30%x=-1.31
=>x.(100%+30%)=-1.31
=>x.13/10=-1.31=-1.31:13/10=-131/130
b) (x-1/2):1/3+5/7=9+5/7
=>(x-1/2).3+5/7=68/7
=>(x-1/2).3=68/7-5/7=9
=>x-1/2=9:3=3
=>x=3+1/2=3 1/2( hỗn số)
c) 1/2x-3/4=14/9.3/7
=>1/2x-3/4=2/3
=>1/2x=2/3+3/4=17/12
x=17/12:1/2=17/12.2=17/6
d) - 5/6 -x = 7/12+ -1/3
=>- 5/6 -x = 7/12+ -4/12=1/4
=> x = -5/6 -1/4=-13/12
e) x + 3/-15 = 1/3
=> x= 1/3 - -3/15 =1/3+3/15
=> x=5/15 + 3/15=8/15
f) (4,5 -2 x). (-1 4/7)=11/14
=> 4,5 -2x=11/14 : -3/7=11/14. -7/3=-11/6
=>-2x=-11/6-9/2= -11/6 -27/6 =-19/3
=>x= -19/3: -2x=19/6
Chúc bn thi HKII tốt!!!
Tìm x
a, 5x - 10 . (-7) = 15 . (-3)
5x + 70 = -45
5x = -45 - 70
5x = -115
x = -115 : 5
x = -23
Vậy x = -23.
b, 2x + 12 = -8
2x = -8 - 12
2x = -20
x = -20 : 2
x = -10
Vậy x = -10.
c, 3x - 5 = -20
3x = -20 + 5
3x = -15
x = -15 : 3
x = -5
Vậy x = -5.
d, 2x - (-12) = -8 . 23
2x + 12 = -184
2x = -184 - 12
2x = -196
x = -196 : 2
x = -98
Vậy x = -98.
e, x2 = 49
x2 = 72 = (-7)2
=> x = 7 hoặc x = -7.
Vậy x thuộc {-7 ; 7}
i, (x - 2)2 + 1 = 65
(x - 2)2 = 65 - 1
(x - 2)2 = 64
(x - 2)2 = 82 = (-8)2
=> x - 2 = 8 hoặc x - 2 = -8
=> x = 10 hoăc x = -6
Vậy x thuộc {-6 ; 10}.
g, 2 (x - 3)2 - 5 = 5 . (-3)2
2 (x - 3)2 - 5 = 5 . 9
2 (x - 3)2 - 5 = 45
2 (x - 3)2 = 45 + 5
2 (x - 3)2 = 50
(x - 3)2 = 50 : 2
(x - 3)2 = 25
(x - 3)2 = 52 = (-5)2
=> x - 3 = 5 hoặc x - 3 = -5
=> x = 8 hoặc x = -2
Vậy x thuộc {-2 ; 8}.
a) 5x - 10.(-7)=15.(-3) b) 2x+12=-8 c) 3x-5=-20 d)2x-(-12)=-8.23 e)\(^{x^2}\)=49 i)\(\left(x-2\right)^2+1\)=65
5x+70=-45 2x=-8-12 3x=-20+5 2x+12=-184 x=7 \(\left(x-2\right)^2\) =64
5x=-45-70 2x=-20 3x=-15 2x=-184-12 X-2 =8
5x=-115 x=-20:2 x=-15:3 2x=-186 x =10
x=-23 x=-10 x=-5 x=-93
g)\(2.\left(x-3\right)^2-5=5.\left(-3\right)^2\)
\(2\left(x-3\right)^2-5=30\)
\(2.\left(x-3\right)^2=35\)
\(2.\left(x^2-2x.3+3^2\right)=35\)
\(2x^2-24x+18=35\)
\(2x^2-24x=17\)
\(2x\left(x-12\right)=17\)
\(\orbr{\begin{cases}2x=17\\x-12=17\end{cases}}\orbr{\begin{cases}x=\frac{17}{2}\\x=29\end{cases}}\)
Lời giải:
$7^{5x}:49=7^{28}$
$7^{5x}:7^2=7^{28}$
$7^{5x-2}=7^{28}$
$\Rightarrow 5x-2=28$
$\Rightarrow 5x=30$
$\Rightarrow x=6$
b.
$5^{2x}.5^{14}=5^{30}$
$5^{2x+14}=5^{30}$
$\Rightarrow 2x+14=30$
$\Rightarrow 2x=16$
$\Rightarrow x=8$
a) 7^5x:49=7^28
7^5x:7^2=7^28
7^5x=7^28.7^2
7^5x=7^30
suy ra 5x=30
x= 6